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Samacheer Kalvi 12th Biology Chapter 14 Exercise Solutions

Tamil Nadu Class 12 Biology Chapter 14 Principles of Inheritance and Variation exercise solutions — Mendel's laws, blood groups, genetic disorders, and exam tips.

Updated 25 May 202622 min read

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Step-by-step answers for all textbook questions in this chapter

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Chapter 14 — Principles of Inheritance and Variation Exercise Solutions

This Zoology chapter on inheritance overlaps with the Botany chapter (Chapter 2). Master blood group genetics and genetic disorders.

How to Use This Page

  • Start with the Key Concepts table — it gives a rapid overview of every major term you need to remember.
  • Attempt each section in order — MCQs first, then Fill in the Blanks, True or False, Match the Following, short answers, and detailed answers.
  • Compare your answers with the provided solutions. For 5-mark questions, check if your answer includes all the sub-points mentioned.
  • Read Common Mistakes to Avoid at least twice before the exam — these are the most frequent errors.
  • Use the Exam Checklist as a final revision sheet to ensure you have covered every topic.

Key Concepts Quick Recap

TermDefinition
Multiple allelesThree or more alleles for a single gene locus in a population (e.g. I^A, I^B, i for ABO blood group)
CodominanceBoth alleles are expressed equally in the heterozygote (e.g. I^A I^B = Blood group AB)
Incomplete dominanceHeterozygote shows an intermediate phenotype between two homozygotes (e.g. pink flowers in snapdragon)
PleiotropySingle gene influencing multiple phenotypic traits (e.g. sickle cell gene affects RBC shape and malaria resistance)
Sex-linked inheritanceGenes located on the X or Y chromosome; X-linked recessive disorders affect males more frequently
HaemophiliaX-linked recessive disorder — deficiency of clotting factors (VIII or IX) leading to prolonged bleeding
Sickle cell anaemiaAutosomal recessive disorder — point mutation in beta-globin gene (glutamic acid → valine at position 6)
Erythroblastosis foetalisHaemolytic disease of the newborn — Rh incompatibility between Rh− mother and Rh+ foetus
Phenylketonuria (PKU)Autosomal recessive disorder — lack of phenylalanine hydroxylase leads to intellectual disability
Huntington's diseaseAutosomal dominant disorder — CAG repeat expansion in HTT gene causes progressive neurodegeneration
Duchenne muscular dystrophyX-linked recessive disorder — mutation in dystrophin gene causes progressive muscle weakness
Universal donorBlood group O (no A or B antigens on RBCs)
Universal recipientBlood group AB (no anti-A or anti-B antibodies in plasma)

Blood Group Inheritance — Summary

Blood GroupGenotypeAntigen on RBCAntibody in Plasma
AI^A I^A or I^A iAAnti-B
BI^B I^B or I^B iBAnti-A
ABI^A I^BA and BNone
OiiNoneAnti-A and Anti-B

Universal donor: O (no antigens) Universal recipient: AB (no antibodies)

Rh factor: Rh+ has Rh antigen; Rh− does not. Erythroblastosis foetalis occurs when Rh− mother carries Rh+ foetus.

Genetic Disorders — Autosomal

DisorderModeCauseFeature
Sickle cell anaemiaAutosomal recessiveAbnormal haemoglobin (HbS)Sickle-shaped RBC, anaemia
Phenylketonuria (PKU)Autosomal recessiveLack of phenylalanine hydroxylaseMental retardation, fair skin
Cystic fibrosisAutosomal recessiveCFTR protein mutationThick mucus in lungs
Huntington's diseaseAutosomal dominantCAG repeat in HTT geneProgressive neurodegeneration
AchondroplasiaAutosomal dominantFGFR3 mutationShort stature, dwarfism

Sex-Linked Disorders

DisorderGene LocationInheritanceAffected
Haemophilia AX-linked recessiveFactor VIII geneMales > Females
Haemophilia BX-linked recessiveFactor IX geneMales > Females
Colour blindnessX-linked recessiveOpsin genesMales > Females
Duchenne muscular dystrophyX-linked recessiveDystrophin geneMales

Solved Cross — Haemophilia

Carrier female × Normal male: X^H X^h × X^H Y

Offspring:

  • X^H X^H — Normal female (25%)
  • X^H X^h — Carrier female (25%)
  • X^H Y — Normal male (25%)
  • X^h Y — Haemophiliac male (25%)

I. Choose the Best Answer (MCQs)

1. ABO blood grouping is an example of: (a) Incomplete dominance (b) Epistasis (c) Multiple alleles and codominance (d) Pleiotropy

2. The genotype of blood group AB is: (a) I^A I^A (b) I^B I^B (c) I^A I^B (d) ii

3. Sickle cell anaemia is caused by substitution of: (a) Valine by glutamic acid (b) Glutamic acid by valine (c) Lysine by valine (d) Valine by lysine

4. Which of the following is an X-linked recessive disorder? (a) Huntington's disease (b) Cystic fibrosis (c) Achondroplasia (d) Haemophilia

5. Erythroblastosis foetalis occurs when: (a) Rh+ mother carries Rh− foetus (b) Rh− mother carries Rh+ foetus (c) Mother has blood group AB (d) Father has blood group O

6. In incomplete dominance (snapdragon), crossing red (RR) with white (rr) gives: (a) All red (b) All white (c) All pink (d) 1 red : 2 pink : 1 white

7. A single gene that produces multiple phenotypic effects is called: (a) Epistasis (b) Codominance (c) Pleiotropy (d) Polygenic inheritance

8. The F2 phenotypic ratio in incomplete dominance is: (a) 3:1 (b) 9:3:3:1 (c) 1:2:1 (d) 2:1

9. Which blood group is the universal donor? (a) A (b) B (c) AB (d) O

10. Cystic fibrosis is caused by a mutation in the: (a) Beta-globin gene (b) Phenylalanine hydroxylase gene (c) CFTR gene (d) Dystrophin gene

11. If a carrier female for haemophilia marries a normal male, the probability of their son being haemophiliac is: (a) 0% (b) 25% (c) 50% (d) 100%

12. A haemophiliac male (X^h Y) marries a carrier female (X^H X^h). What percentage of their daughters will be haemophiliac? (a) 0% (b) 50% (c) 25% (d) 100%

13. The Rh factor is determined by which gene? (a) I gene (b) HbS gene (c) D gene (d) CFTR gene

14. Which of the following is an autosomal dominant disorder? (a) Sickle cell anaemia (b) PKU (c) Huntington's disease (d) Cystic fibrosis

15. In ABO blood groups, if both parents are blood group A (I^A i), what is the probability of a child with blood group O? (a) 0% (b) 25% (c) 50% (d) 75%

II. Fill in the Blanks

1. ABO blood groups are controlled by the gene I with three alleles: I^A, I^B, and i. 2. In codominance, both alleles are expressed equally in the heterozygous condition. 3. The genotype of blood group O is ii. 4. Erythroblastosis foetalis occurs due to Rh incompatibility between an Rh− mother and an Rh+ foetus. 5. Haemophilia is an X-linked recessive disorder. 6. Sickle cell anaemia is caused by a point mutation in the beta-globin gene. 7. In sickle cell anaemia, glutamic acid is replaced by valine at the 6th position of the beta-globin chain. 8. The universal recipient blood group is AB. 9. In incomplete dominance, the F2 phenotypic ratio is 1:2:1, which is the same as the genotypic ratio. 10. Huntington's disease is inherited as an autosomal dominant trait. 11. A female can be haemophiliac only if her genotype is X^h X^h, which requires a haemophiliac father and a carrier mother. 12. The CFTR gene mutation causes cystic fibrosis, which results in thick mucus production in the lungs. 13. In phenylketonuria, the enzyme phenylalanine hydroxylase is absent, leading to accumulation of phenylalanine. 14. Duchenne muscular dystrophy is caused by a mutation in the dystrophin gene on the X chromosome.

III. True or False (with corrections for false statements)

1. True. In codominance, both alleles in a heterozygote are fully expressed (e.g. I^A I^B = blood group AB).

2. False. — Sickle cell anaemia is an autosomal recessive disorder, not autosomal dominant. Two copies of the HbS allele (HbS HbS) are needed for the disease.

3. True. Haemophilia is an X-linked recessive disorder; males are more commonly affected because they have only one X chromosome.

4. False. — In incomplete dominance, the F2 phenotypic ratio is 1:2:1 (not 3:1), because the heterozygote shows an intermediate phenotype.

5. True. Erythroblastosis foetalis can occur when an Rh− mother carries an Rh+ foetus (second or subsequent pregnancies).

6. False. — Huntington's disease is an autosomal dominant disorder, not recessive. A single copy of the defective gene (Hh) is sufficient to cause the disease.

7. True. Pleiotropy is when a single gene affects multiple phenotypic traits (e.g. sickle cell gene affects RBC shape and provides malaria resistance in heterozygotes).

8. False. — Blood group O individuals have no antigens on their RBCs (not both A and B antigens). Blood group AB has both antigens.

9. True. A colour-blind male (X^c Y) cannot pass the trait to his sons, but all his daughters will be carriers (X^C X^c).

10. False. — Erythroblastosis foetalis typically occurs in the second or subsequent Rh+ pregnancies, not the first, because the mother must first be sensitised to produce anti-Rh antibodies.

IV. Match the Following

Column AColumn B
1. Sickle cell anaemia(e) Point mutation in beta-globin gene
2. Haemophilia(g) X-linked recessive, Factor VIII/IX deficiency
3. I^A I^B(a) Codominance — Blood group AB
4. PKU(c) Lack of phenylalanine hydroxylase
5. Huntington's disease(f) Autosomal dominant — CAG repeat
6. Erythroblastosis foetalis(b) Rh incompatibility
7. Incomplete dominance(d) 1:2:1 ratio in F2
8. Cystic fibrosis(h) CFTR gene mutation — thick mucus
9. Duchenne muscular dystrophy(i) X-linked recessive — dystrophin gene
10. Universal donor(j) Blood group O — no antigens on RBCs

V. Answer Briefly (2-mark)

1. Differentiate between codominance and incomplete dominance.
Answer

Codominance occurs when both alleles in a heterozygote are fully and equally expressed, producing both phenotypes simultaneously (e.g. I^A I^B = blood group AB, where both A and B antigens are present on RBCs). Incomplete dominance occurs when the heterozygote shows an intermediate phenotype between the two homozygous parents (e.g. red × white snapdragon = pink). In codominance, both traits appear; in incomplete dominance, a blended trait appears.

2. What is erythroblastosis foetalis? How can it be prevented?
Answer

Erythroblastosis foetalis is a haemolytic disease of the newborn caused by Rh incompatibility. When an Rh− mother carries an Rh+ foetus (inherited from the father), her immune system produces anti-Rh antibodies. In subsequent Rh+ pregnancies, these antibodies cross the placenta and destroy the foetal RBCs, causing severe anaemia and jaundice. It can be prevented by administering anti-Rh immunoglobulin (RhoGAM) to the Rh− mother within 72 hours of delivery of an Rh+ baby.

3. Explain the inheritance of ABO blood groups with a cross.
Answer

ABO blood groups are controlled by the I gene with three alleles: I^A, I^B (codominant), and i (recessive). Cross: I^A i (blood group A) × I^B i (blood group B). Gametes: I^A, i from parent 1; I^B, i from parent 2. Offspring genotypes: I^A I^B (AB), I^A i (A), I^B i (B), ii (O). Phenotypic ratio: 1 AB : 1 A : 1 B : 1 O. This demonstrates both multiple allelism and codominance.

4. What is pleiotropy? Give an example.
Answer

Pleiotropy is the phenomenon where a single gene influences multiple phenotypic traits. A classic example is sickle cell anaemia: the HbS gene affects RBC shape (sickling under low oxygen), causes anaemia, and in heterozygotes (HbA HbS) provides resistance to malaria. Another example is phenylketonuria (PKU), where the defective gene affects both brain development and skin pigmentation. Cystic fibrosis is also pleiotropic — the CFTR gene mutation affects the lungs, pancreas, liver, and sweat glands simultaneously.

5. Why are X-linked recessive disorders more common in males than in females?
Answer

X-linked recessive disorders are more common in males because males have only one X chromosome. If a male inherits the recessive allele on his X chromosome (X^h Y), he will express the disorder since there is no second X chromosome with a normal allele to mask it. Females have two X chromosomes, so they need two copies of the recessive allele (X^h X^h) to be affected. A female with one copy (X^H X^h) is a carrier and is usually unaffected.

6. Write the genotypes for all four blood groups.
Answer

Blood group A: I^A I^A (homozygous) or I^A i (heterozygous). Blood group B: I^B I^B (homozygous) or I^B i (heterozygous). Blood group AB: I^A I^B (heterozygous — codominant). Blood group O: ii (homozygous recessive).

7. What is the difference between a carrier and an affected individual in X-linked disorders?
Answer

A carrier female has one normal allele and one defective allele on her X chromosomes (X^H X^h). She does not express the disorder because the normal allele produces enough of the functional protein. An affected individual expresses the disorder — for males, this means having the defective allele on their single X chromosome (X^h Y); for females, it means having defective alleles on both X chromosomes (X^h X^h), which is very rare. Carriers can pass the defective allele to their children.

8. What is the significance of the point mutation at position 6 in the beta-globin gene?
Answer

The point mutation at position 6 of the beta-globin gene substitutes glutamic acid with valine. This single amino acid change alters the structure of haemoglobin, producing HbS instead of HbA. Under low oxygen conditions, HbS molecules polymerise into long fibres, causing red blood cells to become sickle-shaped. These sickle cells block capillaries, reduce blood flow, and cause pain crises, organ damage, and anaemia. In heterozygotes (HbA HbS), this mutation also provides some protection against malaria — a classic example of pleiotropy.

VI. Answer in Detail (5-mark)

1. Explain the inheritance of ABO blood groups. How does it demonstrate codominance and multiple allelism?
Answer

ABO blood groups are controlled by a single gene I (isoagglutinin) located on chromosome 9. This gene has three alleles: I^A, I^B, and i. I^A and I^B are codominant to each other (both expressed when present together), while i is recessive to both. This is an example of multiple allelism because more than two alleles exist in the population, though each individual carries only two.

  • Blood group A: Genotypes I^A I^A or I^A i. RBCs have antigen A; plasma has anti-B antibodies.
  • Blood group B: Genotypes I^B I^B or I^B i. RBCs have antigen B; plasma has anti-A antibodies.
  • Blood group AB: Genotype I^A I^B. RBCs have both A and B antigens; plasma has neither anti-A nor anti-B antibodies. This demonstrates codominance — both alleles are expressed simultaneously.
  • Blood group O: Genotype ii. RBCs have no antigens; plasma has both anti-A and anti-B antibodies.

Codominance is demonstrated because I^A I^B individuals express both A and B antigens equally on their RBCs — neither allele is dominant or recessive. Multiple allelism is demonstrated because three alleles (I^A, I^B, i) exist for the same gene locus in the population.

Blood group AB can donate only to AB but can receive from all groups (universal recipient). Blood group O can donate to all groups (universal donor) but can receive only from O. This has critical implications for blood transfusion compatibility.

2. Describe the genetic disorders — sickle cell anaemia, haemophilia, and colour blindness — with their inheritance patterns.
Answer

Sickle cell anaemia: Autosomal recessive disorder caused by a point mutation in the beta-globin gene on chromosome 11. The mutation substitutes glutamic acid with valine at the 6th position of the beta chain. This produces abnormal haemoglobin HbS, which polymerises under low oxygen conditions, causing RBCs to become sickle-shaped. Sickle cells block capillaries, causing pain crises, anaemia, and organ damage. Genotypes: HbA HbA (normal), HbA HbS (carrier — sickle cell trait, some protection against malaria), HbS HbS (disease — sickle cell anaemia). This is also an example of pleiotropy because the same gene affects RBC shape, causes anaemia, and provides malaria resistance in heterozygotes.

Haemophilia: X-linked recessive disorder. Haemophilia A is caused by deficiency of clotting factor VIII; Haemophilia B by deficiency of factor IX. The gene is located on the X chromosome. Males are predominantly affected (X^h Y). Females can be carriers (X^H X^h) but are rarely affected (X^h X^h). Cross: carrier female (X^H X^h) × normal male (X^H Y) → 25% normal female, 25% carrier female, 25% normal male, 25% haemophiliac male. Queen Victoria of England was a famous carrier of haemophilia, which spread through royal families across Europe — this is called the "royal disease."

Colour blindness: X-linked recessive disorder affecting the ability to distinguish colours (most commonly red-green). Caused by mutations in opsin genes on the X chromosome. Inheritance pattern is similar to haemophilia — males are more frequently affected. A colour-blind male (X^c Y) cannot pass the trait to his sons but transmits the allele to all daughters (who become carriers). Carrier females (X^C X^c) have a 50% chance of passing it to sons. The most common type is red-green colour blindness, where individuals cannot distinguish between red and green colours.

3. Explain the Rh factor and erythroblastosis foetalis. How is it prevented?
Answer

The Rh (Rhesus) factor is an antigen present on the surface of RBCs in most people (Rh+). Individuals who lack this antigen are Rh−. The Rh gene is dominant: Rh+ (DD or Dd) and Rh− (dd). Erythroblastosis foetalis (Haemolytic Disease of the Newborn) occurs when an Rh− mother carries an Rh+ foetus.

Mechanism: During the first pregnancy with an Rh+ foetus, some foetal RBCs enter the maternal circulation at delivery. The Rh− mother's immune system recognises Rh antigen as foreign and produces anti-Rh antibodies (IgG). In a subsequent Rh+ pregnancy, these antibodies cross the placenta and attack the foetal RBCs, causing haemolysis, severe anaemia, jaundice, and in extreme cases, stillbirth.

Prevention: Anti-Rh immunoglobulin (RhoGAM) is administered to the Rh− mother within 72 hours of delivery of an Rh+ baby. This destroys any Rh+ foetal cells in the mother's circulation before her immune system can mount a response, preventing antibody formation. It must be given after every Rh+ pregnancy, miscarriage, or abortion. Without RhoGAM, the risk of erythroblastosis foetalis increases with each subsequent Rh+ pregnancy.

Important note: The first Rh+ pregnancy is usually unaffected because the mother has not yet been sensitised. Erythroblastosis foetalis typically manifests from the second Rh+ pregnancy onward, when pre-existing anti-Rh antibodies are already present in the maternal blood.

4. Compare and contrast codominance, incomplete dominance, and pleiotropy with examples.
Answer
  • Codominance: Both alleles in a heterozygote are fully and equally expressed. The heterozygote shows both phenotypes simultaneously, not a blend. Example: ABO blood group — I^A I^B genotype produces both A and B antigens on RBCs (blood group AB). Neither allele is dominant or recessive; both contribute to the phenotype independently. The F2 ratio for a cross involving codominance differs from complete dominance because the heterozygote is distinguishable from both homozygotes.
  • Incomplete dominance: The heterozygote shows an intermediate phenotype between the two homozygous parents. Neither allele is completely dominant. Example: Snapdragon flower colour — RR (red) × rr (white) → Rr (pink) in F1. The F2 ratio is 1:2:1 (red:pink:white), which is the same as the genotypic ratio, because the heterozygote can be distinguished from both homozygotes. This differs from complete dominance, where the F2 phenotypic ratio is 3:1.
  • Pleiotropy: A single gene affects multiple, seemingly unrelated phenotypic traits. This occurs because the gene product (protein) is involved in multiple metabolic pathways or affects different tissues. Example: Sickle cell gene (HbS) — affects RBC shape (sickling), causes anaemia, and in heterozygotes provides resistance to malaria. PKU gene — affects brain development (intellectual disability) and skin pigmentation (fair skin).

Key differences: Codominance and incomplete dominance both involve heterozygotes, but codominance shows both traits while incomplete dominance shows a blend. Pleiotropy is about one gene affecting multiple traits, not about heterozygote expression. Codominance and incomplete dominance are about how alleles interact within a single gene, while pleiotropy is about how a single gene affects multiple phenotypic outcomes.

5. Explain sex-linked inheritance with reference to haemophilia. Why are affected females extremely rare?
Answer

Sex-linked inheritance refers to the inheritance of genes located on the X or Y chromosome. Haemophilia is an X-linked recessive disorder caused by mutations in genes on the X chromosome — factor VIII gene (Haemophilia A) or factor IX gene (Haemophilia B). Since the gene is on the X chromosome, its inheritance pattern differs between males and females.

Inheritance pattern — Cross: Carrier female (X^H X^h) × Normal male (X^H Y)

Gametes: X^H, X^h from mother; X^H, Y from father

Offspring:

  • X^H X^H — Normal female (25%)
  • X^H X^h — Carrier female (25%)
  • X^H Y — Normal male (25%)
  • X^h Y — Haemophiliac male (25%)

Key observations: 50% of sons are haemophiliac. 50% of daughters are carriers. No daughter is affected in this cross.

Why affected females are extremely rare: A female has two X chromosomes. To be affected, she needs two copies of the recessive allele (X^h X^h). This can only happen if her father is haemophiliac (X^h Y) AND her mother is either a carrier (X^H X^h) or affected (X^h X^h). Since haemophiliac males often did not survive to reproductive age before modern treatment, the combination was exceedingly rare. Even today, the probability of this genotype is very low. In contrast, a male needs only one copy of the recessive allele (X^h Y) because he has only one X chromosome, making the disorder far more common in males.

Worked Examples

Example 1 — Incomplete dominance (snapdragon)

Red (RR) × White (rr) → all Rr (Pink) [F1] Pink (Rr) × Pink (Rr) → 1 RR (Red) : 2 Rr (Pink) : 1 rr (White) [F2] Phenotype ratio 1:2:1 = genotype ratio (no complete dominance).

Example 2 — Codominance (ABO blood groups)

IᴬIᴮ → Group AB: BOTH antigens A and B are expressed (codominance). Cross IᴬIᴮ × ii → Iᴬi (A) : Iᴮi (B) in 1:1.

Example 3 — Pleiotropy & dihybrid recap

A single gene affecting multiple traits = pleiotropy (e.g. sickle-cell, PKU). Dihybrid F2 phenotype ratio remains 9:3:3:1 for independently assorting genes.

Example 4 — ABO blood group cross (both parents heterozygous)

Iᴬi (Group A) × Iᴮi (Group B) Gametes: Iᴬ, i from parent 1; Iᴮ, i from parent 2 Offspring: IᴬIᴮ (AB), Iᴬi (A), Iᴮi (B), ii (O) Ratio: 1 AB : 1 A : 1 B : 1 O

Common Mistakes to Avoid

  • Forgetting I^A I^B genotype for blood group AB — both alleles expressed = codominance. Blood group AB is always I^A I^B; there is no homozygous form.
  • Saying haemophilia is autosomal — it is X-linked. The gene is on the X chromosome, not an autosome.
  • Confusing carrier (X^H X^h) with affected female (X^h X^h) — a carrier has one normal allele and is usually unaffected; an affected female needs two defective alleles, which is very rare.
  • Stating Huntington's is recessive — it is autosomal dominant (one copy causes disease). This is a very common exam mistake.
  • ❌ Saying incomplete dominance gives a 3:1 ratio → ✅ Incomplete dominance gives a 1:2:1 phenotypic ratio in F2 (intermediate heterozygote).
  • ❌ Confusing codominance with incomplete dominance → ✅ Codominance — both alleles are fully expressed (blood group AB); Incomplete dominance — heterozygote shows a blended/intermediate phenotype (pink snapdragon).
  • ❌ Stating haemophilia is autosomal → ✅ Haemophilia is an X-linked recessive disorder. Males are affected (X^h Y); females are carriers (X^H X^h).
  • ❌ Writing blood group O has both antigens → ✅ Blood group O has no antigens on RBCs (genotype ii); blood group AB has both A and B antigens.
  • ❌ Saying sickle cell anaemia is dominant → ✅ Sickle cell anaemia is an autosomal recessive disorder; two copies of HbS are needed for the disease (HbS HbS).
  • ❌ Confusing carrier female with affected female in X-linked disorders → ✅ A carrier has one normal and one defective allele (X^H X^h); an affected female needs two defective alleles (X^h X^h), which is very rare.
  • ❌ Stating erythroblastosis foetalis occurs in the first pregnancy → ✅ It typically occurs in the second or subsequent Rh+ pregnancies because the mother needs to have been sensitised first.
  • ❌ Writing Huntington's disease is recessive → ✅ Huntington's disease is autosomal dominant — one copy of the defective gene (Hh) is sufficient to cause the disease.

Exam Checklist

  • [ ] Know all three alleles for ABO blood groups (I^A, I^B, i) and their dominance relationships
  • [ ] Write genotypes for all four blood groups correctly (A: I^A I^A or I^A i, etc.)
  • [ ] Explain codominance using ABO blood group example (I^A I^B = AB)
  • [ ] Explain incomplete dominance using snapdragon example (1:2:1 ratio)
  • [ ] Define pleiotropy with sickle cell anaemia as example
  • [ ] Draw and interpret crosses for X-linked recessive disorders (haemophilia, colour blindness)
  • [ ] Explain why X-linked recessive disorders are more common in males
  • [ ] List autosomal recessive disorders (sickle cell, PKU, cystic fibrosis) vs autosomal dominant (Huntington's, achondroplasia)
  • [ ] Explain Rh factor and erythroblastosis foetalis mechanism and prevention (RhoGAM)
  • [ ] Know the point mutation in sickle cell: glutamic acid → valine at position 6 of beta-globin
  • [ ] Differentiate carrier vs affected individuals in X-linked disorders
  • [ ] Remember: universal donor = O, universal recipient = AB
  • [ ] Know the cross for a carrier female (X^H X^h) × normal male (X^H Y) and the 25% probability outcomes
  • [ ] Practise solving ABO blood group crosses — write all possible offspring genotypes and phenotypes
  • [ ] Explain why affected females in X-linked recessive disorders are extremely rare
  • [ ] Know the difference between codominance, incomplete dominance, and pleiotropy with examples
  • [ ] Remember: erythroblastosis foetalis occurs in second or subsequent Rh+ pregnancies, not the first
  • [ ] Review the CFTR gene mutation → cystic fibrosis; phenylalanine hydroxylase deficiency → PKU; dystrophin mutation → Duchenne muscular dystrophy

Frequently Asked Questions

ABO blood group is controlled by a single gene (I) with three alleles: I^A, I^B, i. I^A and I^B are codominant; i is recessive. Genotypes: I^A I^A or I^A i = Blood group A, I^B I^B or I^B i = Blood group B, I^A I^B = Blood group AB (both expressed — codominance), ii = Blood group O. This is an example of multiple allelism and codominance.