Unit X Overview — What TNPSC Tests
TNPSC Group 1 Prelims Unit X (Aptitude & Mental Ability) covers these topic clusters:
| Topic Cluster | Types of Questions | Expected Questions |
|---|---|---|
| Number Series & Sequences | Find next term; find missing term | 2–3 |
| Analogies (Number/Letter/Word) | Identify the relationship | 1–2 |
| Coding-Decoding | Decode letters/numbers using a pattern | 1–2 |
| Simplification & Arithmetic | BODMAS; fractions; percentages; ratios | 3–4 |
| Time, Work & Speed | Classic word problems | 1–2 |
| Simple & Compound Interest | SI/CI formulae | 1–2 |
| Data Interpretation | Table/chart reading | 2–3 |
| Logical Reasoning / Syllogisms | Statements → Conclusions | 1–2 |
| Clocks & Calendars | Angle, day-of-week problems | 1 |
| Average, Ratio & Proportion | Direct computation | 1–2 |
Total: ~15 questions, ~22 marks
Part 1 — Number Series
Types of Number Series
Type 1: Arithmetic Progression (constant difference)
Each term increases/decreases by a fixed number.
Example: 3, 7, 11, 15, ? Common difference = 4 → Answer: 19
Type 2: Geometric Progression (constant ratio)
Each term multiplied by a fixed number.
Example: 2, 6, 18, 54, ? Ratio = 3 → Answer: 162
Type 3: Squares / Cubes
Example: 1, 4, 9, 16, 25, ? 1², 2², 3², 4², 5² → Answer: 36 (6²)
Example: 1, 8, 27, 64, ? 1³, 2³, 3³, 4³ → Answer: 125 (5³)
Type 4: Mixed / Two-step series
Example: 2, 3, 5, 8, 13, ? Differences: 1, 2, 3, 5 (Fibonacci-like) → Answer: 21
Example: 1, 2, 6, 24, ? 1×1=1, 1×2=2, 2×3=6, 6×4=24 → Answer: 120 (24×5)
Type 5: Missing term in middle
Example: 4, 9, ?, 25, 36 Perfect squares: 4=2², 9=3², 16=4², 25=5² → Answer: 16
Number Series Practice (10 Questions)
1. 7, 14, 21, 28, ?
- a) 33
- b) 35 ✓
- c) 36
- d) 42
2. 3, 6, 12, 24, ?
- a) 36
- b) 42
- c) 48 ✓
- d) 54
3. 1, 1, 2, 3, 5, 8, ?
- a) 11
- b) 13 ✓
- c) 14
- d) 16
Fibonacci: each term = sum of previous two. 5+8 = 13.
4. 2, 5, 10, 17, 26, ?
- a) 35
- b) 36
- c) 37 ✓
- d) 38
Differences: 3, 5, 7, 9, 11 (odd numbers) → 26+11 = 37
5. 100, 50, 25, 12.5, ?
- a) 5
- b) 6.25 ✓
- c) 6
- d) 5.5
Divide by 2 each time → 12.5 ÷ 2 = 6.25
6. 1, 8, 27, 64, 125, ?
- a) 196
- b) 216 ✓
- c) 225
- d) 243
Cubes: 6³ = 216
7. 4, 7, 12, 19, 28, ?
- a) 37
- b) 39 ✓
- c) 40
- d) 41
Differences: 3, 5, 7, 9, 11 → 28+11 = 39
8. 2, 3, 5, 9, 17, ?
- a) 29
- b) 33 ✓
- c) 31
- d) 35
Each term = (previous term × 2) - 1. 17×2 - 1 = 33
9. 0, 1, 4, 9, 16, 25, ?
- a) 30
- b) 32
- c) 36 ✓
- d) 38
0², 1², 2², 3², 4², 5², 6² = 36
10. 6, 11, 21, 41, ?
- a) 70
- b) 75
- c) 81 ✓
- d) 85
Each term = (previous × 2) - 1. 41×2 - 1 = 81
Part 2 — Analogies (Number, Letter, Word)
Number Analogies
Find the relationship between first pair → apply to second.
Format: 4 : 16 :: 7 : ? → 4² = 16, so 7² = 49
Format: 3 : 12 :: 5 : ? → 3 × 4 = 12, so 5 × 4 = 20
Letter Analogies
Format: AC : EG :: BD : ? → AC skips one letter (A_C); EG skips one letter (E_G) → BD skips one letter (B_D) → FH skips one (F_H) → Answer: FH
Format: AB : YX :: CD : ? → AB reversed from end = YX (A=1st, Y=25th from end; B=2nd, X=24th) → CD → WV → Answer: WV
Word Analogies (Concept-based)
Format: Doctor : Hospital :: Teacher : ? → Doctor works in Hospital; Teacher works in School
Format: Pen : Write :: Scissors : ? → Pen is used to Write; Scissors are used to Cut
Analogy Practice (8 Questions)
11. 2 : 8 :: 3 : ?
- a) 18
- b) 12
- c) 27 ✓
- d) 24
2³ = 8; 3³ = 27
12. 9 : 3 :: 49 : ?
- a) 5
- b) 7 ✓
- c) 6
- d) 9
√9 = 3; √49 = 7
13. ACEG : BDFH :: IKMO : ?
- a) JLNP
- b) JLNP ✓
- c) KLNO
- d) JKMN
Each letter shifted +1: I→J, K→L, M→N, O→P
14. Doctor : Stethoscope :: Carpenter : ?
- a) Needle
- b) Saw ✓
- c) Spanner
- d) Plough
15. Pen : Ink :: Lamp : ?
- a) Wire
- b) Switch
- c) Oil/Electricity ✓
- d) Glass
16. 25 : 125 :: 36 : ?
- a) 196
- b) 216 ✓
- c) 206
- d) 256
5² : 5³ :: 6² : 6³ → 36 : 216
17. FILM : ADGH :: MILK : ?
- a) HADG
- b) HADE ✓
- c) HIAG
- d) GHAD
Each letter -5: F→A, I→D, L→G, M→H → M→H, I→D, L→G, K→F → HDGF
Wait — let me recheck: F(6)-5=A(1), I(9)-5=D(4), L(12)-5=G(7), M(13)-5=H(8) → ADGH ✓ M(13)-5=H(8), I(9)-5=D(4), L(12)-5=G(7), K(11)-5=F(6) → HDGF
- a) HDGF
- b) HDGF ✓
- c) GHDF
- d) FGDH
18. Aeroplane : Pilot :: Ship : ?
- a) Crew
- b) Engineer
- c) Captain ✓
- d) Sailor
Part 3 — Coding and Decoding
How Coding Works
A code assigns letters/numbers to words or letters using a consistent pattern.
Type 1: Letter substitution If APPLE = BQQMF, then each letter is shifted +1. So GRAPE = HSBQF
Type 2: Reverse alphabet A=Z, B=Y, C=X... (position from start + position from end = 27) MANGO → NZMTL
Type 3: Number codes If A=1, B=2, C=3... CAT = 3+1+20 = 24
Type 4: Position shift If COMPUTER is coded as DPNQVUFS (each +1), what is PRINTER? P→Q, R→S, I→J, N→O, T→U, E→F, R→S → QSJOUFS
Coding Practice (6 Questions)
19. If CHAIR = 25891 and TABLE = 23564, what is the code for TEACH?
- a) 35225
- b) 35928 ✓
- c) 23598
- d) 35298
T=2, E=5, A=3, C=9, H=8 → TEACH = 25398
Correction: T(Table)=2, A=3, B=4, L=6, E=5; C(Chair)=9, H=8, A=3, I=8...
Let me use a clean example instead:
19. If MANGO = NBOHP (each letter +1), what is PAPAYA coded as?
- a) QBQBZB
- b) QBQBZB ✓
- c) QBQAZA
- d) RAQBZB
P+1=Q, A+1=B, P+1=Q, A+1=B, Y+1=Z, A+1=B → QBQBZB
20. In a code language, ROAD is written as URDG. How is SWAN written?
- a) VXDQ
- b) VZDQ ✓
- c) VZCQ
- d) WZDQ
R+3=U, O+3=R, A+3=D, D+3=G. So S+3=V, W+3=Z, A+3=D, N+3=Q → VZDQ
21. If CAT = 24 (C=3, A=1, T=20; sum=24), what is DOG?
- a) 24
- b) 26
- c) 30 ✓
- d) 28
D=4, O=15, G=7 → 4+15+7 = 26
Wait: D=4, O=15, G=7 → 26. Let me fix: Answer is 26.
- a) 24
- b) 26 ✓
- c) 30
- d) 28
22. If DELHI is coded as EFMIJ (each letter +1), what is MUMBAI?
- a) NVNCBJ
- b) NVNCBJ ✓
- c) NUNCBJ
- d) NVMBAJ
M+1=N, U+1=V, M+1=N, B+1=C, A+1=B, I+1=J → NVNCBJ
23. In a certain code, 15789 = AEGKI and 2346 = BDFH. What is the code for 23549?
- a) BDFKI
- b) BDEAI
- c) BDFAI ✓
- d) BDEKG
2=B, 3=D, 5=F, 4=... wait 4=H... Let me fix: 1=A, 5=E, 7=G, 8=K, 9=I and 2=B, 3=D, 4=F, 6=H 23549 = B, D, E, F, I → BDEFI
- a) BDEFI
- b) BDEFI ✓
- c) BDFEI
- d) BDEIF
24. If in a code language, 'pen' is 'eraser', 'eraser' is 'book', 'book' is 'scale', what do you write with?
- a) Pen
- b) Book
- c) Eraser ✓
- d) Scale
In this code, 'pen' is called 'eraser' — so you write with what is called 'eraser'.
Part 4 — Arithmetic (Percentages, Ratio, SI/CI)
Key Formulas
Percentage:
- x% of y = (x × y) / 100
- % increase = (Increase / Original) × 100
- % decrease = (Decrease / Original) × 100
Ratio and Proportion:
- If a:b = c:d then a×d = b×c (cross multiply)
- Compound ratio of a:b and c:d = ac:bd
Simple Interest:
- SI = (P × R × T) / 100
- Amount = P + SI
Compound Interest:
- A = P(1 + R/100)^T
- CI = A - P
Common shortcut — CI for 2 years:
- CI = SI + (SI × R / 200)
- Or: CI = P[(1+r)² - 1]
Arithmetic Practice (10 Questions)
25. What is 15% of 240?
- a) 32
- b) 36 ✓
- c) 38
- d) 40
240 × 15/100 = 36
26. A price increased from ₹500 to ₹600. What is the percentage increase?
- a) 15%
- b) 20% ✓
- c) 25%
- d) 18%
(100/500) × 100 = 20%
27. If A:B = 3:4 and B:C = 2:3, what is A:B:C?
- a) 3:4:6
- b) 3:4:6 ✓
- c) 6:8:9
- d) 6:8:12
B is common. B = LCM(4,2) = 4. A:B = 3:4; B:C = 2:3 = 4:6. So A:B:C = 3:4:6
28. Find the Simple Interest on ₹8,000 at 5% per annum for 3 years.
- a) ₹1,000
- b) ₹1,100
- c) ₹1,200 ✓
- d) ₹1,500
SI = (8000 × 5 × 3)/100 = 1200
29. What is the Compound Interest on ₹10,000 at 10% per annum for 2 years?
- a) ₹2,000
- b) ₹2,050
- c) ₹2,100 ✓
- d) ₹2,200
A = 10000 × (1.1)² = 10000 × 1.21 = ₹12,100 → CI = ₹2,100
30. In a class of 50 students, 60% are girls. How many boys are there?
- a) 25
- b) 20 ✓
- c) 30
- d) 18
Girls = 60% of 50 = 30. Boys = 50 - 30 = 20
31. A bag contains ₹1, ₹2, and ₹5 coins in ratio 3:2:1. Total coins = 72. What is the total value?
- a) ₹96
- b) ₹120 ✓
- c) ₹108
- d) ₹144
Ratio 3:2:1 → 36 + 24 + 12 = 72 coins ✓ Value = (36×1) + (24×2) + (12×5) = 36 + 48 + 60 = ₹144
Correction: Answer is ₹144.
- a) ₹120
- b) ₹132
- c) ₹144 ✓
- d) ₹156
32. If 12 workers can complete a job in 15 days, how many days will 9 workers take?
- a) 18 days
- b) 20 days ✓
- c) 22 days
- d) 24 days
Workers × Days = constant. 12 × 15 = 9 × D → D = 180/9 = 20 days
33. A train travels 360 km in 4 hours. What is its speed in km/h?
- a) 80 km/h
- b) 90 km/h ✓
- c) 100 km/h
- d) 72 km/h
Speed = Distance/Time = 360/4 = 90 km/h
34. Find the average of 15, 25, 35, 45, 55.
- a) 30
- b) 35 ✓
- c) 40
- d) 45
Sum = 175; Count = 5; Average = 175/5 = 35
Part 5 — Data Interpretation
How to Approach DI Questions
1. Read the table/chart title first — understand what data is shown 2. Note the units — thousands, lakhs, percentages 3. Answer only what is asked — don't read extra data 4. Use approximation — exact calculation wastes time
Practice — Table DI
The following table shows the production (in thousand tonnes) of wheat and rice in 5 states:
| State | Wheat | Rice |
|---|---|---|
| Punjab | 180 | 120 |
| Haryana | 140 | 80 |
| UP | 200 | 160 |
| MP | 100 | 60 |
| Tamil Nadu | 20 | 240 |
35. Which state has the highest total grain production?
- a) Punjab
- b) Haryana
- c) UP ✓
- d) Tamil Nadu
UP = 200+160 = 360; Punjab = 300; TN = 260; Haryana = 220. UP is highest.
36. What is Tamil Nadu's rice production as a percentage of total rice production?
- a) 30%
- b) 36.4% ✓
- c) 40%
- d) 25%
Total rice = 120+80+160+60+240 = 660. TN share = 240/660 × 100 = 36.4%
37. The ratio of wheat to rice production in Punjab is:
- a) 2:1
- b) 3:2 ✓
- c) 4:3
- d) 5:3
Punjab wheat:rice = 180:120 = 3:2
38. How much more wheat does UP produce than Haryana?
- a) 50,000 tonnes
- b) 40,000 tonnes
- c) 60,000 tonnes ✓
- d) 70,000 tonnes
UP wheat = 200,000; Haryana = 140,000; Difference = 60,000 tonnes
Part 6 — Logical Reasoning & Syllogisms
Syllogism Rules (Using Venn Diagrams)
Always draw circles. The conclusion must be TRUE based ONLY on the given statements — not general knowledge.
Type 1: All A are B. All B are C. → Conclusion: All A are C. ✓ (A circle inside B inside C)
Type 2: All A are B. No B is C. → Conclusion: No A is C. ✓
Type 3: Some A are B. All B are C. → Conclusion: Some A are C. ✓ (the "some A" that are B must also be C)
Type 4: Some A are B. Some B are C. → Conclusion: Some A are C. ✗ (NOT necessarily true — the "some" may not overlap)
Syllogism Practice (6 Questions)
39. Statements: All cats are animals. All animals are living beings. Conclusion I: All cats are living beings. Conclusion II: Some living beings are cats.
- a) Only Conclusion I follows
- b) Only Conclusion II follows
- c) Both I and II follow ✓
- d) Neither follows
All cats → animals → living beings. So all cats are living beings (I). And since cats exist, some living beings are cats (II).
40. Statements: Some books are pens. All pens are erasers. Conclusion I: Some books are erasers. Conclusion II: All erasers are books.
- a) Only Conclusion I follows ✓
- b) Only Conclusion II follows
- c) Both follow
- d) Neither follows
"Some books are pens" and "all pens are erasers" → those books that are pens are also erasers → Some books are erasers (I ✓). But not all erasers need to be books (II ✗).
41. Statements: No table is a chair. All chairs are wooden. Conclusion I: No table is wooden. Conclusion II: Some wooden things are chairs.
- a) Only I follows
- b) Only II follows ✓
- c) Both follow
- d) Neither follows
No table is chair — but tables could still be wooden (they could be wooden through another path). So I doesn't necessarily follow. But since all chairs are wooden, some wooden things are chairs (II ✓).
42. Statements: All mangoes are fruits. Some fruits are sweet. Conclusion I: Some mangoes are sweet. Conclusion II: All sweet things are fruits.
- a) Only I
- b) Only II
- c) Both
- d) Neither ✓
"Some fruits are sweet" — those fruits may or may not include mangoes. Can't conclude I. And not all sweet things are necessarily fruits (II also fails).
43. Statements: All doctors are graduates. Ravi is a doctor. Conclusion: Ravi is a graduate.
- a) Does not follow
- b) Follows ✓
- c) Partially follows
- d) Cannot be determined
44. Statements: Some students passed. All who passed got medals. Conclusion I: Some students got medals. Conclusion II: All students got medals.
- a) Only II
- b) Only I ✓
- c) Both
- d) Neither
"Some students passed" and "all who passed got medals" → those some students got medals (I ✓). But not ALL students passed, so II doesn't follow.
Part 7 — Clocks and Calendars
Clock Problems
Key facts:
- Clock face = 360°
- Hour hand moves: 360° in 12 hours = 0.5° per minute
- Minute hand moves: 360° in 60 minutes = 6° per minute
- Relative speed = 6° - 0.5° = 5.5° per minute
Angle between hands formula:
- Angle = |30H - 5.5M| where H = hours, M = minutes
Example: Angle at 3:00
| = | 30×3 - 5.5×0 | = | 90 | = 90° |
|---|
Example: Angle at 6:30
| = | 30×6 - 5.5×30 | = | 180 - 165 | = 15° |
|---|
Calendar Problems
Key facts:
- Ordinary year = 365 days = 52 weeks + 1 odd day
- Leap year = 366 days = 52 weeks + 2 odd days
- Leap year: divisible by 4; century year divisible by 400
- Odd days in 100 years = 5; 200 years = 3; 300 years = 1; 400 years = 0
Day calculation: Add up odd days → divide by 7 → remainder gives the day (0=Sun, 1=Mon, 2=Tue, 3=Wed, 4=Thu, 5=Fri, 6=Sat)
Clocks & Calendars Practice (5 Questions)
45. What is the angle between the hands of a clock at 4:00?
- a) 100°
- b) 120° ✓
- c) 130°
- d) 90°
|30×4 - 5.5×0| = |120 - 0| = 120°
46. A clock shows 3:15. What is the angle between the hands?
- a) 0°
- b) 7.5° ✓
- c) 15°
- d) 22.5°
|30×3 - 5.5×15| = |90 - 82.5| = 7.5°
47. January 1, 2024 is a Monday. What day is January 1, 2025?
- a) Monday
- b) Wednesday ✓
- c) Tuesday
- d) Thursday
2024 is a leap year (366 days = 52 weeks + 2 odd days). Monday + 2 = Wednesday
48. How many leap years are there between 2001 and 2024?
- a) 5
- b) 6 ✓
- c) 7
- d) 4
2004, 2008, 2012, 2016, 2020, 2024 = 6 leap years
49. If today is Wednesday, what day will it be after 100 days?
- a) Monday
- b) Friday ✓
- c) Thursday
- d) Saturday
100 days = 14 weeks + 2 days. Wednesday + 2 = Friday
Part 8 — Area, Volume, Perimeter
Key Formulas
| Shape | Area | Perimeter/Circumference |
|---|---|---|
| Rectangle | l × b | 2(l+b) |
| Square | a² | 4a |
| Triangle | ½ × b × h | a+b+c |
| Circle | πr² | 2πr |
| Cylinder (volume) | πr²h | — |
| Cube (volume) | a³ | — |
| Cuboid (volume) | l×b×h | — |
Use π = 22/7 or 3.14 in calculations.
Area & Volume Practice (5 Questions)
50. A rectangle has length 12 cm and breadth 8 cm. What is its area?
- a) 80 sq cm
- b) 96 sq cm ✓
- c) 100 sq cm
- d) 84 sq cm
51. What is the circumference of a circle with radius 7 cm? (π = 22/7)
- a) 42 cm
- b) 44 cm ✓
- c) 46 cm
- d) 40 cm
C = 2πr = 2 × (22/7) × 7 = 44 cm
52. A cube has side 5 cm. What is its volume?
- a) 100 cm³
- b) 125 cm³ ✓
- c) 150 cm³
- d) 75 cm³
V = 5³ = 125 cm³
53. The area of a triangle with base 10 cm and height 6 cm is:
- a) 60 sq cm
- b) 30 sq cm ✓
- c) 25 sq cm
- d) 45 sq cm
A = ½ × 10 × 6 = 30 sq cm
54. A cylinder has radius 7 cm and height 10 cm. What is its volume? (π = 22/7)
- a) 1,450 cm³
- b) 1,540 cm³ ✓
- c) 1,600 cm³
- d) 1,500 cm³
V = πr²h = (22/7) × 49 × 10 = 22 × 70 = 1,540 cm³
Exam Strategy — Unit X
Time allocation: 15 questions × 45 seconds = ~11 minutes. Attempt Unit X in one focused stretch.
Order of difficulty (easiest first): 1. Number series (pattern recognition — 20 seconds each) 2. Analogies (30 seconds each) 3. Basic arithmetic — average, ratio, percentage 4. Area/Volume (formula application) 5. Data Interpretation (read table once, answer 3–4 questions) 6. Syllogisms (draw Venn diagram — 60 seconds each) 7. Clocks (formula application)
Common mistakes to avoid:
- Series: Don't just look at +/- differences. Check ×, ², ³ too.
- Percentages: Remember "x% of y" ≠ "y% of x" in different contexts.
- Syllogisms: Never use outside knowledge — only what statements say.
- DI: Read the UNIT carefully (thousands vs lakhs changes everything).
- Clocks: Angle formula uses H × 30, not H × 60.
Board Exam Quick Facts
- Unit X in Group 1 Prelims = ~15 questions, 1.5 marks each = ~22 marks
- Number series: check differences, ratios, squares, cubes in order
- SI = PRT/100; CI for 2 years = P[(1+r/100)² - 1]
- Angle between clock hands = |30H − 5.5M|
- Leap year: divisible by 4 (not century) OR divisible by 400 (century)
- Syllogism: always draw Venn diagram — never assume from general knowledge
- Area of triangle = ½ × base × height; Circle area = πr²; Circle circumference = 2πr
