Quick Concept Summary
Mixture and alligation is the exam-friendly form of the weighted average. The alligation (cross-difference) rule instantly gives the ratio in which two ingredients must be combined to reach a target mean — saving you from setting up algebra. The same tool solves average-age, average-marks, and average-speed problems, not just literal mixtures.
The Alligation Rule
To mix a cheaper item and a dearer item to a mean value:
Quantity of cheaper : quantity of dearer = (d − m) : (m − c)
This ratio tells you how to mix; multiply by the total to get actual amounts.
Repeated Replacement (Milk & Water)
If a vessel of x litres has some liquid removed (y litres) and refilled, repeated n times:
Liquid remaining = x × (1 − y/x)ⁿ
Worked Examples
Example 1: In what ratio must rice at ₹30/kg and ₹45/kg be mixed to cost ₹35/kg? cheaper:dearer = (45 − 35) : (35 − 30) = 10 : 5 = 2 : 1.
Example 2: A 40-litre vessel is full of milk. 8 litres are removed and replaced with water, done twice. Milk left? 40 × (1 − 8/40)² = 40 × (4/5)² = 40 × 16/25 = 25.6 litres.
Example 3: Average age of a class is 15. Boys average 16, girls average 14. Ratio of boys to girls? boys:girls = (15 − 14) : (16 − 15) = 1 : 1 → 1 : 1.
Example 4: Mix 60 kg of two sugars (₹20 and ₹28) to sell at ₹25/kg. Quantities? ratio = (28 − 25):(25 − 20) = 3:5 → of 60 kg → 22.5 kg and 37.5 kg.
Common Mistakes
- Treating the alligation result as amounts instead of a ratio.
- Swapping the cross-differences (cheaper gets d − m, not m − c).
- In replacement, using subtraction instead of the (1 − y/x)ⁿ power.
Exam Tips
- Use alligation for any weighted-average question — it is faster than algebra.
- Keep the orientation fixed: cheaper-top-left pairs with the bottom-right difference.
- For replacement, remember the answer is always less than the original — a good sanity check.
