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Class 11 Maths Trigonometry — Samacheer Kalvi Notes

Samacheer Kalvi Class 11 Maths Chapter 3: trigonometric ratios, compound angles, multiple angles, product-to-sum formulas, inverse trig. Formulas, worked examples, board tips.

Updated 8 June 20265 min read

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Step-by-step answers for all textbook questions in this chapter

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Quick Summary

Trigonometry at Class 11 level goes well beyond the basic ratios of Classes 9–10. It covers compound angles, multiple angles, sub-multiple angles, product-to-sum and sum-to-product formulas, and inverse trigonometric functions. This chapter is heavily tested in board exams, NEET, and JEE.


Trigonometric Ratios — Quick Reference

For angle θ in a right triangle:

RatioDefinitionReciprocal
sin θopposite / hypotenusecosec θ = 1/sin θ
cos θadjacent / hypotenusesec θ = 1/cos θ
tan θopposite / adjacentcot θ = 1/tan θ

Key identities: sin²θ + cos²θ = 1; 1 + tan²θ = sec²θ; 1 + cot²θ = cosec²θ


Standard Angle Values

θ0°30°45°60°90°
sin01/21/√2√3/21
cos1√3/21/√21/20
tan01/√31√3∞

Compound Angle Formulas

FormulaExpression
sin(A ± B)sinA cosB ± cosA sinB
cos(A ± B)cosA cosB ∓ sinA sinB
tan(A ± B)(tanA ± tanB) / (1 ∓ tanA tanB)

Multiple Angle Formulas

FormulaForms
sin 2A2 sinA cosA
cos 2Acos²A − sin²A = 2cos²A − 1 = 1 − 2sin²A
tan 2A2tanA / (1 − tan²A)
sin 3A3sinA − 4sin³A
cos 3A4cos³A − 3cosA

Sub-Multiple Angle (Half-Angle) Formulas

  • sin A = 2 sin(A/2) cos(A/2)
  • cos A = 1 − 2sin²(A/2) = 2cos²(A/2) − 1
  • tan(A/2) = sinA / (1 + cosA) = (1 − cosA) / sinA

Product-to-Sum Formulas

ProductSum/Difference
2 sinA cosBsin(A+B) + sin(A−B)
2 cosA cosBcos(A−B) + cos(A+B)
2 sinA sinBcos(A−B) − cos(A+B)

Sum-to-Product Formulas

SumProduct
sinC + sinD2 sin((C+D)/2) cos((C−D)/2)
sinC − sinD2 cos((C+D)/2) sin((C−D)/2)
cosC + cosD2 cos((C+D)/2) cos((C−D)/2)
cosC − cosD−2 sin((C+D)/2) sin((C−D)/2)

Inverse Trigonometric Functions

FunctionDomainRange
sin⁻¹ x[−1, 1][−π/2, π/2]
cos⁻¹ x[−1, 1][0, π]
tan⁻¹ xℝ(−π/2, π/2)

Key identities: sin⁻¹x + cos⁻¹x = π/2; tan⁻¹x + cot⁻¹x = π/2


Worked Examples

Example 1: Prove that sin(A+B) · sin(A−B) = sin²A − sin²B. LHS = (sinA cosB + cosA sinB)(sinA cosB − cosA sinB) = sin²A cos²B − cos²A sin²B = sin²A(1−sin²B) − (1−sin²A)sin²B = sin²A − sin²B = RHS ✓

Example 2: Find the value of cos 75°. cos 75° = cos(45° + 30°) = cos45°cos30° − sin45°sin30° = (1/√2)(√3/2) − (1/√2)(1/2) = (√3 − 1)/(2√2) = (√6 − √2)/4

Example 3: Prove that sin20° sin40° sin80° = √3/8. Use product formula repeatedly: sin20° sin40° = ½[cos20° − cos60°] = ½[cos20° − ½] Then multiply by sin80° = cos10°… (standard board proof) = √3/8 ✓


Important Questions

One Mark

  • Write the value of sin 75°.
  • State the formula for cos 2A in terms of cos A only.
  • What is the principal value range of tan⁻¹?
  • Express sin 3A in terms of sin A.

Short Answer (3 marks)

  • Prove: (sin A + sin 3A) / (cos A + cos 3A) = tan 2A.
  • Find sin 18° using the identity for sin 3θ = cos 2θ.
  • Express 2 cos 3θ cos 5θ as a sum.

Long Answer (5 marks)

  • Prove: sin(A+B+C) = sinA cosB cosC + cosA sinB cosC + cosA cosB sinC − sinA sinB sinC.
  • In triangle ABC, prove that a/sinA = b/sinB = c/sinC (Sine Rule). Use it to solve a triangle given two angles and one side.

Common Mistakes

  • Mixing up sin(A+B) with sinA + sinB — they are NOT equal.
  • Using cos 2A = cos²A − sin²A when only one trig ratio is given — use the appropriate form (2cos²A−1 or 1−2sin²A) to simplify faster.
  • Forgetting the negative sign in cosC − cosD = −2 sin((C+D)/2) sin((C−D)/2).
  • Inverse trig: applying sin⁻¹(sin x) = x without checking if x is in the principal range.

Board Exam Tips

  • Proof questions (proving identities) require starting from the more complex side and working toward the simpler side — never cross-multiply.
  • Sum-to-product conversions appear in "prove that" questions as 3-mark or 5-mark items.
  • The values of sin 18°, cos 36°, cos 18°, and sin 36° are textbook derivations — practise them.
  • NEET/JEE: Multiple angle and compound angle problems appear in almost every paper.

Frequently Asked Questions

sin(A+B) = sinA cosB + cosA sinB; cos(A+B) = cosA cosB − sinA sinB; tan(A+B) = (tanA + tanB)/(1 − tanA tanB). Replace B with −B for subtraction formulas.