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Introduction to Algebra Exercise Solutions | KalviGavani

TN Class 6 Maths Introduction to Algebra exercise solutions — variables expressions equations patterns, MCQ and step-by-step answers.

Updated 12 June 202617 min read

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Step-by-step answers for all textbook questions in this chapter

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Introduction to Algebra — Exercise Solutions

How to Use This Page

This page provides step-by-step solutions for every exercise in Class 6 Maths Term 1 Chapter 2: Introduction to Algebra (Samacheer Kalvi / TN State Board). Work through each problem on your own first, then check your working against the solutions here. Every equation is solved with full working shown — transposing terms, simplifying, and verifying the answer.


Key Concepts (Quick Recap)

Variables

A variable is a letter (x, y, n, p, etc.) that stands for an unknown value. Variables allow us to write general rules instead of listing every specific number.

Algebraic Expressions

An algebraic expression combines numbers, variables, and operations.

  • Term: A single number, variable, or product of both (e.g., 3x, 5, -2y).
  • Coefficient: The number multiplied by the variable in a term (in 3x, the coefficient is 3).
  • Constant: A term with no variable (e.g., 5 in 3x + 5).
  • Like terms: Terms with the same variable part (3x and 7x are like terms).
  • Unlike terms: Terms with different variable parts (3x and 5y are unlike terms).

Equations

An equation has an equals sign (=) and can be solved.

  • LHS = left-hand side, RHS = right-hand side.
  • The balancing method: whatever you do to one side, do the same to the other.
  • Inverse operations: addition undoes subtraction; multiplication undoes division.

Special Identities

  • Additive identity: Adding 0 to any number gives the same number. a + 0 = a.
  • Multiplicative identity: Multiplying any number by 1 gives the same number. a x 1 = a.

Exercise 2.1 — Variables and Patterns

Understanding Variables and Matchstick Patterns

Q1. The teacher asks the class to form patterns using matchsticks. The letter L needs 2 matchsticks. How many matchsticks are needed to form n such letters?

Solution
  • 1 letter L needs 2 matchsticks
  • 2 letters L need 4 matchsticks
  • 3 letters L need 6 matchsticks
  • Pattern: matchsticks = 2 x n
Answer2n matchsticks

Q2. The letter T needs 2 matchsticks. Write the rule for the number of matchsticks needed to form n such letters.

Solution
  • 1 letter T = 2 sticks
  • 2 letters T = 4 sticks
  • 3 letters T = 6 sticks
  • Each T adds 2 more sticks
Answer2n matchsticks

Q3. The letter C needs 3 matchsticks. Write the rule for n such letters.

Solution
  • 1 C = 3 sticks -> 3 x 1 = 3
  • 2 C = 6 sticks -> 3 x 2 = 6
  • 3 C = 9 sticks -> 3 x 3 = 9
Answer3n matchsticks

Q4. The letter Z needs 3 matchsticks. Write the rule.

SolutionSame reasoning as letter C.
Answer3n matchsticks

Q5. The letter V needs 2 matchsticks. The letter E needs 4 matchsticks. The letter N needs 3 matchsticks. Write rules for each.

Solution
LetterSticks per letterRule
V22n
E44n
N33n
AnswerV: 2n, E: 4n, N: 3n

Q6. Observe the pattern: 4, 7, 10, 13, ... Find the general term.

Solution
  • 1st term: 4 = 3(1) + 1
  • 2nd term: 7 = 3(2) + 1
  • 3rd term: 10 = 3(3) + 1
  • 4th term: 13 = 3(4) + 1

The general term is 3n + 1, where n is the position number.

Answer3n + 1

Q7. Observe the pattern: 1, 4, 9, 16, 25, ... Find the general term.

Solution
  • 1st term: 1 = 1 squared
  • 2nd term: 4 = 2 squared
  • 3rd term: 9 = 3 squared
  • 4th term: 16 = 4 squared
  • 5th term: 25 = 5 squared

The general term is n squared, where n is the position number.

Answern squared (or n x n)

Q8. Observe the pattern: 2, 5, 8, 11, ... Find the general term.

Solution
  • 1st term: 2 = 3(1) - 1
  • 2nd term: 5 = 3(2) - 1
  • 3rd term: 8 = 3(3) - 1
  • 4th term: 11 = 3(4) - 1
Answer3n - 1

Q9. Meena's age is written as 3 years more than twice Beena's age. If Beena's age is b, express Meena's age.

SolutionTwice Beena's age = 2b. Three more than that = 2b + 3.
Answer2b + 3

Q10. A cuboid has length l, breadth b, and height h. Write the formula for its volume.

SolutionVolume of a cuboid = length x breadth x height
AnswerV = l x b x h = lbh

Exercise 2.2 — Algebraic Expressions and Equations

Terms, Coefficients, and Like/Unlike Terms

Q1. Identify the terms and coefficients in: 5x squared + 3xy - 7

Solution
TermCoefficientType
5x sq.5Variable term
3xy3Variable term
-7--Constant term
AnswerTerms: 5x squared, 3xy, -7. Coefficients: 5 (of x squared), 3 (of xy).

Q2. Identify like and unlike terms among: 3x, 5y, 7x, -2y, 4x squared

Solution
  • Like terms (same variable part): 3x and 7x (both have x); 5y and -2y (both have y)
  • Unlike terms (different variable part): any term with x vs any term with y vs 4x squared
AnswerLike terms: {3x, 7x} and {5y, -2y}. Unlike: 4x squared is unlike all others.

Q3. Classify the following as monomial, binomial, or trinomial:

(i) 3x (ii) 2x + 5 (iii) 4a - 3b + 7

Solution
  • (i) 3x -> 1 term -> Monomial
  • (ii) 2x + 5 -> 2 terms -> Binomial
  • (iii) 4a - 3b + 7 -> 3 terms -> Trinomial

Forming Expressions from Verbal Statements

Q4. Express algebraically:

(i) t added to 100 (ii) 4 less than 9 times y (iii) 3 times x added to 7 (iv) 10 subtracted from m

Solution

(i) t added to 100 -> t + 100 (ii) 4 less than 9 times y -> 9y - 4 -> 9y - 4 (iii) 3 times x added to 7 -> 3x + 7 -> 3x + 7 (iv) 10 subtracted from m -> m - 10 -> m - 10


Q5. Express verbally:

(a) 7x + 18 (b) 4x divided by 3

Solution

(a) 7x + 18 -> 18 added to 7 times x (or: the sum of 7 times a number and 18) (b) 4x divided by 3 -> 4 times x divided by 3 (or: one-third of 4 times a number)


Q6. Suja's age is a. What will be her age 6 years from now?

SolutionCurrent age = a. After 6 years, her age = a + 6.
Answera + 6

Q7. The price of an orange is b rupees. The price of an apple is 50 rupees more than the orange. Express the apple's price.

SolutionApple price = orange price + 50 = b + 50.
Answerb + 50

Q8. In a class, n students like ice cream. What does 2n mean?

Solution2n = 2 x n. It means double the number of students who like ice cream. If n = 10 students like ice cream, then 2n = 20 represents twice that count.
Answer2n means double the number of students who like ice cream.

Q9. The price of oil per litre is 5 rupees more than 3 times the price of rice per kg. If rice costs p rupees per kg, express the oil price.

Solution3 times the price of rice = 3p. Five more than that = 3p + 5.
Answer3p + 5

Q10. Express algebraically:

(a) y divided by r (b) 10 minus 2 times x

Solution

(a) y divided by r -> y/r (or y divided by r) (b) 10 minus 2 times x -> 10 - 2x -> 10 - 2x


Q11. Rajini's father is 5 years more than 3 times Rajini's age. If Rajini's age is x, write the father's age.

Solution3 times Rajini's age = 3x. Five more = 3x + 5.
Answer3x + 5

Q12. Ramu is 3 years younger than Mathu. If Mathu's age is m, express Ramu's age.

SolutionRamu = Mathu's age - 3 = m - 3.
Answerm - 3

Q13. A square gift box has side p. What length of tape is needed to go around all four sides?

SolutionPerimeter of a square = 4 x side = 4p.
Answer4p

Q14. Find the number of matchsticks needed to form the letter R using the pattern. If one R needs 6 sticks, write the rule for n such letters.

Solution
  • 1 R = 6 sticks
  • 2 R = 12 sticks
  • n R = 6n sticks
Answer6n

Q15. Find the rule for the letter S made of 5 matchsticks each.

Solution
  • 1 S = 5 sticks
  • n S = 5n sticks
Answer5n

Q16. A pattern of triangles is made. Each triangle needs 3 matchsticks, but when arranged in a row sharing a side, the pattern is: 1 triangle = 3 sticks, 2 triangles = 5 sticks, 3 triangles = 7 sticks. Find the general rule.

Solution
TrianglesSticksPattern
132(1) + 1
252(2) + 1
372(3) + 1
Answer2p + 1 (or 2n + 1, where n is the number of triangles)

Exercise 2.3 — Solving Simple Equations

Solving by Balancing Method

Q1. Solve: m + 10 = 16

Solution (Balancing Method)

Step 1: m + 10 = 16

Step 2: Subtract 10 from both sides

m + 10 - 10 = 16 - 10

m = 6

Verification: 6 + 10 = 16 (LHS = RHS)

Answerm = 6

Q2. Solve: 3x + 10 = 25

Solution (Balancing Method)

Step 1: 3x + 10 = 25

Step 2: Subtract 10 from both sides

3x + 10 - 10 = 25 - 10

3x = 15

Step 3: Divide both sides by 3

3x / 3 = 15 / 3

x = 5

Verification: 3(5) + 10 = 15 + 10 = 25 (LHS = RHS)

Answerx = 5

Q3. Solve: z / 3 = 4

Solution

Step 1: z / 3 = 4

Step 2: Multiply both sides by 3

z = 4 x 3

z = 12

Verification: 12 / 3 = 4 (LHS = RHS)

Answerz = 12

Q4. Solve: 7y - 20 = 99

Solution (Balancing Method)

Step 1: 7y - 20 = 99

Step 2: Add 20 to both sides

7y - 20 + 20 = 99 + 20

7y = 119

Step 3: Divide both sides by 7

7y / 7 = 119 / 7

y = 17

Verification: 7(17) - 20 = 119 - 20 = 99 (LHS = RHS)

Answery = 17

Q5. Solve: 2x + 9 = 301

Solution (Balancing Method)

Step 1: 2x + 9 = 301

Step 2: Subtract 9 from both sides

2x + 9 - 9 = 301 - 9

2x = 292

Step 3: Divide both sides by 2

2x / 2 = 292 / 2

x = 146

Verification: 2(146) + 9 = 292 + 9 = 301 (LHS = RHS)

Answerx = 146

Q6. Solve: p - 5 = 12

Solution

Step 1: p - 5 = 12

Step 2: Add 5 to both sides

p = 12 + 5

p = 17

Verification: 17 - 5 = 12 (LHS = RHS)

Answerp = 17

Q7. Solve: y / 5 = 10

Solution

Step 1: y / 5 = 10

Step 2: Multiply both sides by 5

y = 10 x 5

y = 50

Verification: 50 / 5 = 10 (LHS = RHS)

Answery = 50

Q8. Solve: 4x - 3 = 17

Solution

Step 1: 4x - 3 = 17

Step 2: Add 3 to both sides

4x = 17 + 3

4x = 20

Step 3: Divide both sides by 4

x = 20 / 4

x = 5

Verification: 4(5) - 3 = 20 - 3 = 17 (LHS = RHS)

Answerx = 5

Q9. Solve: n + 7 = 20

Solution

Step 1: n + 7 = 20

Step 2: Subtract 7 from both sides

n = 20 - 7

n = 13

Verification: 13 + 7 = 20 (LHS = RHS)

Answern = 13

Q10. Solve: 5a - 8 = 22

Solution

Step 1: 5a - 8 = 22

Step 2: Add 8 to both sides

5a = 22 + 8

5a = 30

Step 3: Divide both sides by 5

a = 30 / 5

a = 6

Verification: 5(6) - 8 = 30 - 8 = 22 (LHS = RHS)

Answera = 6

Additional Questions

AQ1. What is the additive identity?

SolutionThe additive identity is the number which, when added to any number, gives the same number.

a + 0 = a for all a.

Answer0 is the additive identity.

AQ2. What is the multiplicative identity?

SolutionThe multiplicative identity is the number which, when multiplied by any number, gives the same number.

a x 1 = a for all a.

Answer1 is the multiplicative identity.

AQ3. Express algebraically:

(i) t added to 100 (ii) 4 less than 9 times y

Solution

(i) t + 100 (ii) 9y - 4

Answer(i) t + 100, (ii) 9y - 4

AQ4. Matchstick patterns: Letter R needs 6 sticks, Letter S needs 5 sticks. Write the rules.

Solution
  • n letters R need 6n matchsticks
  • n letters S need 5n matchsticks
AnswerR: 6x, S: 5y (or 6n and 5n respectively)

AQ5. Suja's age is a. What will be her age 6 years from now?

Answera + 6

AQ6. The price of an apple is 50 rupees more than the price of an orange. If the orange costs b rupees, what is the apple's price?

Answerb + 50

AQ7. In a class, n students like ice cream. What does 2n mean?

Answer2n means double the number of students who like ice cream.

AQ8. The price of oil per litre is 5 rupees more than 3 times the price of rice per kg. If rice costs p rupees, express the oil price.

Answer3p + 5

AQ9. Solve: m + 10 = 16

Solution

m + 10 = 16

m = 16 - 10

m = 6

Verification: 6 + 10 = 16 (LHS = RHS)

Answerm = 6

AQ10. Express algebraically:

(a) y divided by r (b) 10 minus 2 times x

Solution

(a) y divided by r -> y/r (b) 10 minus 2 times x -> 10 - 2x


AQ11. Express verbally:

(a) 7x + 18 (b) 4x divided by 3

Solution

(a) 7x + 18 -> 18 added to 7 times x (b) 4x divided by 3 -> 4 times x divided by 3


AQ12. Rajini's father is 5 years more than 3 times Rajini's age. If Rajini's age is x, write the father's age.

Answer3x + 5

AQ13. A triangular matchstick pattern follows the rule: 1 triangle = 3 sticks, 2 triangles = 5 sticks, 3 triangles = 7 sticks. Find the general rule.

Solution
Triangles (p)SticksPattern
132(1)+1
252(2)+1
372(3)+1
Answer2p + 1

AQ14. Solve: 3x + 10 = 25

Solution

3x + 10 = 25

3x = 25 - 10

3x = 15

x = 15 / 3

x = 5

Verification: 3(5) + 10 = 25 (LHS = RHS)

Answerx = 5

AQ15. Solve: z / 3 = 4

Solution

z / 3 = 4

z = 4 x 3

z = 12

Verification: 12 / 3 = 4 (LHS = RHS)

Answerz = 12

AQ16. Ramu is 3 years younger than Mathu. If Mathu's age is m, express Ramu's age.

Answerm - 3

AQ17. Tape needed for a square gift box with side p, going once around all four sides.

SolutionPerimeter of square = 4 x side = 4p.
Answer4p

AQ18. Solve: 7y - 20 = 99

Solution

7y - 20 = 99

7y = 99 + 20

7y = 119

y = 119 / 7

y = 17

Verification: 7(17) - 20 = 119 - 20 = 99 (LHS = RHS)

Answery = 17

AQ19. Solve: 2x + 9 = 301

Solution

2x + 9 = 301

2x = 301 - 9

2x = 292

x = 292 / 2

x = 146

Verification: 2(146) + 9 = 292 + 9 = 301 (LHS = RHS)

Answerx = 146

AQ20. Aarthi is 3 years younger than Harini. The sum of their ages is 23. Find Harini's age.

Solution

Let Harini's age = h.

Then Aarthi's age = h - 3.

Sum of ages = h + (h - 3) = 23

2h - 3 = 23

2h = 23 + 3

2h = 26

h = 26 / 2

h = 13

Verification: Harini = 13, Aarthi = 13 - 3 = 10. Sum = 13 + 10 = 23 (LHS = RHS)

AnswerHarini is 13 years old.

Common Mistakes

1. Confusing "less than" with subtraction order: "4 less than 9y" means 9y - 4, not 4 - 9y. The quantity after "less than" comes first.

2. Forgetting to do the same operation on both sides: When solving 3x + 5 = 20, some students only subtract 5 from the left side. Always balance -- subtract 5 from both sides.

3. Mixing up expressions and equations: An expression like 3x + 5 cannot be "solved" -- it has no equals sign. Only equations (with =) can be solved for a value.

4. Sign errors when transposing: When moving a term to the other side, its sign changes. +5 becomes -5, and -3 becomes +3. Forgetting this is the most common algebra mistake.

5. Writing 2n as n squared: 2n means "2 times n" (e.g., if n = 3, then 2n = 6). n squared means "n times n" (if n = 3, then n squared = 9). These are not the same.

6. Not verifying the answer: Always substitute your answer back into the original equation. If LHS does not equal RHS, recheck your working.

7. Dividing only one term: When solving 2x + 4 = 14, do NOT divide just the x-term. Subtract 4 first (2x = 10), then divide both sides by 2 (x = 5).


Exam Checklist

Before your exam, make sure you can:

  • [ ] Define variable, expression, term, coefficient, and equation correctly
  • [ ] Write a matchstick pattern rule from a visual pattern (e.g., letter patterns)
  • [ ] Find the general term (nth term) of a number pattern like 3, 7, 11, 15, ...
  • [ ] Convert verbal statements to algebraic expressions and vice versa
  • [ ] Identify like terms and unlike terms in an expression
  • [ ] Classify expressions as monomial, binomial, or trinomial
  • [ ] Solve simple linear equations using the balancing method
  • [ ] Solve simple linear equations using the trial-and-error method
  • [ ] Form equations from word problems and solve them
  • [ ] Remember: Additive identity = 0, Multiplicative identity = 1
  • [ ] Always verify your answer by substituting back into the original equation

Frequently Asked Questions

A symbol (usually a letter like x, y, n) that represents an unknown quantity that can take different values.