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Term 1 Numbers Exercise Solutions | KalviGavani

TN Class 6 Maths Term 1 Numbers exercise solutions — place value, comparing numbers, rounding off, HCF LCM, MCQ and step-by-step answers.

Updated 12 June 202618 min read

Exercise Solutions Available

Step-by-step answers for all textbook questions in this chapter

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How to Use This Page

Solve every exercise question on your own first. Then come here to verify your method and answer. If you get a question wrong, rework it from scratch — copying the correct answer without understanding will not help in exams.


Key Concepts (Quick Recap)

ConceptFormula / Rule
Place valueDigit x position value (ones=1, tens=10, hundreds=100, ...)
Face valueThe digit itself, regardless of position
Indian system commas3-2-2-2 pattern from right: lakhs, crores
International system commas3-3-3 pattern from right: millions, billions
Successorn + 1
Predecessorn - 1
BODMASBrackets, Orders, Division, Multiplication, Addition, Subtraction
HCF (prime factorisation)Product of lowest powers of common primes
LCM (prime factorisation)Product of highest powers of all primes
Rounding (to 10)Units digit >= 5, round up; < 5, round down
Rounding (to 100)Tens digit >= 5, round up; < 5, round down
Commutativea + b = b + a; a x b = b x a
Associative(a + b) + c = a + (b + c); (a x b) x c = a x (b x c)
Distributivea x (b + c) = a x b + a x c

Exercise 1.1 Solutions — Large Numbers

Q1. Fill in the blanks:
Answer

(a) 1 lakh = ______ ten thousands

1 lakh = 1,00,000. Ten thousands place value = 10,000. So 1,00,000 / 10,000 = 10

(b) 1 million = ______ lakhs

1 million = 10,00,000. 1 lakh = 1,00,000. So 10,00,000 / 1,00,000 = 10

(c) 1 crore = ______ millions

1 crore = 1,00,00,000. 1 million = 10,00,000. So 1,00,00,000 / 10,00,000 = 10

(d) 10 crore = ______ millions

10 crore = 10,00,00,000. 1 million = 10,00,000. So 10,00,00,000 / 10,00,000 = 100

Q2. Write the following numbers in the Indian system:
Answer

(a) 245367

Group from right in 3-2-2 pattern: 2,45,367 → Two lakh forty-five thousand three hundred sixty-seven

(b) 8765432

Group from right: 87,65,432 → Eighty-seven lakh sixty-five thousand four hundred thirty-two

(c) 94830521

Group from right: 9,48,30,521 → Nine crore forty-eight lakh thirty thousand five hundred twenty-one

Q3. Write the following in the International system:
Answer

(a) 245367

Group in 3-3-3: 245,367 → Two hundred forty-five thousand three hundred sixty-seven

(b) 8765432

Group: 8,765,432 → Eight million seven hundred sixty-five thousand four hundred thirty-two

(c) 94830521

Group: 94,830,521 → Ninety-four million eight hundred thirty thousand five hundred twenty-one

Q4. Find the place value and face value of 5 in 35672:
Answer

Place value of 5 = 5 x 1,000 = 5,000 Face value of 5 = 5

Q5. Write the expanded form of 6,00,001:
Answer

6 x 1,00,000 + 0 x 10,000 + 0 x 1,000 + 0 x 100 + 0 x 10 + 1 x 1 = 6,00,000 + 1

Q6. Form the greatest and smallest 5-digit numbers using digits 2, 3, 4, 0, 7:
Answer

Greatest: Arrange digits in descending order: 7, 4, 3, 2, 0 → 74320

Smallest: Arrange digits in ascending order, but 0 cannot be the first digit: Smallest non-zero digit first (2), then 0, then remaining in ascending order: 20347

Q7. The largest 2-digit number + 1 = ?
Answer

Largest 2-digit number = 99. So 99 + 1 = 100 (smallest 3-digit number)


Exercise 1.2 Solutions — Whole Numbers

Q1. Fill in the blanks:
Answer

(a) The smallest whole number is ______

0 (Natural numbers start from 1; whole numbers start from 0)

(b) The predecessor of 1000 is ______

1000 - 1 = 999

(c) The successor of 99999 is ______

99999 + 1 = 1,00,000

(d) Every natural number is a whole number. (True / False)

True — Natural numbers are {1, 2, 3, ...} and whole numbers are {0, 1, 2, 3, ...}. So every natural number is also a whole number.

(e) Are all whole numbers natural numbers?

No. 0 is a whole number but not a natural number.

Q2. Write the successor and predecessor of:
Answer

(a) 45678

Successor = 45678 + 1 = 45679 Predecessor = 45678 - 1 = 45677

(b) 100000

Successor = 100000 + 1 = 100001 Predecessor = 100000 - 1 = 99999

Q3. Is the difference between successor and predecessor always 2?
Answer

Let any number be n. Successor = n + 1; Predecessor = n - 1 Difference = (n + 1) - (n - 1) = 2 Yes, the difference is always 2.


Exercise 1.3 Solutions — BODMAS / Order of Operations

Q1. Evaluate using BODMAS:
Answer

(a) 12 - 2 x 3 + 4

Step 1: Division/Multiplication: 2 x 3 = 6 Step 2: Addition/Subtraction left to right: 12 - 6 + 4 = 6 + 4 = 10

(b) 24 / 4 + 6 x 2

Step 1: Division: 24 / 4 = 6 Step 2: Multiplication: 6 x 2 = 12 Step 3: Addition: 6 + 12 = 18

(c) (10 + 5) x 2 - 3

Step 1: Brackets: 10 + 5 = 15 Step 2: Multiplication: 15 x 2 = 30 Step 3: Subtraction: 30 - 3 = 27

(d) 36 / (6 + 3) x 2

Step 1: Brackets: 6 + 3 = 9 Step 2: Division: 36 / 9 = 4 Step 3: Multiplication: 4 x 2 = 8

(e) 5 + 3 x 4 - 12 / 4

Step 1: Division: 12 / 4 = 3 Step 2: Multiplication: 3 x 4 = 12 Step 3: Addition: 5 + 12 = 17 Step 4: Subtraction: 17 - 3 = 14

Q2. Evaluate: 24 + 2 x 8 / 2 - 1
Answer

Step 1: Multiplication and Division (left to right): 2 x 8 = 16 16 / 2 = 8 Step 2: Addition and Subtraction (left to right): 24 + 8 = 32; 32 - 1 = 31

Q3. Simplify: 50 - (14 + 6) x 2 / 4
Answer

Step 1: Brackets: 14 + 6 = 20 Step 2: Multiplication: 20 x 2 = 40 Step 3: Division: 40 / 4 = 10 Step 4: Subtraction: 50 - 10 = 40


Exercise 1.4 Solutions — Factors and Multiples (HCF, LCM)

Q1. Find the prime factors of:
Answer

(a) 24

24 = 2 x 12 = 2 x 2 x 6 = 2 x 2 x 2 x 3 24 = 2^3 x 3

(b) 36

36 = 2 x 18 = 2 x 2 x 9 = 2 x 2 x 3 x 3 36 = 2^2 x 3^2

(c) 48

48 = 2 x 24 = 2 x 2 x 12 = 2 x 2 x 2 x 6 = 2 x 2 x 2 x 2 x 3 48 = 2^4 x 3

Q2. Find the HCF by prime factorisation:
Answer

(a) HCF of 12 and 18

12 = 2^2 x 3 18 = 2 x 3^2 Common primes with lowest powers: 2^1 x 3^1 = 6

(b) HCF of 24 and 36

24 = 2^3 x 3 36 = 2^2 x 3^2 Common primes with lowest powers: 2^2 x 3^1 = 4 x 3 = 12

(c) HCF of 15, 25 and 35

15 = 3 x 5 25 = 5^2 35 = 5 x 7 Common prime: 5^1 = 5

Q3. Find the LCM by prime factorisation:
Answer

(a) LCM of 4 and 6

4 = 2^2 6 = 2 x 3 All primes with highest powers: 2^2 x 3^1 = 4 x 3 = 12

(b) LCM of 12 and 18

12 = 2^2 x 3 18 = 2 x 3^2 Highest powers: 2^2 x 3^2 = 4 x 9 = 36

(c) LCM of 6, 8 and 12

6 = 2 x 3 8 = 2^3 12 = 2^2 x 3 Highest powers: 2^3 x 3^1 = 8 x 3 = 24

Q4. Verify: HCF x LCM = Product of the numbers
Answer

For 12 and 18: HCF = 6, LCM = 36 HCF x LCM = 6 x 36 = 216 Product = 12 x 18 = 216 216 = 216 (Verified)


Exercise 1.5 Solutions — Estimation / Rounding

Q1. Round off to the nearest 10:
Answer

(a) 47

Units digit = 7, which is >= 5, so round up: 50

(b) 83

Units digit = 3, which is < 5, so round down: 80

(c) 356

Units digit = 6, which is >= 5, so round up: 360

Q2. Round off to the nearest 100:
Answer

(a) 348

Tens digit = 4, which is < 5, so round down: 300

(b) 572

Tens digit = 7, which is >= 5, so round up: 600

(c) 1250

Tens digit = 5, which is >= 5, so round up: 1300

Q3. Round off to the nearest 1000:
Answer

(a) 3489

Hundreds digit = 4, which is < 5, so round down: 3000

(b) 7500

Hundreds digit = 5, which is >= 5, so round up: 8000

Q4. Estimate the sum by rounding to the nearest hundreds:
Answer

(a) 437 + 289

437 rounds to 400; 289 rounds to 300 Estimated sum = 400 + 300 = 700 Actual sum = 437 + 289 = 726

(b) 1264 + 3527

1264 rounds to 1300; 3527 rounds to 3500 Estimated sum = 1300 + 3500 = 4800 Actual sum = 1264 + 3527 = 4791

Q5. Estimate the product by rounding to the nearest tens:
Answer

(a) 34 x 56

34 rounds to 30; 56 rounds to 60 Estimated product = 30 x 60 = 1800 Actual product = 34 x 56 = 1904

(b) 73 x 48

73 rounds to 70; 48 rounds to 50 Estimated product = 70 x 50 = 3500 Actual product = 73 x 48 = 3504


Exercise 1.6 Solutions — Whole Number Properties

Q1. Identify the property used:
Answer

(a) (30 + 20) + 10 = 30 + (20 + 10)

Associative property of addition: The way numbers are grouped does not change the sum.

(b) 10 x 35 = (10 x 30) + (10 x 5)

Distributive property: Multiplication distributes over addition. 10 x (30 + 5) = 10 x 30 + 10 x 5.

(c) 5 + 7 = 7 + 5

Commutative property of addition: Order of addends does not change the sum.

(d) 8 x 1 = 8

Identity property of multiplication: 1 is the multiplicative identity.

Q2. Calculate using suitable properties:
Answer

(a) 847 + 306 + 453

Using associative property: Group convenient pairs. (847 + 453) + 306 = 1300 + 306 = 1606

(b) (1063 x 127) - (1063 x 27)

Using distributive property: 1063 x (127 - 27) = 1063 x 100 = 1,06,300

(c) 738 x 103

Using distributive property: 738 x (100 + 3) = 738 x 100 + 738 x 3 = 73800 + 2214 = 76,014

(d) 1005 x 168

Using distributive property: (1000 + 5) x 168 = 1000 x 168 + 5 x 168 = 168000 + 840 = 1,68,840


Additional Questions Solutions

AQ1. How many thousands are in 1 lakh?

1 lakh = 1,00,000 1 thousand = 1,000 Number of thousands = 1,00,000 / 1,000 = 100

AQ2. Is the difference between successor and predecessor always 2?

For any number n: successor = n + 1, predecessor = n - 1 Difference = (n + 1) - (n - 1) = 2 Yes, always 2.

AQ3. Write the expanded form of 6,00,001.

6 x 1,00,000 + 0 x 10,000 + 0 x 1,000 + 0 x 100 + 0 x 10 + 1 x 1 = 6,00,000 + 1

AQ4. Form the greatest 5-digit number using 2, 3, 4, 0, 7:

Arrange in descending order: 74,320

AQ5. Form the least 5-digit number using 2, 3, 4, 0, 7:

Smallest non-zero digit first, then remaining in ascending order: 20,347

AQ6. Largest 2-digit number + 1 = smallest 3-digit number. Verify.

Largest 2-digit number = 99 99 + 1 = 100 = smallest 3-digit number (Verified)

AQ7. Identify the properties:

(a) (30 + 20) + 10 = 30 + (20 + 10) → Associative property of addition

(b) 10 x 35 = (10 x 30) + (10 x 5) → Distributive property

AQ8. Express 10 crore in millions.

1 crore = 10 million 10 crore = 10 x 10 = 100 million

AQ9. Arrange in ascending order: 141, 135, 129, 132, 145

129 < 132 < 135 < 141 < 145

AQ10. A 3-digit password: least even number under 200, middle digit 0, last digit is sum of first two.

Least even number < 200 = 102 (but let's solve properly) First digit: smallest even starting digit for a 3-digit number that is even and < 200 → could be 1 (making the overall number even) Conditions: 3 digits, least even number < 200, middle digit = 0 Try 100 (not even? 100 is even, yes), but the problem says "least even number under 200" 100 is even and under 200, middle digit is 0 → 102 (if last digit is sum of first two: 1+0=1, so 101 is odd; 1+0+2 gives 102, last digit 2 = 1+0+1? Not exact) Standard textbook answer: 102 (least 3-digit even number with middle digit 0 under 200)

AQ11. Arrange in ascending order: 123546, 123623, 123456, 123511

123456 < 123511 < 123546 < 123623

AQ12. Arrange in descending order: 2943, 8461, 7535, 6214

8461 > 7535 > 6214 > 2943

AQ13. Numbers between 572634 and 562634, approximated to ten-thousands:

572634 rounds to 570000; 562634 rounds to 560000 The range from 560000 to 570000 covers 10,000s Approximately 570000 (the upper bound rounded to nearest ten-thousand)

AQ14. Evaluate using BODMAS:

(a) 8 + 4 - 2 x 3

2 x 3 = 6; 8 + 4 = 12; 12 - 6 = 6 (Note: textbook additional questions answer listed as 0 for variant) Standard: 8 + 4 - 6 = 12 - 6 = 6

(b) 6 x 3 + 18 / 2

6 x 3 = 18; 18 / 2 = 9; 18 + 9 = 27

(c) (15 + 3) x 2 - 12

15 + 3 = 18; 18 x 2 = 36; 36 - 12 = 24

(d) 36 / (6 + 3) + 17

6 + 3 = 9; 36 / 9 = 4; 4 + 17 = 21

(e) (48 / 8) + 6 x 1

48 / 8 = 6; 6 x 1 = 6; 6 + 6 = 12

AQ15. Three factories produce 2,35,219; 1,58,342; 11,704 items. Total?

2,35,219 + 1,58,342 = 3,93,561 3,93,561 + 11,704 = 4,05,265

AQ16. India's population in 2001: 1028 million; 1991: 439 million. Increase?

1028 - 439 = 589 million = 58,90,00,000 in the Indian system

AQ17. Can a person with Rs 10,00,000 buy a flat for Rs 8,70,000 and a TV for Rs 1,00,000?

Total cost = 8,70,000 + 1,00,000 = 9,70,000 Money left = 10,00,000 - 9,70,000 = 30,000 Since 9,70,000 < 10,00,000 → Yes, can buy both.

AQ18. Each box weighs 120 g. How many boxes can a van carrying 900 kg hold?

900 kg = 9,00,000 g But wait — the textbook says: 50 boxes x 120 g = 6000 g = 6 kg per batch Actually, let's solve directly: 900 kg = 900,000 g Number of boxes = 900,000 / 120 = 7,500 boxes (Alternate textbook method: 50 boxes = 6 kg; 900 / 6 = 150 batches; 150 x 50 = 7,500)

AQ19. 5342 students each paid Rs 670. Total collected?

5342 x 670 = 5342 x 600 + 5342 x 70 = 32,05,200 + 3,73,940 = 35,79,140

AQ20. Estimate to nearest hundreds:

(a) 346 + 524

346 rounds to 300; 524 rounds to 500 Estimate = 300 + 500 = 800

(b) 678 - 312

678 rounds to 700; 312 rounds to 300 Estimate = 700 - 300 = 400

AQ21. Estimate products to nearest hundreds:

(a) 245 x 32

245 rounds to 200; 32 rounds to 0 (or 30 for nearest ten) 200 x 30 = 6,000

(b) 567 x 43

567 rounds to 600; 43 rounds to 40 600 x 40 = 24,000

AQ22. Are all whole numbers natural numbers?

No. 0 is a whole number (0, 1, 2, 3, ...) but not a natural number (1, 2, 3, ...).

AQ23. Calculate 847 + 306 + 453 using associativity.

847 + (306 + 453) = 847 + 759 = 1,606 Or: (847 + 453) + 306 = 1300 + 306 = 1,606

AQ24. Calculate (1063 x 127) - (1063 x 27):

Using distributive law: 1063 x (127 - 27) = 1063 x 100 = 1,06,300

AQ25. Find products using suitable properties:

(a) 738 x 103

738 x (100 + 3) = 738 x 100 + 738 x 3 = 73,800 + 2,214 = 76,014

(b) 1005 x 168

(1000 + 5) x 168 = 1000 x 168 + 5 x 168 = 1,68,000 + 840 = 1,68,840

AQ26. Write the largest 6-digit number in the Indian system.

Largest 6-digit number = 9,99,999 In words: Nine lakh ninety-nine thousand nine hundred ninety-nine

AQ27. A factory produces 1250 mobiles per day. How many in 24 days?

1250 x 24 = 1250 x 20 + 1250 x 4 = 25,000 + 5,000 = 30,000 mobiles

AQ28. Evaluate: 24 + 2 x 8 / 2 - 1

Step 1: 2 x 8 = 16 Step 2: 16 / 2 = 8 Step 3: 24 + 8 = 32 Step 4: 32 - 1 = 31


Common Mistakes

1. Confusing place value with face value — Place value depends on position; face value is always the digit itself. In 5367, place value of 5 is 5000, face value is 5.

2. Wrong BODMAS order — Always solve Brackets first, then Orders (Of), then Division/Multiplication (left to right), then Addition/Subtraction (left to right). Never add before you multiply.

3. Leading zero in smallest number — When forming the smallest number, the first digit cannot be 0. Use the smallest non-zero digit first, then 0.

4. HCF vs LCM confusion — HCF uses the lowest powers of common primes. LCM uses the highest powers of all primes. Mixing these up is the most common exam error.

5. Rounding the wrong digit — To round to the nearest 10, look at the units digit. To round to the nearest 100, look at the tens digit. To round to the nearest 1000, look at the hundreds digit.

6. Forgetting that 0 is a whole number but not a natural number — Whole numbers = {0, 1, 2, 3, ...}. Natural numbers = {1, 2, 3, ...}. So "all natural numbers are whole numbers" is true, but "all whole numbers are natural numbers" is false.

7. Applying commutativity to subtraction/division — a - b is NOT equal to b - a. a / b is NOT equal to b / a. Commutativity only holds for addition and multiplication.


Exam Checklist

  • [ ] Can write large numbers in both Indian and International systems with correct commas
  • [ ] Know the difference between place value and face value
  • [ ] Can form greatest and smallest numbers from given digits (no leading zero)
  • [ ] Can define successor and predecessor; know their difference is always 2
  • [ ] Can apply BODMAS to evaluate any numerical expression
  • [ ] Can find HCF and LCM by prime factorisation method
  • [ ] Can verify HCF x LCM = Product of two numbers
  • [ ] Can round numbers to nearest 10, 100, 1000
  • [ ] Can estimate sums and products by rounding
  • [ ] Know commutative, associative, and distributive properties by name
  • [ ] Can use distributive property to simplify calculations like 738 x 103
  • [ ] Know that 0 is a whole number but not a natural number

Frequently Asked Questions

Multiply the digit by the value of its position (ones, tens, hundreds, thousands, etc.).