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Class 11 Statistics Exercise Solutions

Class 11 Statistics exercise solutions — data collection, classification, measures of central tendency, dispersion, correlation, index numbers MCQs and answers.

Updated 18 June 20265 min read

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Class 11 Statistics — Exercise Solutions


Key Concepts Quick Recap

ConceptFormulaNotes
Mean (Ungrouped)x̄ = Σx / NAffected by extreme values
Median (Odd n)Middle value after arrangingNot affected by outliers
Median (Even n)Average of two middle values
ModeMost frequent valueMay have no mode, one, or multiple
RangeMaximum − MinimumSimplest measure of dispersion
Variance (σ²)Σ(x − x̄)² / NIn squared units
Standard Deviation√VarianceSame units as data
Coefficient of Variation(σ / x̄) × 100Relative dispersion (%)
Karl Pearson's rΣ(x−x̄)(y−ȳ) / [Nσₓσᵧ]Range: −1 to +1

I. Choose the Best Answer (MCQs)

1. The sum of deviations of all values from the mean is: (a) Maximum (b) Minimum (c) Zero (d) Infinite

Answer(c) Zero Property of mean: Σ(xᵢ − x̄) = 0 always. This is because the mean is the balancing point of the distribution. Positive and negative deviations cancel out exactly.

2. Which measure of central tendency is not affected by extreme values? (a) Mean (b) Mode (c) Median (d) Range

Answer(c) Median Median: positional average — only depends on middle value(s). Extreme values (outliers) at ends don't affect the middle position. Mean is pulled toward extreme values. Mode is also unaffected by extremes but depends on frequency.

3. If the mean of 5 observations 4, 6, x, 8, 10 is 7, then x = (a) 5 (b) 6 (c) 7 (d) 8

Answer(c) 7 Mean = Σx / N → 7 = (4+6+x+8+10) / 5 → 35 = 28 + x → x = 7.

4. The measure of dispersion which is expressed in the same units as the data is: (a) Variance (b) Mean Deviation (c) Standard Deviation (d) Both (b) and (c)

Answer(d) Both (b) and (c) Variance: expressed in squared units. Mean deviation and standard deviation: both expressed in original units of data. Standard deviation is preferred because it uses all data points and is mathematically tractable.

5. Karl Pearson's coefficient of correlation (r) lies between: (a) 0 and 1 (b) −1 and 0 (c) −1 and +1 (d) −∞ and +∞

Answer(c) −1 and +1 r = −1: perfect negative correlation. r = 0: no linear correlation. r = +1: perfect positive correlation. r between 0.7 and 1.0: strong positive correlation. r between −1.0 and −0.7: strong negative correlation.

6. Primary data is collected: (a) From published sources (b) First-hand, directly for the specific purpose of investigation (c) From secondary published reports (d) From internet sources only

Answer(b) First-hand, directly for the specific purpose of investigation Primary data: original data collected by investigator for the first time for a specific purpose. Methods: questionnaire, interview, observation, experiment. Secondary data: already collected and published by someone else (census, government reports, journals).

7. The coefficient of variation is used to compare: (a) Two datasets with same mean (b) Variability relative to the mean, especially when means differ (c) Two datasets with same standard deviation (d) Only qualitative data

Answer(b) Variability relative to the mean, especially when means differ CV = (σ/x̄) × 100. Used to compare relative dispersion of two or more datasets when units or means differ. Lower CV → more consistent (less variable) data.

II. Short Answer Questions

Q1. Explain the different methods of data collection.
Answer

Data collection methods:

1. Direct Personal Interview: Investigator meets respondents face-to-face. Advantages: personal rapport, clarify doubts, high response rate, can observe non-verbal cues. Disadvantage: expensive, time-consuming, interviewer bias.

2. Indirect Oral Interview: Investigator asks questions through a third party who is close to the subject. Used when direct access is difficult (e.g., census-type surveys in remote areas).

3. Information from Local Sources/Correspondents: Trained local correspondents collect and report data. Used by newspapers, government departments. Cost-effective but may lack accuracy.

4. Questionnaire Sent through Mail/Internet: Printed or online questionnaire sent to respondents. Advantages: wide geographic coverage, anonymous (reduces bias), economical. Disadvantage: low response rate, can't clarify doubts, requires literacy.

5. Census Method: Every unit of the population is observed. Complete and accurate data but very expensive and time-consuming. Example: Census of India (every 10 years).

6. Sampling Method: Only a representative subset (sample) is studied. More practical, faster, less expensive. Requires careful sampling to avoid bias.

Q2. Calculate the mean, median, and mode for the dataset: 5, 7, 8, 9, 7, 6, 7, 10, 5, 6.
Answer

Data arranged in order: 5, 5, 6, 6, 7, 7, 7, 8, 9, 10 (n = 10)

Mean: x̄ = (5+5+6+6+7+7+7+8+9+10) / 10 = 70 / 10 = 7

Median: n = 10 (even) → average of 5th and 6th values. 5th value = 7, 6th value = 7 → Median = (7+7)/2 = 7

Mode: 7 appears 3 times (most frequent) → Mode = 7

In this dataset, Mean = Median = Mode = 7 → approximately normal distribution.


Exam Checklist

  • Mean = Σx/N; Σ(x − x̄) = 0 always.
  • Median: middle value; not affected by extremes.
  • Mode: most frequent; best for categorical data.
  • Range = Max − Min; SD = √Variance (in same units as data).
  • CV = (σ/x̄) × 100; compares relative dispersion.
  • Pearson's r: −1 to +1; 0 = no correlation; ±1 = perfect.
  • Primary data: first-hand; Secondary data: already published.
  • Census: all units; Sampling: representative subset.

Frequently Asked Questions

Three measures: 1. Mean (Arithmetic Mean): sum of all values / number of values. Best for: symmetrical data with no extreme outliers. Not good for skewed data. 2. Median: middle value when arranged in order. Best for: skewed data, ordinal data, when outliers exist. 3. Mode: most frequently occurring value. Best for: categorical/nominal data, finding most common value. Relationship: in normal distribution Mean = Median = Mode.