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Samacheer Kalvi 10th Science Chapter 1 Long Answer Questions — Laws of Motion

All long answer questions (5 marks) from Samacheer Kalvi Class 10 Science Chapter 1 Laws of Motion with complete detailed answers and diagrams described.

Updated 24 May 20267 min read

Long Answer Questions — Chapter 1: Laws of Motion


Q1. State and explain Newton's three laws of motion with examples.
Answer

Newton's First Law of Motion (Law of Inertia)

Statement: Every object continues to be in its state of rest or uniform motion in a straight line unless acted upon by a net external force.

Explanation
  • A body at rest will remain at rest unless a force is applied.
  • A body moving with constant velocity in a straight line will continue to do so unless a force changes its state.
  • This is also called the Law of Inertia.

Examples: 1. A book on a table stays at rest until someone pushes it. 2. A ball rolling on a frictionless surface would roll forever — friction is the external force that eventually stops it. 3. Passengers lurch backward when a bus starts suddenly.


Newton's Second Law of Motion (Law of Force and Acceleration)

Statement: The rate of change of momentum of a body is directly proportional to the net force applied and the change occurs in the direction of the force.

Mathematical Expression:

Let a body of mass m have initial velocity u and final velocity v after time t.

Initial momentum = mu Final momentum = mv Change in momentum = mv − mu Rate of change = (mv − mu) / t = m(v − u) / t = ma

ThereforeF = ma

Examples: 1. A cricket ball (small mass) accelerates more than a football (larger mass) for the same kick force. 2. A heavier truck requires a stronger engine (more force) to achieve the same acceleration as a car.


Newton's Third Law of Motion (Law of Action and Reaction)

Statement: For every action, there is an equal and opposite reaction. The action and reaction forces always act on two different bodies.

Key points:

  • Action and reaction are simultaneous (occur at the same time)
  • They are equal in magnitude and opposite in direction
  • They act on different bodies — so they do not cancel each other

Examples: 1. Rocket propulsion: Hot gases are expelled backward (action) → rocket moves forward (reaction) 2. Walking: Foot pushes ground backward (action) → ground pushes foot forward (reaction) 3. Swimming: Swimmer pushes water backward (action) → water pushes swimmer forward (reaction) 4. Recoil of gun: Gun exerts force on bullet forward (action) → bullet exerts force on gun backward (reaction)


Q2. Derive the law of conservation of momentum from Newton's laws.
Answer

Statement: When no net external force acts on a system, the total momentum of the system remains constant.

Derivation:

Consider two balls A and B:

  • Mass of A = mₐ, Mass of B = m_b
  • Initial velocity of A = uₐ, Initial velocity of B = u_b
  • They collide and after collision:
  • Final velocity of A = vₐ, Final velocity of B = v_b

During collision:

Let F_AB = force exerted by A on B (action) Let F_BA = force exerted by B on A (reaction)

By Newton's Third Law: F_AB = −F_BA ... (1)

By Newton's Second Law:

  • Change in momentum of B = F_AB × t = m_b(v_b − u_b)
  • Change in momentum of A = F_BA × t = mₐ(vₐ − uₐ)

From equation (1): m_b(v_b − u_b) = −mₐ(vₐ − uₐ)

Expanding: m_b·v_b − m_b·u_b = −mₐ·vₐ + mₐ·uₐ

Rearranging: mₐ·uₐ + m_b·u_b = mₐ·vₐ + m_b·v_b

This means: Total initial momentum = Total final momentum

Therefore, momentum is conserved. ✓

Applications: 1. Recoil of a gun 2. Rocket and jet propulsion 3. Collisions between billiard balls


Q3. Explain the recoil of a gun using the law of conservation of momentum.
Answer

Situation: Before firing, both gun and bullet are at rest. The total momentum of the system = 0.

During firing:

  • Explosion exerts force on the bullet → bullet moves forward with velocity v (say)
  • By Newton's 3rd law, bullet exerts equal and opposite force on gun → gun moves backward

Applying conservation of momentum:

Total initial momentum = 0 (both at rest) Total final momentum = M × V + m × v

Where:

  • M = mass of gun
  • V = velocity of gun (recoil velocity, backward)
  • m = mass of bullet
  • v = velocity of bullet (forward)

Since total momentum is conserved: M × V + m × v = 0

V = −(m × v) / M

The negative sign indicates the gun moves in the opposite direction to the bullet.

Conclusion: The larger the mass of the gun (M), the smaller the recoil velocity (V). This is why heavy guns have less recoil compared to light guns.


Q4. What is torque? Explain the principle of moments with a diagram.
Answer

Torque (Moment of Force)

Definition: Torque is the turning effect produced by a force on a body about an axis or pivot.

Formulaτ = F × d

Where:

  • τ = Torque (N·m)
  • F = Force applied (N)
  • d = Perpendicular distance from the pivot to the line of action of force (m)

Unit: Newton-metre (N·m)


Principle of Moments

Statement: When a body is in rotational equilibrium, the sum of clockwise moments about any point equals the sum of anticlockwise moments about the same point.

Mathematically: Sum of clockwise moments = Sum of anticlockwise moments

F₁ × d₁ = F₂ × d₂


Diagram Description (Lever / Seesaw):

Pivot (fulcrum) | F₁ | F₂ ↓ | ↓ [===d₁===][==pivot==][===d₂===]
  • F₁ acts at distance d₁ on the left → creates anticlockwise moment = F₁ × d₁
  • F₂ acts at distance d₂ on the right → creates clockwise moment = F₂ × d₂
  • For equilibrium: F₁ × d₁ = F₂ × d₂

Types of Levers

TypeFulcrum positionExample
Class 1Between effort and loadSeesaw, scissors
Class 2Load between fulcrum and effortWheelbarrow, nutcracker
Class 3Effort between fulcrum and loadTweezers, forearm

Q5. Explain centripetal force and centrifugal force. Distinguish between them.
Answer

Centripetal Force

Definition: The force that acts on a body moving in a circular path, always directed toward the centre of the circle, is called centripetal force.

FormulaF_c = mv²/r

Where:

  • m = mass (kg)
  • v = speed (m/s)
  • r = radius (m)

Direction: Always toward the centre (inward)

Nature: Centripetal force is a real force — it is provided by some actual force in each case:

  • Earth-Sun system: gravity provides centripetal force
  • Stone on string: tension in string
  • Car on road: friction with road surface
  • Satellite in orbit: gravity provides centripetal force

Centrifugal Force

Definition: Centrifugal force is an apparent (pseudo) force that appears to act on a body moving in a circular path, directed away from the centre.

Nature: It is NOT a real force. It is a fictitious force that appears only in a rotating (non-inertial) reference frame.


Comparison Table

PropertyCentripetal ForceCentrifugal Force
DirectionToward centreAway from centre
NatureReal forcePseudo (fictitious) force
CauseProvided by actual forces (gravity, tension, etc.)Apparent, due to rotation
Exists inAll reference framesOnly in rotating frame
ExampleTension keeps stone in circular pathMud flies off a spinning wheel

Practical Applications of Centripetal/Centrifugal Effects

1. Road banking (curved roads): Roads are banked at an angle so the normal force provides centripetal force, allowing vehicles to turn safely. 2. Washing machine spin dry: Centrifugal effect throws water outward through holes in the drum. 3. Cream separator: Denser particles (milk) move outward, lighter cream stays inward when rotated. 4. Satellites: Gravity = centripetal force keeps satellites in orbit.


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Frequently Asked Questions

1st Law (Inertia): A body at rest stays at rest and a body in motion stays in motion unless acted on by a net external force. 2nd Law: F = ma — net force equals mass times acceleration. 3rd Law: Every action has an equal and opposite reaction acting on different bodies.