Current Affairs updated daily
KalviGavaniKalviGavani

Respiration in Plants — NCERT Class 11 Biology

Complete NCERT Solutions for CBSE Class 11 Biology Chapter 14 — all intext and chapter-end exercise questions on glycolysis, Krebs cycle, electron transport chain, fermentation, oxidative phosphorylation, respiratory quotient, and amphibolic pathway answered clearly.

Updated 11 June 202612 min read

Exercise Solutions Available

Step-by-step answers for all textbook questions in this chapter

View Solutions →

How to Use This Page

These are complete NCERT Solutions for CBSE Class 11 Biology Chapter 14 — Respiration in Plants. Attempt each question before checking the answer. Use precise biochemical terms — marks are given for terms like 'glycolysis', 'Krebs cycle', 'electron transport chain', 'oxidative phosphorylation', 'chemiosmosis', 'amphibolic', etc.


Key Concepts (Quick Recap)

  • Respiration: Catabolic process that breaks down respiratory substrates (mainly glucose) to release energy in the form of ATP.
  • Glycolysis: Occurs in cytoplasm; 1 glucose → 2 pyruvate; net 2 ATP, 2 NADH; does not require O₂.
  • Fate of pyruvate: Aerobic → enters mitochondria, forms acetyl-CoA; Anaerobic → fermentation (ethanol + CO₂ or lactic acid).
  • Krebs cycle (TCA cycle): Occurs in mitochondrial matrix; acetyl-CoA (2C) + oxaloacetate (4C) → citrate (6C); per glucose (2 turns): 2 ATP, 6 NADH, 2 FADH₂, 4 CO₂.
  • Electron transport chain (ETC): Inner mitochondrial membrane; NADH and FADH₂ donate electrons; O₂ is the final electron acceptor forming H₂O.
  • Oxidative phosphorylation: ATP synthesis coupled to electron transport; driven by proton gradient (chemiosmosis); ATP synthase enzyme.
  • ATP yield: Aerobic respiration of 1 glucose — theoretical 36–38 ATP; actual yield ~30–32 ATP in eukaryotes.
  • Fermentation: Anaerobic; incomplete oxidation; ethanol fermentation (yeast) or lactic acid fermentation (muscle cells); only 2 ATP per glucose.
  • Respiratory quotient (RQ): RQ = CO₂ produced / O₂ consumed; carbohydrates RQ = 1, fats RQ ≈ 0.7, proteins RQ ≈ 0.8–0.9.
  • Amphibolic pathway: Krebs cycle is both catabolic (breaks down substrates) and anabolic (provides intermediates for biosynthesis).

Intext Questions

Page 231

Q1. Differentiate between: (a) Respiration and Combustion (b) Glycolysis and Krebs cycle
Answer

(a) Respiration vs Combustion:

FeatureRespirationCombustion
Energy releaseStepwise, controlledSudden, uncontrolled
TemperaturePhysiological temperature (37 °C)Very high temperature
EnzymesRequired (catalysed by enzymes)Not required
ATP productionATP is producedNo ATP produced
IntermediatesFormed at each stepNo intermediates
OccurrenceInside living cellsOutside living organisms

(b) Glycolysis vs Krebs cycle:

FeatureGlycolysisKrebs cycle
LocationCytoplasmMitochondrial matrix
SubstrateGlucose (6C)Acetyl-CoA (2C)
Products per glucose2 pyruvate, 2 ATP (net), 2 NADH4 CO₂, 2 ATP, 6 NADH, 2 FADH₂
Oxygen requirementDoes not require O₂Requires O₂ (indirectly)
CO₂ releaseNo CO₂ released4 CO₂ released per glucose
PhasesEnergy investment (2 ATP used) + Energy payoff (4 ATP produced)Acetyl-CoA + oxaloacetate → citrate → regeneration of oxaloacetate
Q2. What are the main steps in aerobic respiration? Where does it take place?
Answer

The main steps in aerobic respiration are:

1. Glycolysis: Glucose (6C) is broken down into 2 molecules of pyruvate (3C). Occurs in the cytoplasm. Net gain: 2 ATP + 2 NADH. 2. Oxidative decarboxylation of pyruvate: Each pyruvate (3C) is converted to acetyl-CoA (2C) + CO₂ + NADH. Occurs in the mitochondrial matrix. Per glucose: 2 CO₂ + 2 NADH. 3. Krebs cycle (TCA cycle): Acetyl-CoA (2C) combines with oxaloacetate (4C) to form citrate (6C). Through a series of reactions, oxaloacetate is regenerated. Per glucose (2 turns): 4 CO₂ + 2 ATP + 6 NADH + 2 FADH₂. Occurs in the mitochondrial matrix. 4. Electron transport chain (ETC) and oxidative phosphorylation: NADH and FADH₂ donate electrons to the ETC on the inner mitochondrial membrane. ATP is synthesised by ATP synthase using the proton gradient. Per glucose: ~32–34 ATP.

Aerobic respiration takes place in the cytoplasm (glycolysis) and mitochondria (Krebs cycle and ETC).

Page 236

Q1. What is oxidative phosphorylation?
Answer

Oxidative phosphorylation is the process of ATP synthesis that is coupled to the electron transport chain (ETC). It occurs on the inner mitochondrial membrane. The steps are:

1. NADH and FADH₂ donate electrons to the electron carriers (Complex I, II, III, IV) of the ETC. 2. As electrons pass through the carriers, energy is released, which is used to pump protons (H⁺) from the mitochondrial matrix to the intermembrane space. 3. This creates a proton gradient (higher H⁺ concentration in the intermembrane space). 4. The protons flow back into the matrix through ATP synthase (F₀–F₁ complex), and the energy of this flow drives the synthesis of ATP from ADP and inorganic phosphate (Pi). 5. Oxygen acts as the final electron acceptor, combining with electrons and protons to form water (H₂O).

This process is also called chemiosmosis (proposed by Peter Mitchell). Approximately 2–3 ATP are synthesised per NADH and approximately 1.5–2 ATP per FADH₂.

Q2. What is the significance of step-wise release of energy in respiration?
Answer

The significance of step-wise release of energy in respiration is:

1. Energy is not released all at once — if it were, most energy would be lost as heat, which could damage cells. 2. ATP is synthesised gradually — energy is released in small amounts at each step and stored as ATP, which can be used by the cell as needed. 3. Intermediates are produced — these are used as precursors for the synthesis of other biomolecules (amino acids, fatty acids, etc.). 4. Enzyme-controlled reactions — each step is catalysed by a specific enzyme, allowing regulation of the pathway. 5. Efficiency — about 40% of the energy released is trapped in ATP; the rest is released as heat, which helps maintain body temperature.

Page 240

Q1. What happens when cells oxidise pyruvate without oxygen?
Answer

When cells oxidise pyruvate without oxygen (anaerobic conditions), fermentation occurs. There are two types:

1. Alcoholic fermentation (in yeast):

  • Pyruvate (3C) → Acetaldehyde (2C) + CO₂ (by pyruvate decarboxylase)
  • Acetaldehyde + NADH → Ethanol (2C) + NAD⁺ (by alcohol dehydrogenase)
  • NAD⁺ is regenerated, allowing glycolysis to continue.
  • Net yield: 2 ATP per glucose molecule.

2. Lactic acid fermentation (in muscle cells under strenuous exercise, and in some bacteria):

  • Pyruvate + NADH → Lactic acid + NAD⁺ (by lactate dehydrogenase)
  • NAD⁺ is regenerated for glycolysis.
  • No CO₂ is released.
  • Net yield: 2 ATP per glucose molecule.

In both cases, NAD⁺ is regenerated so that glycolysis can continue producing a small amount of ATP (2 per glucose) even in the absence of oxygen.

Q2. Why is the respiratory quotient (RQ) of fats less than 1?
Answer

The respiratory quotient (RQ) of fats is less than 1 because fats require more oxygen for oxidation than the amount of CO₂ produced. Fats have more hydrogen and less oxygen in their molecules compared to carbohydrates, so more O₂ is needed to oxidise the hydrogen to water.

For example, tripalmitin (a fat):

C₅₁H₉₈O₆ + 72.5 O₂ → 51 CO₂ + 49 H₂O

RQ = 51 / 72.5 = 0.70

For glucose (a carbohydrate):

C₆H₁₂O₆ + 6 O₂ → 6 CO₂ + 6 H₂O

RQ = 6 / 6 = 1.0

Since more O₂ is consumed per molecule of CO₂ released during fat oxidation, the RQ of fats is less than 1.


Chapter-End Exercise

Q1. Differentiate between: (a) Respiration and combustion (b) Glycolysis and Krebs cycle
Answer

(See Intext Page 231 Q1 — answered above.)

Q2. What are respiratory substrates? Name the most common respiratory substrate.
Answer

Respiratory substrates are the organic substances that are oxidised during respiration to release energy. The most common respiratory substrates are:

  • Carbohydrates (most common, especially glucose)
  • Fats
  • Proteins
  • Organic acids

The most common respiratory substrate is glucose (C₆H₁₂O₆). It is the preferred substrate because: 1. It can be easily oxidised compared to fats and proteins. 2. It yields energy quickly. 3. It is directly used in glycolysis.

When glucose is unavailable, the body uses fats and then proteins as respiratory substrates.

Q3. Give the schematic representation of glycolysis.
Answer

Glycolysis (Embden-Meyerhof-Parnas pathway):

Glucose (6C) │ Hexokinase + ATP → ADP ▼ Glucose-6-phosphate (6C) │ Phosphohexose isomerase ▼ Fructose-6-phosphate (6C) │ Phosphofructokinase + ATP → ADP ▼ Fructose-1,6-bisphosphate (6C) │ Aldolase ▼ DHAP (3C) + GAP (3C) ←→ both interconvert │ │ ▼ ▼ (2×) 1,3-Bisphosphoglycerate (3C) │ PGK + ADP → ATP × 2 ▼ (2×) 3-Phosphoglycerate (3C) │ Phosphoglyceromutase ▼ (2×) 2-Phosphoglycerate (3C) │ Enolase – H₂O ▼ (2×) Phosphoenolpyruvate (PEP) (3C) │ Pyruvate kinase + ADP → ATP × 2 ▼ (2×) Pyruvate (3C)

Energy investment phase: 2 ATP consumed. Energy payoff phase: 4 ATP produced + 2 NADH generated. Net gain per glucose: 2 ATP + 2 NADH.

Q4. What are the main steps in aerobic respiration? Where does it take place?
Answer

(See Intext Page 231 Q2 — answered above.)

Q5. Give the schematic representation of Krebs cycle.
Answer

Krebs cycle (TCA cycle / Citric acid cycle):

1. Acetyl-CoA (2C) + Oxaloacetate (4C) → Citrate (6C) (by citrate synthase) 2. Citrate → Isocitrate (6C) (by aconitase) 3. Isocitrate + NAD⁺ → α-Ketoglutarate (5C) + NADH + CO₂ (by isocitrate dehydrogenase) 4. α-Ketoglutarate + NAD⁺ + CoA → Succinyl-CoA (4C) + NADH + CO₂ (by α-ketoglutarate dehydrogenase) 5. Succinyl-CoA + GDP + Pi → Succinate (4C) + GTP (→ ATP) + CoA (by succinyl-CoA synthetase) 6. Succinate + FAD → Fumarate (4C) + FADH₂ (by succinate dehydrogenase) 7. Fumarate + H₂O → Malate (4C) (by fumarase) 8. Malate + NAD⁺ → Oxaloacetate (4C) + NADH + H⁺ (by malate dehydrogenase)

Per turn of the cycle (per acetyl-CoA): 3 NADH + 1 FADH₂ + 1 ATP + 2 CO₂ Per glucose (2 turns): 6 NADH + 2 FADH₂ + 2 ATP + 4 CO₂

Q6. What is oxidative phosphorylation?
Answer

(See Intext Page 236 Q1 — answered above.)

Q7. What is the significance of step-wise release of energy in respiration?
Answer

(See Intext Page 236 Q2 — answered above.)

Q8. What happens when cells oxidise pyruvate without oxygen?
Answer

(See Intext Page 240 Q1 — answered above.)

Q9. Discuss "The respiratory pathway is an amphibolic pathway."
Answer

The respiratory pathway (specifically the Krebs cycle) is called an amphibolic pathway because it serves both catabolic and anabolic functions:

Catabolic role:

  • The Krebs cycle breaks down acetyl-CoA (derived from carbohydrates, fats, and proteins) to release energy in the form of NADH, FADH₂, and GTP/ATP.
  • CO₂ is released as a waste product.
  • The electrons from NADH and FADH₂ are used in the ETC to produce more ATP.

Anabolic role:

  • The intermediates of the Krebs cycle are withdrawn for the biosynthesis of various compounds:
  • α-Ketoglutarate → amino acid glutamate → other amino acids
  • Oxaloacetate → amino acid aspartate → pyrimidines
  • Succinyl-CoA → porphyrins (haem, chlorophyll)
  • Citrate → fatty acids and sterols (in cytoplasm)
  • Acetyl-CoA → fatty acids, steroids
  • When intermediates are withdrawn, they are replenished by anaplerotic reactions (e.g., pyruvate + CO₂ → oxaloacetate by pyruvate carboxylase).

Since the pathway functions as both a breakdown (catabolic) and synthesis (anabolic) route, it is amphibolic.

Q10. Define RQ. What is its value for fats?
Answer

Respiratory Quotient (RQ) is defined as the ratio of the volume of CO₂ evolved to the volume of O₂ consumed during respiration:

RQ = Volume of CO₂ evolved / Volume of O₂ consumed

The RQ value for fats is approximately 0.7 (less than 1). This is because fats contain more hydrogen and less oxygen compared to carbohydrates, so more O₂ is required for complete oxidation than the CO₂ produced.

For tripalmitin: RQ = 51/72.5 = 0.70

SubstrateRQ Value
Carbohydrates (glucose)1.0
Fats (tripalmitin)0.7
Proteins0.8–0.9
Organic acids (e.g., malic acid)> 1.0
Q11. What is the common pathway for aerobic and anaerobic respiration?
Answer

The common pathway for both aerobic and anaerobic respiration is glycolysis (also called the Embden-Meyerhof-Parnas pathway).

  • Glycolysis occurs in the cytoplasm and does not require oxygen.
  • It breaks down one molecule of glucose (6C) into two molecules of pyruvate (3C).
  • Net energy yield: 2 ATP + 2 NADH per glucose molecule.

After glycolysis, the fate of pyruvate differs:

ConditionFate of PyruvateEnd ProductsATP Yield
AerobicKrebs cycle + ETC (in mitochondria)CO₂ + H₂O36–38 ATP
AnaerobicFermentation (in cytoplasm)Ethanol + CO₂ (yeast) or Lactic acid (muscles)2 ATP
Q12. Differentiate between aerobic respiration and anaerobic respiration.
Answer
FeatureAerobic RespirationAnaerobic Respiration (Fermentation)
Oxygen requirementRequires O₂Does not require O₂
LocationCytoplasm (glycolysis) + Mitochondria (Krebs cycle, ETC)Cytoplasm only
Complete/incomplete oxidationComplete oxidation of glucoseIncomplete oxidation of glucose
End productsCO₂ + H₂OEthanol + CO₂ (in yeast) or Lactic acid (in muscles)
ATP yield per glucose36–38 ATP (theoretical)2 ATP
StagesGlycolysis → Krebs cycle → ETCGlycolysis → Fermentation
NAD⁺ regenerationVia ETCVia fermentation (reducing acetaldehyde or pyruvate)
Energy efficiencyHigh (~40%)Low (~2.1%)
OccurrenceMost organismsYeast, some bacteria, muscle cells under O₂ debt

Internal Links

  • [Chapter 14 Guide — Respiration in Plants](/school/cbse/class/11/biology/cbse-respiration-in-plants)
  • [All Class 11 Biology Solutions](/school/cbse/class/11/biology/solutions)
  • [Class 11 Biology Subject Guide](/school/cbse/class/11/biology)

Frequently Asked Questions

The complete aerobic respiration of one glucose molecule yields a theoretical maximum of 36–38 ATP: 2 ATP from glycolysis, 2 ATP from the Krebs cycle (per glucose, via 2 turns), and 32–34 ATP from oxidative phosphorylation via the electron transport chain using NADH and FADH₂. The actual yield in eukaryotic cells is about 30–32 ATP because some protons leak across the inner mitochondrial membrane and the shuttle mechanisms for cytoplasmic NADH vary.