Exercise Solutions Available
Step-by-step answers for all textbook questions in this chapter
1. Refraction of Light
Snell's Law
When light travels from medium 1 (refractive index n₁) to medium 2 (refractive index n₂):
where θ₁ is the angle of incidence and θ₂ is the angle of refraction, both measured from the normal.
Key points:
- When light goes from rarer to denser (n₁ < n₂): it bends towards the normal (θ₂ < θ₁).
- When light goes from denser to rarer (n₁ > n₂): it bends away from the normal (θ₂ > θ₁).
- The refractive index n = c/v where c is the speed of light in vacuum and v is the speed in the medium.
Absolute and Relative Refractive Index
- Absolute refractive index of a medium: n = c/v
- Relative refractive index: ₁n₂ = n₂/n₁ = v₁/v₂ = sinθ₁/sinθ₂
Cauchy's relation (dispersion): n = A + B/λ² — refractive index decreases as wavelength increases, which is why violet light bends more than red in a prism.
2. Total Internal Reflection (TIR)
Critical Angle
When light travels from a denser medium (n₁) to a rarer medium (n₂), and the angle of incidence reaches the critical angle C, the refracted ray grazes the interface (θ₂ = 90°).
From Snell's law at the critical angle:
If n₂ = 1 (air): sinC = 1/n₁
For glass (n = 1.5): sinC = 1/1.5 → C ≈ 41.8° For water (n = 1.33): sinC = 1/1.33 → C ≈ 48.8° For diamond (n = 2.42): sinC = 1/2.42 → C ≈ 24.4° (sparkle effect!)
Applications of TIR
| Application | Explanation |
|---|---|
| Optical fibre | Light travels through core (denser) by repeated TIR at core-cladding boundary |
| Prism binoculars | Right-angle prisms reflect light by TIR — no silvering needed |
| Mirage (hot road) | Layers of hot air near road are rarer; light from sky undergoes TIR |
| Endoscope | Flexible optical fibre transmits images by TIR |
| Sparkling of diamond | Very small critical angle (24°) — most light undergoes TIR inside |
3. Refraction Through Lenses
Lens Maker's Equation
For a thin lens made of material with refractive index n in air:
Sign convention (Cartesian):
- Distances measured from optical centre O.
- Distances in the direction of incident light: positive.
- Distances opposite to incident light: negative.
- For a convex lens: R₁ > 0, R₂ < 0 → f > 0 (converging)
- For a concave lens: R₁ < 0, R₂ > 0 → f < 0 (diverging)
Thin Lens Formula
Magnification: m = v/u = height of image / height of object
Power of a Lens
Equivalently: 1/f_eq = 1/f₁ + 1/f₂
- Convex lens: P positive; concave lens: P negative.
- Combination of lenses in contact: P_total = P₁ + P₂ + P₃ ...
Why use lens combination? To reduce aberrations and increase magnification in instruments like microscopes and cameras.
4. Huygens' Wave Theory
Wavefronts
A wavefront is a surface connecting all points that are in the same phase of vibration at a given instant.
| Source type | Wavefront shape |
|---|---|
| Point source | Spherical |
| Line source | Cylindrical |
| Very distant source | Plane (effectively flat) |
Huygens' Principle
1. Every point on a wavefront acts as a secondary source and emits secondary wavelets in all forward directions. 2. The new wavefront at any later time is the common tangential envelope (forward tangent surface) of all secondary wavelets.
Refraction and Reflection from Huygens' Principle
Refraction: When a plane wavefront hits a refracting surface at an angle, parts of the wavefront in the denser medium travel slower. The new wavefront tilts, explaining Snell's law geometrically.
Reflection: Secondary wavelets from the reflecting surface reconstruct a reflected wavefront — the angle of incidence equals the angle of reflection.
5. Interference of Light — Young's Double Slit Experiment (YDSE)
Setup
Two narrow parallel slits S₁ and S₂, separated by distance d, are illuminated by coherent monochromatic light of wavelength λ. A screen is placed at distance D from the slits.
Path Difference
For a point P at height y on the screen:
Conditions
Position: y_n = nλD/d
Position: y_n = (2n−1)λD/2d
- Constructive interference (bright fringe): Δ = nλ where n = 0, ±1, ±2, ...
- Destructive interference (dark fringe): Δ = (2n−1)λ/2
Fringe Width
Distance between two consecutive bright (or dark) fringes:
To increase fringe width: increase D (move screen farther), increase λ (use red light), or decrease d (bring slits closer).
Intensity Distribution
where δ = 2πΔ/λ is the phase difference. Maximum intensity = 4I₀ (at bright fringes), minimum = 0 (at dark fringes).
Conditions for Sustained Interference
1. Sources must be coherent — constant phase difference. 2. Light must be monochromatic — single wavelength. 3. The two sources must have the same amplitude for complete destructive interference (I_min = 0). 4. Slits must be very narrow and closely spaced.
6. Diffraction of Light
Meaning
Diffraction is the bending of light around the edges of an obstacle or through a narrow slit. It is evidence of the wave nature of light.
Single Slit Diffraction
A slit of width a is illuminated by monochromatic light of wavelength λ.
Condition for minima:
- The central maximum is the brightest and widest band.
- Width of central maximum = 2λD/a (from first minima on both sides)
- Secondary maxima occur between minima, each half as wide as the central maximum.
Effect of slit width:
- Narrower slit (smaller a) → wider diffraction pattern.
- Wider slit (larger a) → narrower, more focused pattern.
Difference: Interference vs Diffraction
| Feature | Interference | Diffraction |
|---|---|---|
| Origin | Two or more coherent sources (slits) | Single slit or obstacle |
| Fringe width | All fringes equal width | Central maximum is widest |
| Fringe intensity | All bright fringes equal | Intensity decreases from centre |
| Pattern | Alternating bright and dark | Central bright, then decreasing fringes |
7. Polarisation
Nature of Light
Light is a transverse electromagnetic wave — the electric and magnetic field vectors oscillate perpendicular to the direction of propagation. Sound waves are longitudinal and cannot be polarised; this proves light is transverse.
Unpolarised light: Electric field vibrates in all planes perpendicular to propagation. Plane-polarised light: Electric field vibrates in only one plane.
Methods of Polarisation
1. Polaroids (selective absorption / dichroism): A polaroid transmits only one direction of vibration. 2. Reflection (Brewster's law): At a specific angle θ_B (Brewster's angle), the reflected ray is completely plane-polarised. tanθ_B = n 3. Scattering: Sunlight scattered by molecules (blue sky) is partially polarised. 4. Double refraction (birefringence): Certain crystals like calcite split incident light into two polarised rays (ordinary and extraordinary).
Malus's Law
When plane-polarised light of intensity I₀ passes through an analyser whose axis makes angle θ with the polarisation direction:
- θ = 0°: I = I₀ (maximum transmission)
- θ = 90°: I = 0 (complete extinction)
Brewster's Law
At Brewster's angle θ_B (also called the polarising angle):
At this angle, the reflected and refracted rays are perpendicular to each other (θ_r + θ_refracted = 90°).
For glass (n = 1.5): tan θ_B = 1.5 → θ_B ≈ 56.3°
Worked Numerical Examples
Numerical 1 — Critical Angle and Total Internal Reflection
Problem: A ray of light travels from glass (n = 1.5) to water (n = 1.33). Find the critical angle for this interface.
Numerical 2 — Thin Lens: Image Position and Magnification
Problem: An object 5 cm tall is placed 30 cm in front of a convex lens of focal length 20 cm. Find (a) the image distance, (b) the magnification, and (c) the image height.
Numerical 3 — Young's Double Slit: Fringe Width
Problem: In a YDSE, the slits are separated by 0.5 mm and the screen is 1.0 m away. Monochromatic light of wavelength 589 nm is used. Find (a) the fringe width and (b) the distance of the 3rd bright fringe from the central maximum.
Numerical 4 — Malus's Law: Intensity After Analyser
Problem: Unpolarised light of intensity I₀ falls on a polariser. The transmitted polarised light then falls on an analyser. When the analyser is rotated so that its axis makes 60° with the polariser axis, find the final intensity.
Board Examination Questions and Answers
One-Mark Questions
Q1. State the condition for total internal reflection. A: (1) Light must travel from optically denser to rarer medium. (2) The angle of incidence must exceed the critical angle.
Q2. What is the fringe width in Young's double slit experiment? A: β = λD/d, where λ is wavelength, D is screen distance, and d is slit separation.
Q3. What does Malus's law state? A: The intensity of polarised light transmitted through an analyser is I = I₀cos²θ, where θ is the angle between the analyser axis and the plane of polarisation.
Two-Mark Questions
Five-Mark Questions
Setup: Two narrow parallel slits S₁ and S₂ (separation d) are made on an opaque screen and illuminated by a monochromatic source of wavelength λ. A viewing screen is placed at distance D (D >> d).
Theory: At any point P on the screen at height y from the centre, the path difference between the two waves is:
Constructive interference (bright fringe): Path difference Δ = nλ (n = 0, ±1, ±2, ...) Position: y_n = nλD/d
Destructive interference (dark fringe): Path difference Δ = (2n−1)λ/2 Position: y_n = (2n−1)λD/(2d)
Fringe width derivation: Distance between consecutive bright fringes: β = y_(n+1) − y_n = (n+1)λD/d − nλD/d = λD/d
This is the fringe width formula. It is the same for dark fringes, showing that fringes are equally spaced.
Conditions for sustained interference: 1. Sources must be coherent (constant phase difference). 2. Light must be monochromatic. 3. Slit separation d must be much smaller than D.
Polarisation: In ordinary unpolarised light, the electric field vibrates in all directions perpendicular to propagation. When light is restricted to vibrate in only one plane, it is called plane-polarised light. Polarisation is possible only for transverse waves, confirming the transverse nature of light.
(a) Malus's Law: When plane-polarised light of intensity I₀ is incident on an analyser whose transmission axis makes angle θ with the polarisation direction, the transmitted intensity is: I = I₀cos²θ At θ = 0°, I = I₀ (maximum). At θ = 90°, I = 0 (extinction). This law is used to verify the degree of polarisation of light.
(b) Brewster's Law: When unpolarised light is reflected from a surface at the Brewster angle θ_B, the reflected beam is completely plane-polarised parallel to the surface. Brewster's relation: tanθ_B = n where n is the refractive index of the reflecting medium. At this angle, the reflected and refracted rays are mutually perpendicular. For glass (n = 1.5), θ_B = 56.3°.
(c) Applications of polaroids: 1. Polaroid sunglasses: Horizontally polarised glare (from road and water surfaces) is blocked by vertically oriented polaroid lenses, reducing eye strain. 2. 3D movies: Two projectors emit light polarised at 90° to each other. Viewers wear polaroid glasses with orthogonal lenses — each eye sees only one image, creating depth perception.
NEET and Board Exam Weightage
| Topic | NEET (expected questions) | Board marks |
|---|---|---|
| Refraction and TIR | 1–2 | 3–5 |
| Lenses and lens formula | 1–2 | 3–5 |
| YDSE and fringe width | 1–2 | 5 |
| Diffraction | 1 | 2–3 |
| Polarisation and Malus's law | 1 | 3–5 |
Focus areas for Tamil Nadu board exam:
- Derive fringe width formula (5-mark question, appears in almost every year).
- Numerical on thin lens formula — practice sign convention carefully.
- Critical angle calculation — straightforward 2-mark question.
- Distinguish interference vs diffraction — standard 2-mark question.
- Malus's law derivation and numerical — frequently asked.
