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Samacheer Kalvi 10th Science Chapter 5 Long Answer Questions — Acoustics with Answers

Long answer questions (5 marks) from Samacheer Kalvi Class 10 Science Chapter 5 Acoustics with detailed answers covering sound waves, echo, SONAR, and ultrasonics.

Updated 25 May 20268 min read

Chapter 5 — Acoustics: Long Answer Questions


1. Explain the production and propagation of sound. Describe the properties of sound waves.

Production of Sound

Sound is produced by the vibration of an object. When an object vibrates:

  • It pushes the surrounding air molecules, creating regions of compression (high pressure)
  • When it moves back, it creates regions of rarefaction (low pressure)
  • These alternating compressions and rarefactions travel outward as a longitudinal wave

Examples:

  • Vocal cords vibrate → voice
  • Tuning fork prongs vibrate → sound
  • Guitar string vibrates → musical note
  • Loudspeaker cone vibrates → amplified sound

Propagation of Sound

Sound requires a medium (solid, liquid, or gas) to travel. It cannot travel through vacuum.

Speed of sound in different media:

MediumSpeed of sound (approx.)
Air (20°C)343 m/s
Water1500 m/s
Steel5100 m/s

Sound travels fastest in solids and slowest in gases.

Effect of temperature: Speed of sound in air increases by ~0.6 m/s for every 1°C rise in temperature.

Properties of Sound Waves

1. Frequency (f):
Answer
  • Number of complete vibrations per second
  • Unit: hertz (Hz)
  • Determines pitch — high frequency = high pitch (shriller sound); low frequency = low pitch (deeper sound)
  • Human audible range: 20 Hz to 20,000 Hz
2. Amplitude (A):
Answer
  • Maximum displacement of vibrating particles from equilibrium
  • Determines loudness — greater amplitude = louder sound
  • Unit of loudness: decibel (dB)
3. Wavelength (λ):
Answer
  • Distance between two consecutive compressions (or rarefactions)
  • Unit: metre (m)
4. Time period (T):
Answer
  • Time taken for one complete vibration
  • T = 1/f
5. Wave speed (v):
Answer
  • v = fλ = λ/T
6. Timbre (quality):
Answer
  • The characteristic quality of sound that distinguishes two sounds of same pitch and loudness
  • Determined by the mixture of harmonics (overtones) present

2. Explain reflection of sound. Define echo and state the conditions required for echo formation.

Reflection of Sound

Sound waves, like light waves, obey the laws of reflection: 1. The angle of incidence = angle of reflection (measured from the normal to the reflecting surface) 2. The incident sound, reflected sound, and normal all lie in the same plane

Hard, smooth surfaces (walls, cliffs, metal sheets) are good reflectors of sound. Soft, porous surfaces (cloth, foam) absorb sound.


Echo

An echo is the repetition of a sound caused by the reflection of sound waves from a distant surface.

Condition for hearing a distinct echo: The reflected sound must reach the ear at least 0.1 seconds after the original sound (because the human ear can distinguish two sounds separated by at least 0.1 s).

Minimum distance for echo: If speed of sound = v m/s, in 0.1 s sound travels = v × 0.1 m This distance is covered twice (to the wall and back): minimum distance = v × 0.1/2 = v/20

At 20°C (v = 340 m/s): Minimum distance = 340/20 = 17 m (approximately)

So the reflecting surface must be at least 17 m away from the source for a distinct echo to be heard.

Formula for distance calculation:

d = v × t/2

Where d = distance to reflecting surface, v = speed of sound, t = time between producing sound and hearing echo


Reverberation

Reverberation is the persistence of sound in an enclosed space due to multiple reflections from walls, ceiling, and floor — the reflected sounds arrive within 0.1 s of each other and are perceived as prolonged sound.

Optimum reverberation time: 1–2 seconds for music; shorter for speech.

Control: Carpets, cushioned seats, curtains, acoustic tiles, false ceilings absorb excess sound.


3. What is SONAR? Explain its working and applications.
Answer

SONAR — Sound Navigation And Ranging — is a technology that uses sound waves (especially ultrasound) to detect and locate objects underwater.

Principle

SONAR works on the principle of reflection of sound (echo): 1. A transducer (ultrasound transmitter-receiver) attached to the ship sends a pulse of ultrasound downward (or in any direction) 2. The ultrasound pulse travels through water, hits an object or the sea floor, and reflects back 3. The returning echo is detected by the receiver 4. The time interval between sending and receiving the echo is measured 5. Distance to the object is calculated:

d = v × t/2

Where v = speed of sound in water (~1500 m/s), t = time for echo to return

Worked Example

An ultrasound pulse is sent from a ship. The echo from the seabed returns in 4 seconds.

  • d = 1500 × 4/2 = 3000 m (depth of ocean)

Applications of SONAR

ApplicationDetails
Depth soundingMeasuring depth of seas and oceans (echo sounding)
Detecting submarinesNaval warfare — locate enemy submarines
Detecting fish shoalsFishing industry — locate large groups of fish
Seabed mappingCreating detailed ocean floor maps
Detecting icebergsPreventing ship collisions
NavigationGuiding ships in shallow or hazardous waters

4. Explain the applications of ultrasound. What is echolocation?

Ultrasound

Ultrasound has frequency above 20,000 Hz (beyond human hearing range).

Properties that make it useful:

  • Short wavelength → can detect very small objects
  • High energy → can penetrate matter
  • Can be directed as a narrow beam
  • Reflected clearly from boundaries between different materials

Applications of Ultrasound

1. Medical applications:
Answer
  • Ultrasonography (USG/sonography): Creates images of internal organs using reflected ultrasound; monitors foetal development during pregnancy; detects tumours, kidney stones, liver problems
  • HIFU (High Intensity Focused Ultrasound): Destroys tumours without surgery
  • Lithotripsy: Breaking kidney stones using high-intensity ultrasound so they can be passed out of the body
2. Industrial applications:
Answer
  • Non-Destructive Testing (NDT): Detecting internal cracks and flaws in metals and structures without damaging them (aircraft wings, pipelines, railway tracks)
  • Ultrasonic cleaning: Objects (spectacles, electronic components, jewellery) immersed in cleaning fluid; ultrasound creates rapid pressure changes that dislodge dirt (cavitation)
  • Welding of plastics using ultrasonic vibrations
3. Navigation and detection:
Answer
  • SONAR (see above)
  • Ranging: Parking sensors in cars use ultrasound to detect distance to obstacles

Echolocation

Echolocation is the biological use of sound echoes by animals to navigate, hunt, and detect objects.

Bats:

  • Emit very high-frequency ultrasound pulses (20 kHz–200 kHz) through their mouth or nose
  • Detect the echoes with their large ears
  • Can determine direction, distance, size, and speed of insects and obstacles
  • Fly in complete darkness without collision
  • Their brains process echo information in real-time

Other animals using echolocation:

  • Dolphins and whales — underwater echolocation
  • Cave-dwelling birds (oilbirds, swiftlets) — navigate in dark caves
  • Some blind humans — have learned to echolocation by clicking their tongue

Inspiration for technology: SONAR and ultrasound detection systems are inspired by bat echolocation.


5. Explain the audible range, infrasound, and ultrasound. Mention which animals can hear in each range.

Classification of Sound by Frequency

1. Infrasound (below 20 Hz):
Answer
  • Frequency: less than 20 Hz
  • Below human hearing range
  • Can travel very long distances — used for long-range communication
AnimalUse
ElephantsCommunicate over distances of several km using infrasound rumbles
WhalesLong-distance communication in oceans
RhinocerosesCommunication
Alligators/crocodilesCommunication

Also produced by: earthquakes (seismic waves), volcanic eruptions, ocean waves, some machinery. Can be felt as vibrations even if not heard.

2. Audible range (20 Hz – 20,000 Hz):
Answer
  • The range of frequencies detectable by the human ear
  • Hearing ability decreases with age — elderly people often cannot hear above 12,000–15,000 Hz
AnimalAudible range (approx.)
Humans20 Hz – 20,000 Hz
Dogs40 Hz – 65,000 Hz
Cats45 Hz – 79,000 Hz
Bats1,000 Hz – 120,000 Hz
3. Ultrasound (above 20,000 Hz):
Answer
  • Frequency: greater than 20,000 Hz (20 kHz)
  • Above human hearing range
AnimalUse of ultrasound
BatsEcholocation for navigation and hunting insects
DolphinsEcholocation underwater
Dogs and catsHear ultrasound (used in dog whistles)
RodentsCommunicate using ultrasound
Whales (some)High frequency clicks for echolocation

Technological applications of ultrasound: Medical imaging (USG), SONAR, NDT (industrial flaw detection), ultrasonic cleaning, lithotripsy. (See Q4 above for details.)


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Frequently Asked Questions

Sound waves are longitudinal mechanical waves. Key properties: (1) Frequency (f) — number of vibrations per second; unit: Hz. Determines pitch. (2) Amplitude (A) — maximum displacement of particles from rest position. Determines loudness. (3) Wavelength (λ) — distance between two consecutive compressions or rarefactions. (4) Time period (T) — time for one complete vibration; T = 1/f. (5) Wave speed (v) — v = fλ. Speed of sound in air at 20°C ≈ 343 m/s. Increases with temperature and is highest in solids.