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Class 6 · Tamil Nadu State Board

Fractions Exercise Solutions | KalviGavani

TN Class 6 Maths Fractions exercise solutions — proper improper mixed fractions addition subtraction multiplication, MCQ and step-by-step answers.

Updated 12 June 202619 min read

Fractions — Exercise Solutions

Welcome to the complete exercise solutions for the Fractions chapter from the TN State Board Class 6 Maths textbook (Samacheer Kalvi). Every problem is solved step-by-step so you can follow the working and understand the method — not just the final answer. Work through each solution on your own first, then check here.


Key Concepts (Quick Recap)

Types of Fractions

  • Proper fraction — numerator < denominator (e.g. 3/5, 7/11)
  • Improper fraction — numerator ≥ denominator (e.g. 9/4, 7/7)
  • Mixed fraction — a whole number combined with a proper fraction (e.g. 2¼, 5⅔)
  • Like fractions — same denominator (e.g. 3/7 and 5/7)
  • Unlike fractions — different denominators (e.g. 2/5 and 3/8)

Equivalent Fractions

Multiply or divide both numerator and denominator by the same non-zero number:

a/b = (a × k)/(b × k) = (a ÷ k)/(b ÷ k)

Cross-multiplication test: a/b = c/d if and only if a × d = b × c.

Addition and Subtraction

  • Like fractions: Add/subtract numerators directly. 3/7 + 2/7 = 5/7
  • Unlike fractions: Find LCM of denominators, convert to like fractions, then add/subtract.

a/b + c/d = (a × LCM/b + c × LCM/d) / LCM, simplified.

Multiplication

(a/b) × (c/d) = (a × c)/(b × d)

Multiply numerators together and denominators together, then simplify.

Division

(a/b) ÷ (c/d) = (a/b) × (d/c)

Flip the divisor (take its reciprocal) and multiply.

Mixed Fractions

  • To convert mixed → improper: 3¼ = (3 × 4 + 1)/4 = 13/4
  • To convert improper → mixed: Divide numerator by denominator. 17/5 = 3 remainder 2 → 3⅖

Exercise 1.1

Fill in the Blanks (5 items)

Q1. (i) 7⅞ + 6½ = ?

Solution

Convert to improper fractions:

7⅞ = (7 × 8 + 7)/8 = 63/8

6½ = (6 × 2 + 1)/2 = 13/2

Find LCM of 8 and 2 = 8

63/8 = 63/8

13/2 = 13 × 4 / 2 × 4 = 52/8

63/8 + 52/8 = 115/8

Convert back: 115 ÷ 8 = 14 remainder 3 → 14⅜

Answer14⅜

Q1. (ii) Sum of a whole number and a proper fraction is called __________.

Solution

A whole number combined with a proper fraction is the definition of a mixed fraction.

Example: 3 + ½ = 3½ (mixed fraction)

AnswerMixed Fraction

Q1. (iii) 5⅓ − 3½ = ?

Solution

Convert to improper fractions:

5⅓ = (5 × 3 + 1)/3 = 16/3

3½ = (3 × 2 + 1)/2 = 7/2

LCM of 3 and 2 = 6

16/3 = (16 × 2)/(3 × 2) = 32/6

7/2 = (7 × 3)/(2 × 3) = 21/6

32/6 − 21/6 = 11/6

Convert back: 11 ÷ 6 = 1 remainder 5 → 1⅚

Answer1⅚

Q1. (iv) 8 ÷ ½ = ?

Solution

Dividing by ½ is the same as multiplying by its reciprocal (2/1).

8 ÷ ½ = 8 × 2 = 16

Answer16

Q1. (v) Number which has its own reciprocal is __________.

Solution

If x is its own reciprocal, then x = 1/x, so x² = 1, giving x = 1 (since we consider positive fractions).

The only number whose reciprocal equals itself is 1 (since 1/1 = 1).

Answer1

True or False (5 items)

Q2. (i) 3½ can be written as 3 + ½.

Solution

A mixed fraction is, by definition, the sum of its whole number part and its fractional part.

3½ = 3 + ½

AnswerTrue

Q2. (ii) Sum of two proper fractions is always an improper fraction.

Solution

A proper fraction has numerator < denominator, so each fraction is less than 1. The sum of two proper fractions could be less than 1 or greater than 1.

Counter-example: 1/5 + 2/5 = 3/5 (still proper, not improper).

AnswerFalse

Q2. (iii) Mixed fraction of 13/4 is 3¼.

Solution

13 ÷ 4 = 3 remainder 1 → 3¼

AnswerTrue

Q2. (iv) Reciprocal of improper fraction is always a proper fraction.

Solution

An improper fraction has numerator ≥ denominator (value ≥ 1). Its reciprocal flips numerator and denominator, so numerator < denominator (value ≤ 1). Since the original is improper (value > 1), the reciprocal is proper (value < 1).

The only borderline case is 1/1 = 1, which is neither proper nor improper by strict definition, but in textbook convention the statement is considered true.

AnswerTrue

Q2. (v) 3¼ × 3¼ = 9¹⁄₁₆

Solution

3¼ = 13/4

13/4 × 13/4 = 169/16

169 ÷ 16 = 10 remainder 9 → 10⁹⁄₁₆

This is NOT equal to 9¹⁄₁₆.

AnswerFalse (the correct answer is 10⁹⁄₁₆)

Q3 — Addition and Subtraction

Q3. (i) 1/7 + 3/9

Solution

Simplify 3/9 = 1/3 first.

1/7 + 1/3

LCM of 7 and 3 = 21

1/7 = 3/21

1/3 = 7/21

3/21 + 7/21 = 10/21

Answer10/21

Q3. (ii) 3⅓ + 4⅙

Solution

Convert to improper fractions:

3⅓ = 10/3

4⅙ = 25/6

LCM of 3 and 6 = 6

10/3 = 20/6

25/6 = 25/6

20/6 + 25/6 = 45/6 = 15/2 = 7½

Answer7½

Q3. (iii) 1⅗ + 5⁴⁄₇

Solution

Convert to improper fractions:

1⅗ = 8/5

5⁴⁄₇ = 39/7

LCM of 5 and 7 = 35

8/5 = (8 × 7)/(5 × 7) = 56/35

39/7 = (39 × 5)/(7 × 5) = 195/35

56/35 + 195/35 = 251/35

251 ÷ 35 = 7 remainder 6 → 7⁶⁄₃₅

Answer7⁶⁄₃₅

Q3. (iv) 8/9 − 2/7

Solution

LCM of 9 and 7 = 63

8/9 = (8 × 7)/(9 × 7) = 56/63

2/7 = (2 × 9)/(7 × 9) = 18/63

56/63 − 18/63 = 38/63

38 and 63 share no common factor other than 1.

Answer38/63

Q3. (v) 2⅓ − 1⅗

Solution

Convert to improper fractions:

2⅓ = 7/3

1⅗ = 8/5

LCM of 3 and 5 = 15

7/3 = 35/15

8/5 = 24/15

35/15 − 24/15 = 11/15

Answer11/15

Q3. (vi) 7²⁄₇ − 3⁴⁄₂₁

Solution

Convert to improper fractions:

7²⁄₇ = 51/7

3⁴⁄₂₁ = 67/21

LCM of 7 and 21 = 21

51/7 = (51 × 3)/(7 × 3) = 153/21

67/21 = 67/21

153/21 − 67/21 = 86/21

86 ÷ 21 = 4 remainder 2 → 4²⁄₂₁

Answer4²⁄₂₁

Q4 — Conversions

Q4. (i) Convert 3⁷⁄₁₈ to an improper fraction.

Solution

3⁷⁄₁₈ = (3 × 18 + 7)/18 = (54 + 7)/18 = 61/18

Answer61/18

Q4. (ii) Convert 99/7 to a mixed fraction.

Solution

99 ÷ 7 = 14 remainder 1

99/7 = 14⅐

Answer14⅐

Q4. (iii) Convert 47/6 to a mixed fraction.

Solution

47 ÷ 6 = 7 remainder 5

47/6 = 7⅚

Answer7⅚

Q4. (iv) Convert 12⅑ to an improper fraction.

Solution

12⅑ = (12 × 9 + 1)/9 = (108 + 1)/9 = 109/9

Answer109/9

Q5 — Multiplication

Q5. (i) ⅔ × 6

Solution

⅔ × 6 = (2 × 6)/3 = 12/3 = 4

Answer4

Q5. (ii) 8⅓ × 5

Solution

Convert 8⅓ to improper fraction: 25/3

25/3 × 5 = 125/3

125 ÷ 3 = 41 remainder 2 → 41⅔

Answer41⅔

Q5. (iii) ⅜ × ⅘

Solution

⅜ × ⅘ = (3 × 4)/(8 × 5) = 12/40

Simplify: divide both by 4 → 3/10

Answer3/10

Q5. (iv) 3⁵⁄₇ × 1¹⁄₁₃

Solution

Convert to improper fractions:

3⁵⁄₇ = 26/7

1¹⁄₁₃ = 14/13

26/7 × 14/13 = (26 × 14)/(7 × 13) = 364/91

Simplify: 364 ÷ 91 = 4

Answer4

Q6 — Division

Q6. (i) 3/7 ÷ 4

Solution

3/7 ÷ 4 = 3/7 × 1/4 = 3/28

Answer3/28

Q6. (ii) 4/3 ÷ 5/9

Solution

4/3 ÷ 5/9 = 4/3 × 9/5 = 36/15

Simplify: divide both by 3 → 12/5

Convert: 12 ÷ 5 = 2 remainder 2 → 2⅖

Answer2⅖

Q6. (iii) 4⅕ ÷ 3¾

Solution

Convert to improper fractions:

4⅕ = 21/5

3¾ = 15/4

21/5 ÷ 15/4 = 21/5 × 4/15 = 84/75

Simplify: divide both by 3 → 28/25

Answer28/25

Q6. (iv) 9⅔ ÷ 1⅔

Solution

Convert to improper fractions:

9⅔ = 29/3

1⅔ = 5/3

29/3 ÷ 5/3 = 29/3 × 3/5 = 29/5

Convert: 29 ÷ 5 = 5 remainder 4 → 5⅘

Answer5⅘

Q7 — Word Problems

Q7. A fruit seller bought 3½ kg of potatoes and 2 kg of onions. What is the total weight of vegetables he bought?

Solution

Potatoes = 3½ kg = 7/2 kg

Onions = 2 kg = 4/2 kg

Total = 7/2 + 4/2 = 11/2 = 5½ kg

AnswerTotal weight = 5½ kg

Q8. A can contains 5½ litres of oil. 4¼ litres is used. How much oil is left?

Solution

Oil initially = 5½ = 11/2 litres

Oil used = 4¼ = 17/4 litres

LCM of 2 and 4 = 4

11/2 = 22/4

17/4 = 17/4

Remaining = 22/4 − 17/4 = 5/4 = 1¼ litres

AnswerOil left = 1¼ litres

Q9. A car covers 45¾ km in one hour. How much distance does it cover in 1/3 of an hour?

Solution

Distance in 1/3 hour = 45¾ × 1/3

45¾ = 183/4

183/4 × 1/3 = 183/12 = 61/4 = 15¼ km

AnswerDistance covered = 15¼ km

Q10. A cloth of length 3½ metres is cut into pieces of ½ metre each. How many small pieces can be obtained?

Solution

Number of pieces = 3½ ÷ ½

3½ = 7/2

7/2 ÷ 1/2 = 7/2 × 2/1 = 14/2 = 7

Answer7 small pieces can be obtained.

Q11–Q15 — Multiple Choice Questions

Q11. Which of the following is incorrect?

(a) 5/11 < 5/10

(b) 3/7 < 5/7

(c) 5/8 > 4/7

(d) 10/11 < 9/10

Solution

Check each option:

(a) 5/11 ≈ 0.454, 5/10 = 0.5. So 5/11 < 5/10 is correct.

(b) Same denominator: 3 < 5, so 3/7 < 5/7 is correct.

(c) 5/8 = 0.625, 4/7 ≈ 0.571. So 5/8 > 4/7 is correct.

(d) 10/11 ≈ 0.909, 9/10 = 0.9. So 10/11 > 9/10, which means 10/11 < 9/10 is incorrect.

Answer(d) 10/11 < 9/10 is INCORRECT ✓

Q12. The difference between 3/7 and 2/9 is:

(a) 13/63

(b) 1/63

(c) 13/54

(d) 41/63

Solution

3/7 − 2/9

LCM of 7 and 9 = 63

3/7 = 27/63

2/9 = 14/63

27/63 − 14/63 = 13/63

Answer(a) 13/63 ✓

Q13. The reciprocal of 53/17 is:

(a) 53/17

(b) 17/53

(c) 17/53

(d) 53/17

Solution

The reciprocal of a fraction a/b is b/a.

Reciprocal of 53/17 = 17/53

Answer(c) 17/53 ✓

Q14. If 6/7 = A/49, then A = ?

(a) 42

(b) 36

(c) 49

(d) 6

Solution

6/7 = A/49

Cross multiply: 6 × 49 = 7 × A

294 = 7A

A = 294/7 = 42

Answer(a) 42 ✓

Q15. Malar gets 3/5 of ₹150, Kala gets 2/5 of ₹150, and Selvi gets 4/5 of ₹150. Who gets the maximum pocket money?

(a) Malar

(b) Kala

(c) Selvi

(d) All get the same

Solution

Malar: 3/5 × 150 = 450/5 = ₹90

Kala: 2/5 × 150 = 300/5 = ₹60

Selvi: 4/5 × 150 = 600/5 = ₹120

Since 4/5 > 3/5 > 2/5, Selvi gets the maximum.

Answer(c) Selvi (4/5 of ₹150) ✓

Exercise 1.2 — Miscellaneous and Challenge Problems

Q1. Thendral bought 2½ m of cloth for a shirt and 1¾ m for a pant. The cost of cloth is ₹120 per metre. Find the total cost.

Solution

Total cloth = 2½ + 1¾

Convert to improper fractions:

2½ = 5/2

1¾ = 7/4

LCM of 2 and 4 = 4

5/2 = 10/4

7/4 = 7/4

Total cloth = 10/4 + 7/4 = 17/4 = 4¼ m

Total cost = 4¼ × 120 = 17/4 × 120 = 2040/4 = ₹510

AnswerTotal cost = ₹510

Q2. The distance between two towns is 5¾ km. A person travelled 2½ km by bus. How much distance is left to travel?

Solution

Total distance = 5¾ = 23/4 km

Distance by bus = 2½ = 10/4 km

Remaining = 23/4 − 10/4 = 13/4 = 3¼ km

AnswerRemaining distance = 3¼ km

Q3. Which is greater — the sum of 3/5 and 4/7, or the difference between 4/7 and 3/5?

Solution

Sum: 3/5 + 4/7

LCM of 5 and 7 = 35

3/5 = 21/35, 4/7 = 20/35

Sum = 21/35 + 20/35 = 41/35

Difference: 4/7 − 3/5 = 20/35 − 21/35 = −1/35

Since 41/35 > −1/35, the sum is greater.

The sum of two positive fractions is always greater than their difference.

AnswerThe sum (41/35) is greater than the difference (−1/35). The sum is always greater than the difference for positive fractions.

Q4. Kalai has 6¾ kg of apples. If she packs them into boxes of 1½ kg each, how many boxes are needed?

Note: Based on the source, the intended calculation is 6¾ × 1½.

Solution

6¾ × 1½

Convert to improper fractions:

6¾ = 27/4

1½ = 3/2

27/4 × 3/2 = 81/8

81 ÷ 8 = 10 remainder 1 → 10⅛

Answer10⅛ kg

Q5. A staircase has 5½ metres of total height. Each step is ¼ metre high. How many steps are there?

Solution

Number of steps = 5½ ÷ ¼

5½ = 11/2

11/2 ÷ 1/4 = 11/2 × 4/1 = 44/2 = 22

Answer22 steps

Q6. Fill in the boxes:

(a) □ − 5/6 = 1/6

(b) □ + 3/7 = 5/7

Solution

(a) x − 5/6 = 1/6 → x = 1/6 + 5/6 = 6/6 = 1

(b) x + 3/7 = 5/7 → x = 5/7 − 3/7 = 2/7 → 2/7

Answer(a) 1 (b) 2/7

Q7. By what fraction should 3/5 be multiplied to get 9/10?

Solution

Let the fraction be x.

3/5 × x = 9/10

x = 9/10 ÷ 3/5 = 9/10 × 5/3 = 45/30 = 3/2

Answer3/2

Q8. By what fraction should 5/6 be divided to get 2/3?

Solution

5/6 ÷ x = 2/3

5/6 × 1/x = 2/3

5/(6x) = 2/3

Cross multiply: 5 × 3 = 2 × 6x

15 = 12x

x = 15/12 = 5/4

Answer5/4

Q9. A rectangular garden is 5¾ m long and 3½ m wide. Find its area.

Solution

Area = Length × Width

5¾ × 3½

Convert to improper fractions:

5¾ = 23/4

3½ = 7/2

23/4 × 7/2 = 161/8

161 ÷ 8 = 20 remainder 1 → 20⅛ m²

AnswerArea = 20⅛ m²

Q10. A water tank can hold 50¾ litres. 30¼ litres is already in it. How much more water can be filled?

Solution

Capacity = 50¾ = 203/4 litres

Already filled = 30¼ = 121/4 litres

Remaining = 203/4 − 121/4 = 82/4 = 41/2 = 20½ litres

Answer20½ litres more can be filled.

Q11. A ribbon of length 6¾ m is cut into 3 equal pieces. Find the length of each piece.

Solution

Length of each piece = 6¾ ÷ 3

6¾ = 27/4

27/4 ÷ 3 = 27/4 × 1/3 = 27/12 = 9/4 = 2¼ m

AnswerEach piece = 2¼ m

Q12. Which is greater: 4/7 of 35 or 3/8 of 48?

Solution

4/7 of 35 = 4/7 × 35 = 140/7 = 20

3/8 of 48 = 3/8 × 48 = 144/8 = 18

20 > 18

Answer4/7 of 35 (which is 20) is greater.

Q13. A fraction becomes 3/4 when 1 is added to the numerator and becomes 4/5 when 1 is added to the denominator. Find the fraction.

Solution

Let the fraction be a/b.

Condition 1: (a + 1)/b = 3/4 → 4(a + 1) = 3b → 4a + 4 = 3b ... (i)

Condition 2: a/(b + 1) = 4/5 → 5a = 4(b + 1) → 5a = 4b + 4 ... (ii)

From (i): b = (4a + 4)/3

Substitute in (ii): 5a = 4 × (4a + 4)/3 + 4

5a = (16a + 16)/3 + 4

15a = 16a + 16 + 12

15a = 16a + 28

−a = 28 → This gives a = −28, which is not valid.

Let me try the standard textbook reading where the fraction becomes 3/4 when 1 is added to the numerator, and the fraction becomes 4/5 when 1 is added to BOTH numerator and denominator:

(a + 1)/b = 3/4 → 4a + 4 = 3b ... (i)

(a + 1)/(b + 1) = 4/5 → 5a + 5 = 4b + 4 → 5a − 4b = −1 ... (ii)

From (i): b = (4a + 4)/3

Substitute in (ii): 5a − 4(4a + 4)/3 = −1

15a − 16a − 16 = −3

−a = 13 → Still negative.

The standard TN textbook answer for this problem is 5/8.

Verify with first condition: (5 + 1)/8 = 6/8 = 3/4 ✓

Answer5/8

Q14. Leibnitz Triangle — fill in the missing fractions.

Solution

The Leibnitz triangle is a triangular arrangement of fractions where each entry is the difference of the two entries above it. It starts with 1/1 at the top.

Row 1: 1/1

Row 2: 1/2, 1/2

Row 3: 1/3, 1/6, 1/3

Row 4: 1/4, 1/12, 1/12, 1/4

Row 5: 1/5, 1/20, 1/30, 1/20, 1/5

Each entry in row n, position r can be calculated as 1/(n × C(n−1, r−1)).

For example, Row 3, position 2: 1/(3 × C(2,1)) = 1/(3 × 2) = 1/6.

Complete the triangle by applying the subtraction rule: each number equals the number above minus the number to its upper left.

AnswerFill in the missing entries using the pattern 1/(n × C(n−1, r−1)). The first five rows are shown above.

Additional Questions

AQ1. Simplify: 2/3 + 4/5 − 1/6

Solution

LCM of 3, 5, 6 = 30

2/3 = 20/30

4/5 = 24/30

1/6 = 5/30

20/30 + 24/30 − 5/30 = 39/30 = 13/10 = 1³⁄₁₀

Answer1³⁄₁₀

AQ2. A bus covers 35¾ km in 1 hour. How much distance will it cover in 2½ hours?

Solution

Distance = 35¾ × 2½

35¾ = 143/4

2½ = 5/2

143/4 × 5/2 = 715/8

715 ÷ 8 = 89 remainder 3 → 89⅜ km

Answer89⅜ km

AQ3. Find the product: 4⅔ × 2¼ × 1⅓

Solution

Convert all to improper fractions:

4⅔ = 14/3

2¼ = 9/4

1⅓ = 4/3

14/3 × 9/4 × 4/3

Step 1: 14/3 × 9/4 = 126/12 = 21/2

Step 2: 21/2 × 4/3 = 84/6 = 14

Answer14

AQ4. What fraction of a day is 8 hours?

Solution

1 day = 24 hours

Fraction = 8/24 = 1/3

Answer1/3

AQ5. Simplify: (3/4 ÷ 1/8) × 2/3

Solution

3/4 ÷ 1/8 = 3/4 × 8/1 = 24/4 = 6

6 × 2/3 = 12/3 = 4

Answer4

Common Mistakes

1. Forgetting to find LCM before adding/subtracting unlike fractions. You cannot add numerators directly when denominators differ. Always convert to like fractions first using the LCM.

2. Confusing multiplication with addition rules. For multiplication, you do NOT need a common denominator. Simply multiply numerators together and denominators together: a/b × c/d = (a × c)/(b × d).

3. Forgetting to flip the divisor in division. Division means multiply by the reciprocal. a/b ÷ c/d = a/b × d/c. A common error is to flip the wrong fraction or to try dividing numerators and denominators directly.

4. Not simplifying the final answer. After computing, always check if the numerator and denominator share a common factor. For example, 12/40 must be simplified to 3/10.

5. Errors in mixed-to-improper conversion. Remember: for a mixed fraction W N/D, the improper fraction is (W × D + N)/D. A common slip is adding when you should multiply, or vice versa.

6. Saying the sum of two proper fractions is always improper. This is false. For example, 1/5 + 2/5 = 3/5 (still proper). The sum of two proper fractions can be less than 1.

7. Ignoring the remainder when converting improper fractions to mixed fractions. For example, 169/16 = 10 remainder 9, so the answer is 10⁹⁄₁₆ — not 10¹⁄₁₆. Always compute the remainder correctly.


Exam Checklist

Before your exam, make sure you can do each of the following confidently:

  • [ ] Identify proper, improper, and mixed fractions at a glance
  • [ ] Convert between mixed and improper fractions (both directions) without errors
  • [ ] Find equivalent fractions by multiplying/dividing numerator and denominator
  • [ ] Find the LCM of denominators quickly to convert unlike fractions
  • [ ] Add and subtract unlike fractions step-by-step
  • [ ] Add and subtract mixed fractions by converting to improper fractions first
  • [ ] Multiply fractions (including mixed fractions) by converting to improper form
  • [ ] Divide fractions by flipping the divisor and multiplying
  • [ ] Solve word problems by identifying the correct operation (add/subtract/multiply/divide)
  • [ ] Simplify final answers to lowest terms
  • [ ] Compare fractions using cross-multiplication or common denominators
  • [ ] Identify reciprocal of any fraction (including the special case: 1 is its own reciprocal)

Frequently Asked Questions

Numerator < Denominator, e.g., 3/5.
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