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Class 9 · Tamil Nadu State Board

Samacheer Kalvi 9th Science Light Exercise Solutions

Complete TN Class 9 Science Chapter 6 Light exercise solutions — MCQs, True/False, Fill in the Blanks, Match the Following, Short Answers, Detailed Answers, Numericals, and Exam Tips.

Updated 12 June 202621 min read

How to Use This Page

These are complete exercise solutions for Samacheer Kalvi 9th Science Chapter 6 — Light. Solve each question yourself first, then verify below. Draw ray diagrams neatly with labels for mirror/lens questions. Pay close attention to the Cartesian sign convention — it is the single biggest source of errors in numerical problems on this chapter.


Key Concepts (Quick Recap)

TermDefinition
ReflectionLight bounces back from a surface. Laws: angle of incidence = angle of reflection (∠i = ∠r); incident ray, reflected ray, and normal lie in the same plane.
Concave mirrorConverging mirror (inner curved surface reflects). Can form real or virtual images depending on object position.
Convex mirrorDiverging mirror (outer curved surface reflects). Always forms a virtual, erect, diminished image.
Mirror formula1/f = 1/v + 1/u — relates focal length (f), image distance (v), and object distance (u) using Cartesian sign convention.
Magnificationm = h'/h = –v/u. Positive m = virtual/erect image; negative m = real/inverted image.
RefractionBending of light at the interface of two media due to change in speed. Rarer → denser: bends towards normal. Denser → rarer: bends away.
Refractive indexμ = sin i / sin r = c/v. Higher μ means denser medium and slower light speed.
Total internal reflectionLight reflects completely back into the denser medium when incident angle exceeds the critical angle. Requires: (1) denser → rarer medium, (2) angle > critical angle.
Centre of curvature (C)Centre of the sphere of which the mirror is a part. Distance from pole to C = radius of curvature (R).
Focus (F)Mid-point between pole and centre of curvature. Parallel rays converge at F (concave) or appear to diverge from F (convex). R = 2f.
Pole (P)The centre of the reflecting surface of the mirror. All distances are measured from the pole.
Critical angleThe angle of incidence in the denser medium for which the refracted ray grazes the surface (angle of refraction = 90°). Beyond this, total internal reflection occurs.
DispersionSplitting of white light into its constituent colours (VIBGYOR) when passing through a prism, due to different refractive indices for different wavelengths.

I. Choose the Correct Answer

Q1. A ray of light passes from one medium to another. Refraction takes place when angle of incidence is: (a) 0° (b) 45° ✓ (c) 90° (d) 180°

Answer(b) ✓ — At 0° (normal incidence), light passes without bending. At 45°, the ray bends due to change in speed between media.

Q2. Which mirror is used as reflectors in torchlight? (a) Concave mirror ✓ (b) Convex mirror (c) Plane mirror (d) Parabolic mirror

Answer(a) ✓ — Concave mirrors focus light into a powerful parallel beam when the bulb is placed at the focus.

Q3. We can create enlarged, virtual images with: (a) Concave mirror ✓ (b) Convex mirror (c) Plane mirror (d) Convex lens

Answer(a) ✓ — When the object is between F and P of a concave mirror, the image is enlarged, virtual, and erect.

Q4. When the reflecting surface is curved outwards, the mirror formed will be: (a) Concave mirror (b) Convex mirror ✓ (c) Plane mirror (d) Parabolic mirror

Answer(b) ✓ — Outer curved surface = convex mirror; inner curved surface = concave mirror.

Q5. When a beam of white light passes through a prism it gets: (a) Reflected (b) Refracted and dispersed ✓ (c) Only refracted (d) Only reflected

Answer(b) — White light splits into its constituent colours (VIBGYOR) due to different refractive indices for different wavelengths.

Q6. The speed of light is maximum in: (a) Vacuum ✓ (b) Glass (c) Water (d) Diamond

Answer(a) ✓ — Speed of light is maximum in vacuum (3 × 10⁸ m/s). In other media, it slows down proportionally to the refractive index.

Q7. A ray of light travelling in air falls obliquely on the surface of a calm pond. It will: (a) Go straight without bending (b) Bend towards the normal ✓ (c) Bend away from the normal (d) Reflect back into air

Answer(b) ✓ — Air is rarer and water is denser. When light goes from rarer to denser medium obliquely, it bends towards the normal and slows down.

Q8. The focal length of a concave mirror is 15 cm. Its radius of curvature is: (a) 7.5 cm (b) 15 cm (c) 30 cm ✓ (d) 45 cm

Answer(c) ✓ — Radius of curvature R = 2f = 2 × 15 = 30 cm. This relationship holds for all spherical mirrors.

Q9. If the magnification produced by a mirror is +1, the image is: (a) Real, inverted, magnified (b) Virtual, erect, same size ✓ (c) Real, inverted, diminished (d) Virtual, erect, diminished

Answer: (b) ✓ — Positive magnification means virtual and erect.m= 1 means same size. This is produced by a plane mirror.

II. True or False

1. The angle of deviation depends on the refractive index of the glass.
AnswerTrue ✓
2. If a ray of light passes obliquely from one medium to another, it does not suffer any deviation.
AnswerFalse — Correction: When light passes obliquely from one medium to another with different optical densities, it bends at the interface (refraction).
3. The convex mirror always produces a virtual, diminished and erect image of the object.
AnswerTrue ✓
4. When an object is at the centre of curvature of a concave mirror, the image formed will be virtual and erect.
AnswerFalse — Correction: The image is real, inverted, and the same size as the object, located at C.
5. The reason for brilliance of diamonds is total internal reflection of light.
AnswerTrue ✓ — Diamonds have a very high refractive index (2.41), causing multiple internal reflections.
6. A ray passing through the centre of curvature of a concave mirror gets diverged after reflection.
AnswerFalse — Correction: A ray directed towards C strikes the mirror normally (∠i = 0°), so it retraces its path. There is no divergence.
7. The refractive index of a medium can be less than 1.
AnswerFalse — Correction: Refractive index μ = c/v, and since the speed of light in any medium is always less than or equal to c, μ ≥ 1. Vacuum has μ = 1; all other media have μ > 1.
8. Snell's law fails when light travels from a denser to a rarer medium at an angle greater than the critical angle.
AnswerTrue ✓ — Beyond the critical angle, Snell's law would give sin r > 1, which is impossible; instead, total internal reflection occurs.

Assertion and Reason

Q1. A: A plane mirror is preferred over convex/concave for observing traffic at a hairpin bend. R: A convex mirror has a much larger field of view than a plane mirror or concave mirror. → (d) A is false (convex mirror is preferred, not plane mirror) but R is true.

Q2. A: Incident ray directed towards centre of curvature retraces its path. R: Angle of incidence = Angle of reflection = 0°. → (b) Both A and R are true, but R is not the correct explanation. The ray retraces because it hits the mirror normally (at 90° to the surface), making ∠i = 0°, not because ∠i = ∠r.


III. Fill in the Blanks

1. In going from a rarer to denser medium, the ray of light bends towards the normal. 2. The mirror used in search light is concave mirror. 3. The angle of deviation of a light ray in a prism depends on the angle of prism and angle of incidence. 4. The radius of curvature of a concave mirror whose focal length is 5 cm is 10 cm (R = 2f). 5. Large concave mirrors are used to concentrate sunlight to produce heat in solar furnaces. 6. The minimum angle of incidence in the denser medium for which the refracted ray grazes the surface is called the critical angle. 7. According to Snell's law, μ₁ sin i = μ₂ sin r; for light going from air to glass, μ = sin i / sin r = c/v, where c is the speed of light in vacuum. 8. The image formed by a convex mirror is always virtual, erect, and diminished, regardless of the object's position. 9. When an object is placed at the focus of a concave mirror, the image is formed at infinity.


IV. Match the Following

#Column IColumn II
1Ratio of height of image to height of object(c) Magnification
2Used in hairpin bends in mountains(d) Convex Mirror
3Coin inside water appearing slightly raised(e) Refraction
4Mirage(b) Total Internal Reflection
5Used as Dentist's mirror(a) Concave Mirror
6Splitting of white light into VIBGYOR(g) Dispersion
7Centre of the reflecting surface of a mirror(f) Pole
8Distance from pole to centre of curvature(h) Radius of curvature

V. Answer Briefly (2-mark)

Q1. Which mirror/lens has a negative focal length per Cartesian sign convention?
Answer

Concave mirrors and concave lenses have negative focal lengths (f < 0) per the Cartesian sign convention. Since the focus lies in front of the mirror (on the same side as the object for a concave mirror), the distance is measured against the direction of incident light, making it negative. Convex mirrors and convex lenses have positive focal lengths because their focus lies behind the reflecting/refracting surface.

Q2. Name the mirror that can give (i) an erect and enlarged image, (ii) the same sized, inverted image.
Answer

Concave mirror is the only spherical mirror that can produce both types of images. (i) When the object is placed between F and P, the concave mirror forms a virtual, erect, and enlarged image. (ii) When the object is placed at C, it forms a real, inverted, and same-sized image. A convex mirror always gives a diminished image and can never produce a same-sized or enlarged real image.

Q3. If an object is placed at the focus of a concave mirror, where is the image formed?
Answer

The image is formed at infinity. When the object is at the focus, the reflected rays become parallel and never actually converge, forming a highly magnified image at an infinite distance. This principle is used in torchlights and searchlights where the bulb is placed at the focus to produce a parallel beam of light.

Q4. Why does a ray of light bend when travelling between media?
Answer

Light bends because its speed changes when moving between media of different optical densities. In a denser medium, light slows down and the wavefront closer to the interface decelerates first, causing the ray to bend towards the normal. In a rarer medium, light speeds up and the ray bends away from the normal. This change in direction is what we call refraction, governed by Snell's law: μ₁ sin i = μ₂ sin r.

Q5. What is the speed of light in vacuum?
Answer

The speed of light in vacuum is 3 × 10⁸ m/s (approximately 3 lakh km per second). This is the maximum speed at which light can travel in any medium. In all other transparent media like glass, water, or diamond, light travels slower than this value. The ratio of the speed of light in vacuum to its speed in a medium gives the refractive index of that medium.

Q6. Why are concave mirrors used by dentists?
Answer

A concave mirror focuses light onto a small area and produces a magnified, erect image when the object (teeth) is placed close to it, within its focal length. This allows the dentist to see a clear, enlarged view of the teeth for examination and treatment. The mirror is held close to the teeth so the object is between F and P, producing a virtual, erect, and magnified image.

Q7. State Snell's law of refraction.
Answer

Snell's law states that the ratio of the sine of the angle of incidence to the sine of the angle of refraction is constant for a given pair of media: μ₁ sin i = μ₂ sin r. For light going from air (μ₁ ≈ 1) into a medium of refractive index μ, this simplifies to μ = sin i / sin r. This constant is the refractive index of the second medium with respect to the first.

Q8. What happens to a ray of light striking a concave mirror along the principal axis?
Answer

A ray of light travelling along the principal axis strikes the mirror normally, so the angle of incidence is 0°. By the law of reflection, the angle of reflection is also 0°, and the ray retraces its path back along the principal axis. This is why a ray directed towards the centre of curvature retraces its path.

Q9. Differentiate between real and virtual images.
Answer

A real image is formed by the actual convergence of reflected or refracted rays and can be projected on a screen; it is always inverted. A virtual image is formed by the apparent convergence of rays and cannot be projected on a screen; it is always erect. Concave mirrors can produce both real and virtual images depending on object position, while convex mirrors always produce virtual images.


VI. Answer in Detail (5-mark)

Q1. Draw ray diagrams for concave mirror when the object is at various positions and describe the nature of the image.
Answer

A concave mirror produces different types of images depending on the object's position relative to the focus (F) and centre of curvature (C). The mirror formula 1/f = 1/v + 1/u and magnification m = –v/u govern all cases.

(i) Object at infinity: Rays arrive parallel to the principal axis. After reflection, they converge at the focus F. The image is real, inverted, and highly diminished (point-sized). This is how distant stars appear at the focus of a concave telescope mirror.

(ii) Object beyond C: Rays from the object converge between F and C after reflection. The image is real, inverted, and diminished. As the object moves farther away, the image shrinks and moves closer to F.

(iii) Object at C: The image forms exactly at C. It is real, inverted, and the same size as the object. This is the only position where object and image are equidistant from the mirror.

(iv) Object between C and F: The reflected rays converge beyond C. The image is real, inverted, and magnified. A projector uses this configuration — the slide (object) is between C and F and the enlarged image is projected on a distant screen.

(v) Object at F: Reflected rays become parallel, meeting at infinity. The image is real, inverted, and highly magnified (formed at infinity). Searchlights place the bulb at F to produce a parallel beam.

(vi) Object between F and P: Reflected rays diverge but appear to come from behind the mirror. The image is virtual, erect, and magnified. This is the configuration used by dentists and in shaving mirrors.

Summary table:

Object PositionImage PositionNature of Image
At infinityAt FReal, inverted, diminished
Beyond CBetween F and CReal, inverted, diminished
At CAt CReal, inverted, same size
Between C and FBeyond CReal, inverted, magnified
At FAt infinityReal, inverted, highly magnified
Between F and PBehind mirrorVirtual, erect, magnified
Q2. Explain refraction with ray diagrams and state Snell's law.
Answer

Refraction is the bending of light as it passes from one transparent medium to another due to a change in its speed. When light enters a denser medium, it slows down and bends towards the normal; when it enters a rarer medium, it speeds up and bends away from the normal.

(a) Rarer to denser medium (e.g., air to glass): The ray bends towards the normal. The speed of light decreases because the denser medium offers more resistance to the passage of light. The angle of refraction (r) is smaller than the angle of incidence (i). Practical examples include a coin at the bottom of a pool appearing raised, and a pencil in water appearing bent at the surface.

(b) Denser to rarer medium (e.g., glass to air): The ray bends away from the normal. The speed of light increases as the medium becomes optically less dense. The angle of refraction is larger than the angle of incidence. If the angle of incidence exceeds the critical angle, total internal reflection occurs — the ray reflects entirely back into the denser medium. This is the principle behind optical fibres and diamond brilliance.

(c) Normal incidence (i = 0°): When light hits the interface perpendicular to the surface (along the normal), it passes straight through without any deviation. The direction does not change, though the speed does change in the new medium.

Snell's Law: The ratio of the sine of the angle of incidence to the sine of the angle of refraction is constant for a given pair of media:

μ₁ sin i = μ₂ sin r

For light going from air (μ₁ ≈ 1) to a medium with refractive index μ:

μ = sin i / sin r = c / v

where c = speed of light in vacuum, v = speed of light in the medium. Snell's law is fundamental to understanding lenses, prisms, and all optical instruments.

Q3. Explain total internal reflection and its applications.
Answer

Total internal reflection (TIR) occurs when light travelling from a denser medium to a rarer medium strikes the boundary at an angle of incidence greater than the critical angle. Instead of refracting out, the light is completely reflected back into the denser medium. Two conditions must be satisfied simultaneously: (1) light must travel from a denser medium to a rarer medium, and (2) the angle of incidence must exceed the critical angle for that pair of media.

The critical angle is the angle of incidence in the denser medium for which the angle of refraction in the rarer medium is exactly 90°. It is calculated using: sin θc = μ_raer / μ_denser = 1/μ (when the rarer medium is air). For glass (μ = 1.5), θc ≈ 42°; for diamond (μ = 2.41), θc ≈ 24.4°.

Applications of total internal reflection:

  • Diamonds: The extremely small critical angle (≈24°) combined with the high refractive index means that most light entering a cut diamond undergoes multiple total internal reflections before emerging, producing its characteristic sparkle.
  • Optical fibres: Light signals travel through glass or plastic fibres by repeated TIR, enabling high-speed data transmission over long distances with minimal loss.
  • Mirages: On hot days, the air near the ground is much less dense than the air above. Light from the sky undergoes TIR near the ground, creating the illusion of a water pool on the road.
  • Prisms in binoculars: Right-angled prisms use TIR to reflect light, allowing compact binocular designs without mirror coatings that would absorb some light.

VII. Numerical Problems

Q1. A concave mirror produces a 3 times magnified real image of an object at 7 cm from the mirror. Find the image position.
Answer

m = –3 (real image, so negative), u = –7 cm (object in front of mirror) m = –v/u → –3 = –v/(–7) → v = –21 cm Image is formed 21 cm in front of the mirror (real, inverted).

Q2. Light enters a glass slab of refractive index 1.5. Find the speed of light in glass.
Answer

μ = c/v → v = c/μ = 3 × 10⁸ / 1.5 = 2 × 10⁸ ms⁻¹

Q3. Speed of light in water = 2.25 × 10⁸ ms⁻¹; speed in vacuum = 3 × 10⁸ ms⁻¹. Find refractive index.
Answer

μ = c/v = 3 × 10⁸ / 2.25 × 10⁸ = 1.33

Q4. Object of size 1 cm placed at 15 cm from a concave mirror (f = 10 cm). Find image position and size.
Answer

1/f = 1/v + 1/u → 1/10 = 1/v + 1/(–15) → 1/v = 1/10 + 1/15 = 3/30 + 2/30 = 5/30 = 1/6 v = –30 cm (real image, 30 cm in front of mirror) m = –v/u = –(–30)/(–15) = –2 Image height = m × object height = –2 × 1 = –2 cm (inverted, 2 cm tall)

Q5. Light travels from rarer to denser medium, angle of incidence = 45°, angle of refraction = 30°. Find refractive index.
Answer

μ = sin i / sin r = sin 45° / sin 30° = (1/√2) / (1/2) = 2/√2 = √2 = 1.414

Q6. Speed of light in diamond if refractive index = 2.41.
Answer

v = c/μ = 3 × 10⁸ / 2.41 = 1.245 × 10⁸ m/s


Common Mistakes to Avoid

1. Confusing concave and convex mirror image properties ❌ Assuming all spherical mirrors produce the same type of image ✅ Concave: real/virtual depending on object position. Convex: always virtual, erect, diminished.

2. Wrong sign convention ❌ Using all positive distances or mixing up sign rules ✅ Always use Cartesian sign convention: distances against incident ray direction (in front of mirror) are negative; behind the mirror are positive.

3. Forgetting R = 2f ❌ Calculating focal length from radius independently ✅ Radius of curvature is always twice the focal length: R = 2f.

4. Mixing up refraction directions ❌ Saying light bends towards the normal when going from denser to rarer ✅ Rarer to denser: bends towards normal. Denser to rarer: bends away from normal.

5. Confusing magnification sign ❌ Using only absolute value and ignoring the sign of magnification ✅ Positive m = virtual/erect image; Negative m = real/inverted image. The sign carries meaning.

6. Confusing total internal reflection with ordinary reflection ❌ Thinking TIR can happen in any direction between media ✅ TIR occurs only when going from denser to rarer medium at angle > critical angle. Two conditions must be met.

7. Incorrect mirror formula application ❌ Writing 1/f = 1/v – 1/u or rearranging incorrectly ✅ The correct formula is 1/f = 1/v + 1/u. Use sign convention consistently for f, v, and u.

8. Forgetting that normal incidence means no bending ❌ Assuming light always bends at an interface ✅ At i = 0° (normal incidence), light passes straight through without deviation, even though speed changes in the new medium.


Exam Checklist

  • [ ] Laws of reflection and refraction memorized
  • [ ] Snell's law formula and its application: μ₁ sin i = μ₂ sin r
  • [ ] Concave mirror ray diagrams for all 6 object positions practiced
  • [ ] Convex mirror image properties (always virtual, erect, diminished)
  • [ ] Mirror formula and magnification formula memorized with sign convention
  • [ ] Refractive index formula: μ = sin i / sin r = c/v
  • [ ] Total internal reflection conditions (denser to rarer, angle > critical angle)
  • [ ] Numerical problems on mirror formula and refractive index practiced
  • [ ] Applications of mirrors (dentist, torch, rear-view) understood
  • [ ] Relationship R = 2f and its use in numerical problems
  • [ ] Critical angle calculation: sin θc = 1/μ for air-medium interface
  • [ ] Difference between real and virtual images can be explained with examples
  • [ ] Dispersion of light through a prism and formation of spectrum understood

Internal Links

  • [Chapter 6 Guide — Light](/school/tamil-nadu-state-board/class/9/science/light)
  • [All Class 9 Science Solutions](/school/tamil-nadu-state-board/class/9/science/solutions)
  • [Class 9 Science Subject Guide](/school/tamil-nadu-state-board/class/9/science)

Frequently Asked Questions

First law: The angle of incidence equals the angle of reflection (∠i = ∠r). Second law: The incident ray, reflected ray, and normal all lie in the same plane.
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