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Class 12 · Tamil Nadu State Board

Samacheer Kalvi 12th Chemistry Chapter 9 Exercise Solutions

Tamil Nadu Class 12 Chemistry Chapter 9 Electrochemistry exercise solutions with Nernst equation, cell potential, conductance, Kohlrausch law, Faraday laws, corrosion, and numerical patterns.

Updated 17 June 20268 min read

Chapter 9 — Electrochemistry Exercise Solutions

Electrochemistry requires correct sign convention. Always identify the anode (oxidation) and cathode (reduction) before calculating cell potential.

Key Concepts Quick Recap

TermDefinition
Galvanic cellConverts chemical energy to electrical energy (spontaneous redox reaction)
AnodeElectrode where oxidation occurs; negative terminal in galvanic cell
CathodeElectrode where reduction occurs; positive terminal in galvanic cell
Salt bridgeMaintains electrical neutrality by allowing ion flow between half-cells
Standard electrode potential (E°)Potential measured under standard conditions (1 M, 1 atm, 25 °C)
EMF of cellEcell = Ecathode − Eanode
Gibbs energy relationΔG = −nFEcell; ΔG° = −nFE°cell
Nernst equationE = E° − (RT/nF) ln Q = E° − (0.0591/n) log Q at 25 °C
Faraday's first lawMass deposited ∝ charge passed: m = ZIt = ZQ
Faraday's second lawSame charge deposits equivalent weights of different substances
Molar conductivity (Λm)Conductance of one mole of electrolyte between electrodes 1 m apart
Kohlrausch's lawΛ°m = λ⁺ + λ⁻ (sum of limiting molar conductivities of ions)

Formula Recap

ConceptFormula
Cell EMFEcell = E°cathode − E°anode
Nernst equationE = E° − (0.0591/n) log Q (at 25 °C)
Gibbs energyΔG = −nFEcell
Equilibrium constantlog Keq = nE°cell / 0.0591
Faraday's 1st lawm = (M/nF) × Q = (M/nF) × It
Molar conductivityΛm = (κ × 1000) / C (C in mol/L)
Electrochemical equivalentZ = M / (n × F)

I. Choose the Best Answer (MCQs)

1. In a galvanic cell, oxidation takes place at: (a) Cathode (b) Both electrodes (c) Anode (d) Neither electrode

Answer(c) Anode Oxidation = loss of electrons; this occurs at the anode. The anode is the negative electrode in a galvanic cell.

2. The standard EMF of Daniell cell is (+0.34 V for Cu²⁺/Cu and −0.76 V for Zn²⁺/Zn): (a) 0.42 V (b) 1.10 V (c) −0.42 V (d) 1.76 V

Answer(b) 1.10 V Ecell = Ecathode − Eanode = 0.34 − (−0.76) = 1.10 V. Positive Ecell → spontaneous.

3. The Nernst equation for a cell reaction with n = 2 at 25 °C is: (a) E = E° − (0.0591) log Q (b) E = E° − (0.0296) log Q (c) E = E° + (0.0591) log Q (d) E = E° − (0.0591/n²) log Q

Answer(b) E = E° − (0.0296) log Q 0.0591/n = 0.0591/2 = 0.02955 ≈ 0.0296.

4. According to Kohlrausch's law, the molar conductivity of acetic acid at infinite dilution is: (a) λ(CH₃COO⁻) − λ(H⁺) (b) λ(H⁺) + λ(CH₃COO⁻) (c) λ(Na⁺) + λ(Cl⁻) (d) λ(CH₃COOH)

Answer(b) λ(H⁺) + λ(CH₃COO⁻) Kohlrausch: Λ°m(CH₃COOH) = λ°(H⁺) + λ°(CH₃COO⁻). For weak electrolytes, this allows calculation of Λ°m which cannot be measured directly.

5. Which law states that the mass of substance deposited during electrolysis is proportional to the charge passed? (a) Kohlrausch's law (b) Ohm's law (c) Faraday's first law (d) Nernst's law

Answer(c) Faraday's first law m ∝ Q = It. Faraday's first law: m = ZIt, where Z = electrochemical equivalent.

6. The corrosion of iron (rusting) is an example of: (a) A galvanic cell (b) An electrolytic cell (c) A concentration cell (d) A fuel cell

Answer(a) A galvanic cell In corrosion, iron acts as anode (Fe → Fe²⁺ + 2e⁻) and oxygen is reduced at the cathode. Different parts of the iron surface act as anode and cathode — forming a galvanic cell.

7. If E°cell > 0 for a reaction, then: (a) ΔG > 0 (non-spontaneous) (b) ΔG < 0 (spontaneous) (c) Keq < 1 (d) The reaction is at equilibrium

Answer(b) ΔG < 0 (spontaneous) ΔG = −nFEcell. If Ecell > 0 → ΔG < 0 → reaction is spontaneous.

II. Short Answer Questions

Q1. Explain the function of a salt bridge in a galvanic cell.
Answer

A salt bridge is a U-shaped tube filled with an inert electrolyte (like KCl or KNO₃ in agar gel) that connects two half-cells.

Functions: 1. Maintains electrical neutrality in each half-cell — provides counter ions (K⁺ and Cl⁻ migrate into the solutions to balance charge). 2. Completes the circuit — ions flow through it while electrons flow through the external wire. 3. Without a salt bridge, charge would build up, stopping the current.


Q2. State and explain Faraday's two laws of electrolysis.
Answer

First law: The mass of substance deposited or dissolved at an electrode during electrolysis is directly proportional to the quantity of charge (Q) passed. m = Z × Q = Z × I × t where Z = electrochemical equivalent = M/(nF).

Second law: When the same quantity of charge is passed through different electrolytes connected in series, the masses deposited are proportional to their equivalent weights. m₁/m₂ = E₁/E₂ (E = molar mass / n)


Q3. What is Kohlrausch's law? State one application.
Answer

Kohlrausch's law of independent migration of ions states that at infinite dilution, each ion migrates independently and contributes a fixed value to the molar conductivity, regardless of the other ion present.

Λ°m (electrolyte) = Σ λ°(cations) + Σ λ°(anions)

Example: Λ°m(CH₃COOH) = λ°(H⁺) + λ°(CH₃COO⁻) = λ°(HCl) + λ°(CH₃COONa) − λ°(NaCl)

Application: Calculating Λ°m of weak electrolytes (like CH₃COOH) that cannot be measured directly because they never fully dissociate even at high dilution.


Q4. Distinguish between electrolytic and galvanic cells.
Answer
FeatureGalvanic CellElectrolytic Cell
Energy conversionChemical → electricalElectrical → chemical
SpontaneitySpontaneous (ΔG < 0)Non-spontaneous (ΔG > 0)
AnodeNegative terminalPositive terminal (connected to +ve of battery)
CathodePositive terminalNegative terminal
ExamplesDaniell cell, dry cell, fuel cellElectroplating, electrolysis of water

Worked Examples

Example 1 — Standard cell EMF

(E°Zn²⁺/Zn = −0.76 V, E°Cu²⁺/Cu = +0.34 V)

**Find E°cell for: Zn(s)Zn²⁺(aq)Cu²⁺(aq)Cu(s)**
Cell notation: left = anode (oxidation), right = cathode (reduction) Anode: Zn → Zn²⁺ + 2e⁻ (oxidation) Cathode: Cu²⁺ + 2e⁻ → Cu (reduction) Net: Zn + Cu²⁺ → Zn²⁺ + Cu E°cell = E°cathode − E°anode = 0.34 − (−0.76) = 1.10 V ΔG° = −nFE° = −2 × 96500 × 1.10 = −212,300 J = −212.3 kJ (spontaneous)

Example 2 — Nernst equation

Find Ecell for Daniell cell when [Zn²⁺] = 0.1 M and [Cu²⁺] = 0.01 M at 298 K.

Cell reaction: Zn + Cu²⁺ → Zn²⁺ + Cu n = 2 Q = [Zn²⁺]/[Cu²⁺] = 0.1/0.01 = 10 E = E° − (0.0591/n) log Q = 1.10 − (0.0591/2) log 10 = 1.10 − 0.02955 × 1 = 1.10 − 0.030 = 1.07 V

Example 3 — Faraday's law (mass deposited)

Find the mass of copper deposited when 2.5 A flows for 30 minutes through CuSO₄ solution. (Cu = 63.5 g/mol, n = 2)

Q = I × t = 2.5 × (30 × 60) = 2.5 × 1800 = 4500 C Moles of e⁻ = Q/F = 4500/96500 = 0.04663 mol Moles of Cu = 0.04663/2 = 0.02331 mol (since n = 2 for Cu²⁺) Mass = 0.02331 × 63.5 = 1.48 g

Example 4 — Equilibrium constant from E°cell

Find Keq for the Daniell cell reaction at 25 °C. (E°cell = 1.10 V, n = 2)

log Keq = nE°cell / 0.0591 = (2 × 1.10) / 0.0591 = 37.23 Keq = 10^37.23 ≈ 1.7×10³⁷ Extremely large Keq → the reaction goes essentially to completion.

Example 5 — Molar conductivity and degree of ionisation

The molar conductivity of 0.01 M acetic acid is 16.6 S cm² mol⁻¹ and Λ°m = 390.5 S cm² mol⁻¹. Find degree of ionisation.

α = Λm / Λ°m = 16.6 / 390.5 = 0.0425 = 4.25% Ka = Cα² / (1−α) ≈ Cα² (since α << 1) = 0.01 × (0.0425)² = 0.01 × 1.806×10⁻³ = 1.81×10⁻⁵

Common Mistakes

  • Reversing cathode and anode — remember: anode = oxidation, cathode = reduction.
  • Forgetting to subtract E°anode from E°cathode (not add).
  • Not converting time to seconds in Faraday's law calculations.
  • Using the wrong value of n (number of electrons transferred) in Nernst and Faraday calculations.
  • Wrong sign for Gibbs energy: ΔG = −nFE (not +nFE).

Exam Checklist

  • Anode and cathode are correctly identified.
  • Cell EMF formula: Ecell = Ecathode − Eanode.
  • n (number of electrons) is correct for the specific reaction.
  • Time is converted to seconds for Faraday's law.
  • Nernst equation Q uses concentrations in correct positions ([products]/[reactants]).
  • Final answer has correct sign and unit.

Frequently Asked Questions

Nernst equation, standard cell potential, Gibbs energy relation, conductance and Kohlrausch law, Faraday's laws, and corrosion prevention are the most important topics.
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