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Class 12 · Tamil Nadu State Board

Samacheer Kalvi 12th Botany Chapter 11 Exercise Solutions

Tamil Nadu Class 12 Botany Chapter 11 Respiration in Plants exercise solutions — glycolysis, Krebs cycle, oxidative phosphorylation, fermentation, respiratory quotient, anaerobic respiration MCQs and answers.

Updated 18 June 20266 min read

Chapter 11 — Respiration in Plants


Key Concepts Quick Recap

TermDefinition
RespirationOxidative breakdown of organic molecules to release energy (ATP)
Aerobic respirationUses O₂; complete oxidation; CO₂ + H₂O + 38 ATP per glucose
Anaerobic respirationWithout O₂; incomplete oxidation; fermentation
GlycolysisGlucose (6C) → 2 Pyruvate (3C); in cytoplasm; 2 net ATP
Krebs cycle (TCA cycle)Pyruvate → CO₂ + NADH + FADH₂; in mitochondrial matrix
ETC (Oxidative phosphorylation)NADH and FADH₂ → ATP via electron transport chain; inner mitochondrial membrane
FermentationAnaerobic breakdown: glucose → ethanol + CO₂ (yeast) or lactate (bacteria)
RQRespiratory Quotient = CO₂ released / O₂ consumed
GluconeogenesisSynthesis of glucose from non-carbohydrate substrates

I. Choose the Best Answer (MCQs)

1. Glycolysis occurs in: (a) Mitochondrial matrix (b) Cytoplasm (c) Thylakoid membrane (d) Nucleus

Answer(b) Cytoplasm Glycolysis (Embden-Meyerhof-Parnas pathway) occurs in the cytoplasm (cytosol). It does not require mitochondria and occurs in both aerobic and anaerobic conditions. It converts 1 glucose (6C) → 2 pyruvate (3C), producing 2 net ATP and 2 NADH.

2. The net ATP produced during glycolysis from one molecule of glucose is: (a) 4 (b) 2 (c) 38 (d) 36

Answer(b) 2 Glycolysis: 4 ATP produced, 2 ATP consumed (activation) = 2 net ATP. Also produces 2 NADH. The 2 NADH can be used in ETC to produce more ATP (but in cytoplasm, needs shuttle to enter mitochondria).

3. The Krebs cycle takes place in: (a) Cytoplasm (b) Nucleus (c) Mitochondrial matrix (d) Chloroplast

Answer(c) Mitochondrial matrix The Krebs (TCA/citric acid) cycle enzymes are in the mitochondrial matrix. Pyruvate from glycolysis enters the mitochondria, is converted to Acetyl-CoA (by pyruvate decarboxylation), then enters the Krebs cycle.

4. The respiratory quotient (RQ) for carbohydrates is: (a) 0.7 (b) > 1 (c) 1 (d) 0

Answer(c) 1 For carbohydrates: C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O RQ = 6CO₂/6O₂ = 1.0 For fats: RQ ≈ 0.7 (need more O₂ to oxidise). For organic acids (malic acid): RQ > 1 (produce more CO₂ than O₂ consumed).

5. In fermentation by yeast, the end products are: (a) Lactic acid + CO₂ (b) Ethanol + CO₂ (c) Pyruvate + H₂O (d) Acetic acid + H₂

Answer(b) Ethanol + CO₂ Yeast fermentation: Glucose → Pyruvate (glycolysis) → Acetaldehyde → Ethanol + CO₂. Enzyme: pyruvate decarboxylase (pyruvate → acetaldehyde + CO₂), then alcohol dehydrogenase (acetaldehyde + NADH → ethanol + NAD⁺).

6. Which coenzyme accepts electrons during Krebs cycle? (a) ATP (b) FAD and NAD⁺ (c) NADP⁺ (d) CoA

Answer(b) FAD and NAD⁺ In the Krebs cycle, NAD⁺ is reduced to NADH (at 3 steps) and FAD is reduced to FADH₂ (at 1 step) per turn. These carry electrons to the ETC in the inner mitochondrial membrane for oxidative phosphorylation.

7. Cyanide is a respiratory poison because it: (a) Inhibits glycolysis (b) Inhibits cytochrome oxidase (Complex IV), blocking ETC (c) Prevents glucose entry into cells (d) Inhibits the Krebs cycle

Answer(b) Inhibits cytochrome oxidase (Complex IV) Cyanide (CN⁻) binds irreversibly to cytochrome oxidase (Complex IV = terminal electron acceptor in ETC) → blocks electron transfer to O₂ → ETC stops → no more ATP synthesis → cell death. Even glycolysis continues, but cells cannot produce enough ATP.

II. Short Answer Questions

Q1. Describe glycolysis with all the key steps.
Answer

Glycolysis (in cytoplasm): 1 Glucose (6C) → 2 Pyruvate (3C)

Phase 1 — Energy investment (2 ATP used): 1. Glucose + ATP → Glucose-6-phosphate (hexokinase) 2. Glucose-6-phosphate → Fructose-6-phosphate (phosphoglucoisomerase) 3. Fructose-6-phosphate + ATP → Fructose-1,6-bisphosphate (phosphofructokinase — rate-limiting step) 4. Fructose-1,6-bisphosphate → 2 × Glyceraldehyde-3-phosphate (G3P)

Phase 2 — Energy recovery (4 ATP + 2 NADH produced): 5. 2 G3P + 2NAD⁺ → 2 × 1,3-BPG + 2 NADH (G3P dehydrogenase) 6. 2 × 1,3-BPG + 2 ADP → 2 × 3-PGA + 2 ATP (phosphoglycerate kinase) 7. 2 × 3-PGA → 2 × 2-PGA (phosphoglycerate mutase) 8. 2 × 2-PGA → 2 × PEP + 2H₂O (enolase) 9. 2 × PEP + 2 ADP → 2 Pyruvate + 2 ATP (pyruvate kinase)

Net yield: 2 ATP + 2 NADH (per glucose)


Q2. Describe the Krebs cycle.
Answer

The Krebs (TCA/citric acid) cycle occurs in the mitochondrial matrix. Discovered by Hans Krebs (1937).

Entry: Pyruvate (3C) → Acetyl-CoA (2C) + CO₂ + NADH [pyruvate decarboxylation]

One turn of Krebs cycle (per Acetyl-CoA):

1. Acetyl-CoA (2C) + Oxaloacetate (4C) → Citrate (6C) [citrate synthase] 2. Citrate → Isocitrate 3. Isocitrate → α-ketoglutarate (5C) + CO₂ + NADH 4. α-ketoglutarate → Succinyl-CoA (4C) + CO₂ + NADH 5. Succinyl-CoA → Succinate + GTP (= ATP) 6. Succinate → Fumarate + FADH₂ 7. Fumarate → Malate 8. Malate → Oxaloacetate + NADH

Per Acetyl-CoA: 2 CO₂, 3 NADH, 1 FADH₂, 1 GTP Per glucose (2 Acetyl-CoA): 4 CO₂, 6 NADH, 2 FADH₂, 2 GTP


Q3. Calculate the total ATP yield from aerobic respiration of one glucose.
Answer
StageATPNADH → ATPFADH₂ → ATP
Glycolysis2 net ATP2 NADH × 2.5 = 5 ATP—
Pyruvate decarboxylation—2 NADH × 2.5 = 5 ATP—
Krebs cycle (×2)2 GTP6 NADH × 2.5 = 15 ATP2 FADH₂ × 1.5 = 3 ATP
Total~38 ATP

(Older textbooks use 36-38 ATP; modern P/O ratio: NADH = 2.5 ATP, FADH₂ = 1.5 ATP → 30 ATP from ETC + 4 substrate-level + 4 from glycolysis cytoplasmic NADH shuttle = ~30-38 depending on shuttle)


Common Mistakes

  • Saying glycolysis occurs in mitochondria — it occurs in CYTOPLASM.
  • Forgetting Krebs cycle per glucose requires 2 turns (2 pyruvate per glucose).
  • Confusing NADH (from Krebs cycle) and NADPH (from photosynthesis light reaction).
  • RQ for fats: 0.7 (not 1); RQ for organic acids: > 1 (not 1).

Exam Checklist

  • Glycolysis: cytoplasm; glucose → 2 pyruvate; 2 net ATP + 2 NADH.
  • Krebs cycle: mitochondrial matrix; 2 CO₂ + 3 NADH + 1 FADH₂ + 1 GTP per acetyl-CoA.
  • Total ATP: ~38 per glucose (substrate + oxidative phosphorylation).
  • RQ: carbohydrates = 1; fats = 0.7; organic acids > 1.
  • Fermentation: yeast → ethanol + CO₂; bacteria → lactic acid.
  • Cyanide inhibits Complex IV (cytochrome oxidase).

Frequently Asked Questions

38 ATP (theoretical) per glucose molecule in aerobic respiration: 2 ATP from glycolysis + 2 ATP from Krebs cycle + 34 ATP from oxidative phosphorylation (ETC). Practical yield is about 36-38 ATP.
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