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Samacheer Kalvi 9th Science Heat Exercise Solutions

Complete TN Class 9 Science Chapter 7 Heat exercise solutions — MCQs, True/False, Fill in the Blanks, Match the Following, Short Answers, Detailed Answers, Numericals, and Exam Tips.

Updated 12 June 202619 min read

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These are complete exercise solutions for Samacheer Kalvi 9th Science Chapter 7 — Heat. Solve each question yourself first, then verify below. For numerical problems, always show formula, substitution, and units — marks are awarded for method, not just the final answer. Use the Key Concepts table for a quick review before exams.


Key Concepts (Quick Recap)

TermDefinition
Heat (Q)Form of energy that flows from a hotter body to a colder body; SI unit: joule (J)
TemperatureDegree of hotness or coldness of a body; measured in °C, °F, or K
Temperature conversionK = °C + 273.15 and °F = (9/5)°C + 32
Specific heat capacity (c)Heat required to raise the temperature of 1 kg of a substance by 1 K; formula: Q = mcΔT; unit: J/(kg·K)
Latent heatHeat absorbed or released during change of state without any change in temperature
Latent heat of fusion (Lf)Heat required to convert 1 kg of solid into liquid at its melting point; for ice: 3.34 × 10⁵ J/kg
Latent heat of vaporisation (Lv)Heat required to convert 1 kg of liquid into gas at its boiling point; for water: 2.26 × 10⁶ J/kg
ConductionMode of heat transfer in solids through molecular vibrations without actual movement of particles
ConvectionMode of heat transfer in fluids (liquids and gases) through bulk movement of heated particles
RadiationMode of heat transfer that requires no medium; travels as electromagnetic waves
CalorimetryMeasurement of heat using a calorimeter; principle: heat lost by hot body = heat gained by cold body
Thermal expansionIncrease in dimensions of a substance (solid, liquid, or gas) on heating
Melting pointTemperature at which a solid changes to liquid at constant pressure
Boiling pointTemperature at which a liquid changes to gas at constant pressure

I. Choose the Correct Answer

Q1. Calorimeter is used to measure: (a) temperature (b) heat ✓ (c) specific heat (d) latent heat

Answer(b) ✓ — A calorimeter measures the quantity of heat transferred during physical or chemical processes.

Q2. The specific heat capacity of water is: (a) 4186 J/kg·K ✓ (b) 100 J/kg·K (c) 4186 J/kg (d) 1000 J/kg·K

Answer(a) ✓ — Water has a very high specific heat capacity of 4186 J/(kg·K), which is why it is used as a coolant.

Q3. Which of the following has the lowest specific heat capacity? (a) Water (b) Copper ✓ (c) Iron (d) Aluminium

Answer(b) ✓ — Copper has low specific heat (~385 J/kg·K), meaning it heats up and cools down quickly.

Q4. During change of state, the temperature: (a) increases (b) decreases (c) remains constant ✓ (d) fluctuates

Answer(c) ✓ — During melting or boiling, temperature remains constant as heat is used to change state (latent heat).

Q5. The mode of heat transfer in solids is: (a) convection (b) radiation (c) conduction ✓ (d) both conduction and convection

Answer(c) ✓ — In solids, heat transfers by conduction (molecule to molecule vibration).

Q6. Which substance has the highest specific heat capacity? (a) Copper (b) Iron (c) Water ✓ (d) Aluminium

Answer(c) ✓ — Water has the highest specific heat capacity (4186 J/kg·K) among common substances, making it an excellent coolant and temperature regulator.

Q7. The amount of heat required to convert 1 kg of ice at 0°C to water at 0°C is called: (a) specific heat (b) latent heat of vaporisation (c) latent heat of fusion ✓ (d) calorimetry

Answer(c) ✓ — Latent heat of fusion is the heat needed to change 1 kg of solid to liquid at its melting point without a temperature change.

Q8. Heat transfer by radiation requires: (a) a solid medium (b) a fluid medium (c) no medium ✓ (d) both solid and fluid medium

Answer(c) ✓ — Radiation travels as electromagnetic waves and does not require any material medium, which is why the Sun's heat reaches Earth through vacuum.

Q9. If equal masses of water and copper are heated with the same amount of heat, which will have a higher temperature rise? (a) Water (b) Copper ✓ (c) Both equal (d) Cannot determine

Answer(b) ✓ — Since ΔT = Q/(mc), the substance with lower specific heat (copper, 385 J/kg·K) will show a greater temperature rise for the same heat input compared to water (4186 J/kg·K).

II. Fill in the Blanks

1. Heat is a form of energy. 2. The SI unit of heat is joule (J). 3. The specific heat capacity of water is 4186 J/(kg·K). 4. During melting, the temperature remains constant. 5. The process of converting a liquid into vapour is called vaporisation. 6. The temperature at which a solid changes into a liquid is called its melting point. 7. The heat energy absorbed or released during a change of state without any temperature change is called latent heat. 8. In a calorimeter, the principle used is heat lost by hot body = heat gained by cold body. 9. The mode of heat transfer that does not require a medium is radiation.


III. True or False

1. Heat flows from a body at higher temperature to a body at lower temperature.
AnswerTrue ✓ — Heat always flows from a region of higher temperature to a region of lower temperature until thermal equilibrium is reached.
2. All substances have the same specific heat capacity.
AnswerFalse — Correction: Different substances have different specific heat capacities. Water has the highest among common substances (4186 J/kg·K), while metals like copper have much lower values (385 J/kg·K).
3. During change of state, heat is absorbed or released without change in temperature.
AnswerTrue ✓ — This is the concept of latent heat, where energy is used to break or form intermolecular bonds rather than increase kinetic energy.
4. Conduction occurs in fluids (liquids and gases).
AnswerFalse — Correction: Conduction occurs mainly in solids. In fluids, heat transfer is primarily by convection, where the heated particles actually move and carry heat with them.
5. Black surfaces are good absorbers and good radiators of heat.
AnswerTrue ✓ — Dark, dull surfaces absorb and emit radiant heat more efficiently than light, shiny surfaces.
6. The boiling point of water decreases with increase in pressure.
AnswerFalse — Correction: The boiling point of water increases with increase in pressure. This is the principle behind a pressure cooker, where higher pressure raises the boiling point above 100°C, cooking food faster.
7. The specific heat capacity of a substance depends on its mass.
AnswerFalse — Correction: Specific heat capacity is an intrinsic property of a substance and does not depend on mass. It is defined per unit mass (per kg). The total heat capacity depends on mass, but specific heat capacity does not.
8. In convection, heated fluid rises because it becomes less dense.
AnswerTrue ✓ — When a fluid is heated, it expands and becomes less dense, causing it to rise while cooler, denser fluid sinks, creating convection currents.

IV. Match the Following

Column IColumn II
Conduction(c) Solids
Convection(b) Fluids
Radiation(a) No medium required
Calorimetry(d) Measurement of heat
Latent heat(e) Change of state
Specific heat capacity(g) Heat per unit mass per degree
Melting point(f) Solid to liquid transition temperature
Boiling point(h) Liquid to gas transition temperature

V. Answer Briefly (2-mark)

Q1. Define heat.
Answer

Heat is a form of energy that flows from a body at higher temperature to a body at lower temperature. It is measured in joules (J) in the SI system. Heat transfer continues until both bodies reach the same temperature (thermal equilibrium). Heat depends on the mass, specific heat capacity, and temperature change of the substance.

Q2. Define specific heat capacity.
Answer

Specific heat capacity is the amount of heat required to raise the temperature of 1 kg of a substance by 1 K (or 1°C). The formula is c = Q/(mΔT), and its SI unit is J/(kg·K). Every substance has a unique specific heat capacity — water has one of the highest at 4186 J/(kg·K), while metals like copper have much lower values around 385 J/(kg·K).

Q3. What is latent heat?
Answer

Latent heat is the heat energy absorbed or released during a change of state without any change in temperature. There are two types: latent heat of fusion (solid to liquid) and latent heat of vaporisation (liquid to gas). For example, ice at 0°C absorbs 3.34 × 10⁵ J/kg to become water at 0°C, and water at 100°C absorbs 2.26 × 10⁶ J/kg to become steam at 100°C.

Q4. Why is water used in car radiators?
Answer

Water has a very high specific heat capacity (4186 J/kg·K). It can absorb a large amount of heat from the engine without a significant rise in its own temperature, making it an effective coolant. Additionally, water is readily available, inexpensive, and has a high boiling point, which allows it to function efficiently in the cooling system of an engine.

Q5. What is thermal expansion?
Answer

Thermal expansion is the increase in the dimensions (length, area, or volume) of a substance when it is heated. Solids expand least, liquids more, and gases the most for the same temperature change. Everyday examples include the expansion of railway tracks in summer, the cracking of glass when hot water is poured on it, and the expansion of mercury in a thermometer.

Q6. Distinguish between heat and temperature.
Answer

Heat is the total energy of molecular motion in a substance, measured in joules (J), and depends on mass, specific heat, and temperature difference. Temperature is the measure of the average kinetic energy of molecules, measured in °C, K, or °F, and indicates how hot or cold a body is. A large iceberg at 0°C has more heat than a cup of boiling water, but the cup has a higher temperature.


VI. Answer in Detail (5-mark)

Q1. Differentiate conduction, convection, and radiation.
Answer

Heat can be transferred by three distinct modes, each operating under different conditions:

Conduction:

  • Requires a material medium (typically a solid).
  • Heat is transferred through molecular vibrations without actual movement of the particles from their positions.
  • The molecules at the hot end vibrate more vigorously and transfer energy to neighbouring molecules.
  • Example: A metal spoon left in a hot pot becomes hot at its far end.

Convection:

  • Requires a fluid medium (liquid or gas).
  • Heated fluid becomes less dense and rises, while cooler, denser fluid sinks — creating convection currents.
  • This is a bulk movement of particles carrying heat energy.
  • Example: Boiling water where hot water rises from the bottom and cool water descends; sea breeze and land breeze.

Radiation:

  • Does not require any medium — heat travels as electromagnetic waves (infrared radiation).
  • Can travel through vacuum (the Sun's heat reaches Earth through the vacuum of space).
  • Dark, rough surfaces are good absorbers and radiators; light, shiny surfaces are good reflectors.
  • Example: The warmth you feel from a campfire, or sunlight reaching Earth.
PropertyConductionConvectionRadiation
Medium requiredYes (solid)Yes (fluid)No
MechanismMolecular vibrationBulk fluid movementElectromagnetic waves
SpeedSlowModerateFast (speed of light)
ExampleMetal rod heatingSea breezeSun's heat
Q2. Explain why coastal areas have moderate climate.
Answer

Water has an exceptionally high specific heat capacity of 4186 J/(kg·K), which is significantly higher than that of land (approximately 800–1000 J/(kg·K) for soil and rock). This large difference has important consequences for coastal climates:

  • During the day, the Sun heats both land and sea. Because water requires much more heat to raise its temperature, the sea warms up slowly and keeps the air above it cool. The cool sea breeze blows towards the land, moderating the coastal temperature.
  • During the night, the land cools rapidly because of its low specific heat, while the sea retains its heat for much longer. The warm air over the sea rises and the warmer sea breeze continues to moderate the coastal temperature.
  • Seasonally, the same effect operates over longer periods. In summer, the ocean absorbs heat and keeps coastal regions cooler than inland areas. In winter, the ocean slowly releases stored heat and keeps coastal regions warmer than inland areas.
  • In contrast, inland (interior) regions experience extreme temperatures — very hot in summer and very cold in winter — because land heats up and cools down rapidly due to its low specific heat.

This moderating effect is why cities like Chennai and Mumbai have less temperature variation throughout the year compared to cities like Delhi or Nagpur.

Q3. What are the applications of specific heat capacity?
Answer

The concept of specific heat capacity has several practical applications in daily life and engineering:

1. Water as a coolant in engines and radiators: Water's high specific heat (4186 J/kg·K) allows it to absorb large amounts of heat from engines without a significant temperature rise, making it an ideal coolant in car radiators and industrial cooling systems.

2. Cooking utensils made of metals: Metals like aluminium and copper have low specific heat capacities, so they heat up quickly when placed on a flame, enabling efficient cooking.

3. Handles of cooking utensils made of wood or plastic: Wood and plastic have high specific heat capacities and are poor conductors of heat, so they do not heat up quickly and remain safe to touch even when the metal part is hot.

4. Coastal climate moderation: As explained above, the high specific heat of water moderates the climate of coastal regions compared to inland areas.

5. Use of water in hot water bottles: Water retains heat for a long time due to its high specific heat, making it suitable for hot water bottles used for warmth in winter.

6. Thermal insulation in buildings: Materials with high specific heat are used in building walls to slow down temperature changes, keeping buildings cooler in summer and warmer in winter.

Q4. Describe the method of mixture (calorimetry) to determine specific heat of a solid.
Answer

Principle: Heat lost by hot body = Heat gained by cold body (law of conservation of energy). This is the principle of calorimetry.

Procedure: 1. Weigh the empty calorimeter with stirrer and note its mass (m₁). 2. Fill the calorimeter with a known mass of water (m₂) and note the initial temperature (T₁) using a thermometer. 3. Heat a solid of known mass (m₃) to a known high temperature (T₂) using a water bath or steam heater. 4. Quickly transfer the hot solid into the calorimeter and stir the mixture continuously. 5. Note the final steady temperature (T₃) when the thermometer reading becomes constant.

Calculation
Heat lost by solid = m₃ × c₃ × (T₂ – T₃) Heat gained by water = m₂ × c_water × (T₃ – T₁) Heat gained by calorimeter = m₁ × c_cal × (T₃ – T₁)

By principle of calorimetry:

m₃ × c₃ × (T₂ – T₃) = m₂ × c_water × (T₃ – T₁) + m₁ × c_cal × (T₃ – T₁)

Solving for c₃ gives the specific heat of the solid.

Precautions:

  • The calorimeter should be insulated to prevent heat loss to the surroundings.
  • The solid should be transferred quickly to minimise heat loss to air.
  • Stirring should be continuous for uniform temperature distribution.
  • The calorimeter's heat capacity must be accounted for in the calculation.
Q5. Explain the change of state with a temperature-time graph.
Answer

A typical heating curve for ice at –20°C to steam above 100°C shows five distinct regions:

1. Ice heating (–20°C to 0°C): Temperature rises steadily as heat is used to increase the kinetic energy of ice molecules. The formula is Q = m × c_ice × ΔT, where c_ice ≈ 2100 J/(kg·K). The slope of this region depends on the specific heat of ice.

2. Ice melting (at 0°C): Temperature remains constant as heat is used to break intermolecular bonds and change ice to water. This is latent heat of fusion: Q = m × Lf, where Lf = 3.34 × 10⁵ J/kg. The flat portion of the graph represents this phase change.

3. Water heating (0°C to 100°C): Temperature rises as water absorbs heat: Q = m × c_water × ΔT, where c_water = 4186 J/(kg·K). This region has a gentler slope than ice heating because water has a higher specific heat capacity than ice.

4. Water boiling (at 100°C): Temperature again remains constant as heat converts water to steam. This is latent heat of vaporisation: Q = m × Lv, where Lv = 2.26 × 10⁶ J/kg. Note that Lv is much larger than Lf, so this flat portion is longer on the graph.

5. Steam heating (above 100°C): Temperature rises again: Q = m × c_steam × ΔT, where c_steam ≈ 2010 J/(kg·K).

The flat portions of the graph represent change of state where all energy goes into breaking bonds rather than increasing temperature. The total heat required to go from ice at –20°C to steam at 100°C+ is the sum of all five steps.


VII. Numerical Problems

Q1. Calculate the heat required to raise the temperature of 2 kg of water from 30°C to 80°C. (c = 4186 J/kg·K)
Q = mcΔT Q = 2 × 4186 × (80 – 30) Q = 2 × 4186 × 50 Q = 418,600 J ≈ 418.6 kJ
Q2. A 0.5 kg iron ball at 100°C is placed in 1 kg of water at 20°C. Find the final temperature. (c_iron = 460 J/kg·K, c_water = 4186 J/kg·K)
Answer

Heat lost by iron = Heat gained by water

0.5 × 460 × (100 – T) = 1 × 4186 × (T – 20) 230(100 – T) = 4186(T – 20) 23000 – 230T = 4186T – 83720 106720 = 4416T T = 24.16°C
Q3. Calculate the heat required to convert 1 kg of ice at 0°C to steam at 100°C.
Step 1: Melt ice at 0°C Q₁ = mLf = 1 × 3.34 × 10⁵ = 334,000 J Step 2: Heat water from 0°C to 100°C Q₂ = mcΔT = 1 × 4186 × 100 = 418,600 J Step 3: Convert water to steam at 100°C Q₃ = mLv = 1 × 2.26 × 10⁶ = 2,260,000 J Total = Q₁ + Q₂ + Q₃ = 334,000 + 418,600 + 2,260,000 = 3,012,600 J ≈ 3012.6 kJ
Q4. 500 g of copper at 200°C is dropped into 1 kg of water at 30°C. Find final temperature. (c_copper = 390 J/kg·K, c_water = 4186 J/kg·K)
0.5 × 390 × (200 – T) = 1 × 4186 × (T – 30) 195(200 – T) = 4186(T – 30) 39000 – 195T = 4186T – 125580 164580 = 4381T T = 37.57°C

Common Mistakes to Avoid

1. Confusing heat and temperature

  • ❌ Saying "the heat of the body is 100°C"
  • ✅ Heat is energy measured in joules (J); temperature is degree of hotness measured in °C or K. A large iceberg at 0°C has more heat than a cup of boiling water, but the cup has higher temperature.

2. Forgetting latent heat during state change

  • ❌ Using Q = mcΔT during melting or boiling
  • ✅ During change of state, temperature is constant. Use Q = mL (latent heat), not Q = mcΔT.

3. Wrong specific heat units

  • ❌ Writing specific heat as J/kg or J/K
  • ✅ The correct SI unit of specific heat capacity is J/(kg·K).

4. Not converting grams to kilograms

  • ❌ Using m = 500 in the formula instead of m = 0.5 kg
  • ✅ Always use SI units: mass in kg, temperature difference in K (or °C — the difference is the same).

5. Ignoring calorimeter heat capacity

  • ❌ Only calculating heat gained by water: m₂ × c_water × ΔT
  • ✅ In calorimetry problems, account for heat absorbed by the calorimeter vessel too: m₂ × c_water × ΔT + m₁ × c_cal × ΔT.

6. Confusing conduction, convection, and radiation

  • ❌ Saying "conduction occurs in air" or "radiation needs a medium"
  • ✅ Conduction: solids, molecule-to-molecule vibration. Convection: fluids (liquids/gases), bulk movement. Radiation: no medium needed, electromagnetic waves.

7. Wrong sign convention in calorimetry

  • ❌ Writing heat lost + heat gained = 0 without setting signs correctly
  • ✅ Use: Heat lost by hot body = Heat gained by cold body. Both sides are positive quantities.

Exam Checklist

  • [ ] Heat vs temperature difference memorized
  • [ ] Specific heat formula Q = mcΔT and numerical problems practiced
  • [ ] Latent heat of fusion and vaporisation definitions and values memorized (Lf = 3.34 × 10⁵ J/kg, Lv = 2.26 × 10⁶ J/kg)
  • [ ] Calorimetry principle: heat lost = heat gained
  • [ ] Three modes of heat transfer and examples
  • [ ] Temperature conversion formulas (K = °C + 273.15, °F = (9/5)°C + 32)
  • [ ] Heating curve interpretation (flat portions = state change)
  • [ ] Numerical problems on specific heat and latent heat practiced
  • [ ] Always convert mass to kg before using Q = mcΔT
  • [ ] Know that boiling point increases with pressure (pressure cooker principle)
  • [ ] Dull/black surfaces absorb and radiate heat better; shiny surfaces reflect heat
  • [ ] Coastal climate moderation explained using specific heat of water

Internal Links

  • [Chapter 7 Guide — Heat](/school/tamil-nadu-state-board/class/9/science/heat)
  • [All Class 9 Science Solutions](/school/tamil-nadu-state-board/class/9/science/solutions)
  • [Class 9 Science Subject Guide](/school/tamil-nadu-state-board/class/9/science)

Frequently Asked Questions

The amount of heat energy required to raise the temperature of 1 kg of a substance by 1°C (or 1 K). Formula: Q = mcΔT. Unit: J/(kg·K). Water has the highest specific heat among common substances (4186 J/kg·K).