Exercise Solutions Available
Step-by-step answers for all textbook questions in this chapter
Basic Electrical Engineering — Exercise Solutions
Key Concepts Quick Recap
| Concept | Formula/Value |
|---|---|
| Ohm's Law | V = IR (V=volts, I=amperes, R=ohms) |
| Power | P = VI = I²R = V²/R (watts) |
| Energy | E = Pt (watt-hours or joules) |
| Kirchhoff's Current Law (KCL) | Sum of currents entering = sum leaving a node |
| Kirchhoff's Voltage Law (KVL) | Sum of voltages around a closed loop = 0 |
| Series resistance | R_total = R₁ + R₂ + R₃ |
| Parallel resistance | 1/R_total = 1/R₁ + 1/R₂ + 1/R₃ |
| Transformer ratio | V₁/V₂ = N₁/N₂ = I₂/I₁ |
| Indian AC supply | 230V, 50 Hz |
I. Choose the Best Answer (MCQs)
1. According to Ohm's Law, if voltage is doubled and resistance remains same, current will: (a) Halve (b) Double (c) Remain same (d) Quadruple
2. Three resistors of 3Ω, 6Ω, and 9Ω are connected in parallel. The equivalent resistance is: (a) 18Ω (b) 9Ω (c) About 1.64Ω (d) 6Ω
3. A transformer with 200 primary turns and 1000 secondary turns is a: (a) Step-down transformer (b) Step-up transformer (c) Isolation transformer (d) Auto-transformer
4. The SI unit of electrical resistance is: (a) Ampere (b) Volt (c) Ohm (Ω) (d) Watt
5. In a DC motor, electrical energy is converted to: (a) Light energy (b) Chemical energy (c) Mechanical energy (d) Thermal energy
6. Fuse wire is made of: (a) Copper (b) Aluminium (c) Tin-lead alloy (low melting point) (d) Steel
7. The frequency of AC supply in India is: (a) 25 Hz (b) 50 Hz (c) 60 Hz (d) 100 Hz
II. Short Answer Questions
Exam Checklist
- Ohm's Law: V = IR; Power: P = VI = I²R.
- Series: resistances add; Parallel: reciprocals add.
- KCL: currents at junction; KVL: voltages in loop.
- Transformer: V₁/V₂ = N₁/N₂; step-up: N₂ > N₁.
- Motor: electrical → mechanical; Generator: mechanical → electrical.
- India AC: 230V, 50 Hz.
- Fuse: protects against overcurrent (tin-lead, low melting point).
