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Class 11 Chemistry Hydrocarbons — Samacheer Kalvi Notes

Samacheer Kalvi Class 11 Chemistry Chapter 13: alkanes, alkenes, alkynes, benzene, reactions — substitution, addition, elimination. Mechanisms, worked examples, board exam tips.

Updated 8 June 20264 min read

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Quick Summary

Hydrocarbons contain only carbon and hydrogen. They are the simplest organic compounds and the foundation for all other organic chemistry. The three main families — alkanes (only C−C), alkenes (C=C), and alkynes (C≡C) — have distinct reactions. Benzene introduces aromatic chemistry. The reactions and mechanisms here appear heavily in NEET.


Classification of Hydrocarbons

Hydrocarbons ├── Aliphatic (open chain) │ ├── Alkanes (saturated, C-C only) │ ├── Alkenes (one C=C) │ └── Alkynes (one C≡C) └── Aromatic (ring, benzene-based)

Alkanes (CₙH₂ₙ₊₂)

Hybridisation: sp³Bond angle: 109.5°

Reactions of Alkanes

Halogenation (Free Radical Substitution — FRS): CH₄ + Cl₂ → CH₃Cl + HCl (in presence of light/heat)

Mechanism steps: 1. Initiation: Cl₂ → 2Cl• (light) 2. Propagation: Cl• + CH₄ → HCl + CH₃•; CH₃• + Cl₂ → CH₃Cl + Cl• 3. Termination: Cl• + Cl• → Cl₂; CH₃• + Cl• → CH₃Cl

Combustion: CH₄ + 2O₂ → CO₂ + 2H₂O (complete)


Alkenes (CₙH₂ₙ)

Hybridisation: sp²Bond angle: 120°

Reactions of Alkenes

ReactionReagentProduct
HydrogenationH₂ / Ni, Pt, PdAlkane
HalogenationCl₂ / Br₂ (CCl₄)Vicinal dihalide; Br₂ decolourisation is test for alkene
HydrohalogenationHXAlkyl halide (Markovnikov's rule)
HydrationH₂O / H₂SO₄Alcohol (Markovnikov)
OzonolysisO₃, then Zn/H₂OAldehydes/Ketones

Markovnikov's Rule: H adds to carbon with more H atoms; X goes to more substituted carbon.

Anti-Markovnikov (Peroxide effect): In presence of peroxide, HBr adds anti-Markovnikov (free radical mechanism).


Alkynes (CₙH₂ₙ₋₂)

Hybridisation: spBond angle: 180°

Reactions of Alkynes

  • Hydrogenation: Ethyne + 2H₂ → Ethane (Lindlar's catalyst gives cis-alkene)
  • Halogenation: HC≡CH + 2Cl₂ → CHCl₂−CHCl₂
  • Hydration: HC≡CH + H₂O → CH₃CHO (Markovnikov; Hg²⁺ catalyst)
  • Acidic nature: Terminal alkynes react with Na: HC≡CH + Na → HC≡C⁻Na⁺ + ½H₂

Benzene (C₆H₆) — Aromatic Compound

Structure: Planar hexagonal ring; sp² hybridised carbons; 6 π electrons delocalised.

Hückel's rule: Aromatic if 4n+2 π electrons (n = 0,1,2…). Benzene: n = 1, 6π electrons ✓

Reactions of Benzene (Electrophilic Aromatic Substitution — EAS)

ReactionReagentProduct
HalogenationCl₂ / FeCl₃Chlorobenzene + HCl
NitrationConc. HNO₃ + conc. H₂SO₄Nitrobenzene
SulphonationFuming H₂SO₄Benzenesulphonic acid
Friedel-Crafts alkylationRCl / AlCl₃Alkylbenzene
Friedel-Crafts acylationRCOCl / AlCl₃Aryl ketone

Worked Examples

Example 1: Write the mechanism for free radical chlorination of methane. (Initiation: Cl₂ → 2Cl•; Propagation: two steps; Termination: radical coupling) — see above.

Example 2: Predict the major product of propene + HBr. CH₃CH=CH₂ + HBr → CH₃CHBrCH₃ (2-bromopropane, Markovnikov).

Example 3: How is acetaldehyde prepared from acetylene? HC≡CH + H₂O → CH₃CHO (Hg²⁺/H₂SO₄ catalyst, Markovnikov addition, keto form of the enol).


Important Questions

One Mark

  • What is the general formula of alkynes?
  • State Markovnikov's rule.
  • Which halogen decolourises bromine water test — alkene or alkane?
  • What is the hybridisation of carbon in benzene?

Short Answer (3 marks)

  • Explain the free radical mechanism of chlorination of methane.
  • Write the products of ozonolysis of CH₂=CHCH₃. What does this tell you about the alkene structure?
  • Why does benzene prefer substitution over addition reactions?

Long Answer (5 marks)

  • Explain the electrophilic addition mechanism for the reaction of ethene with HBr. How does the peroxide effect change the product?
  • Compare the reactions of alkanes, alkenes, and alkynes with bromine. What do the observations tell you about saturation?

Common Mistakes

  • Markovnikov's rule: adding H to the more substituted carbon (wrong!) — H goes to the carbon with MORE hydrogen.
  • Confusing free radical substitution (alkanes, light) with electrophilic addition (alkenes, no light needed).
  • Benzene undergoes SUBSTITUTION, not addition — its aromatic stability prevents addition.
  • Terminal alkyne acidity: forgetting that only terminal alkynes are acidic (sp carbon's higher s-character → stronger bond holding the H → actually more acidic, not less).

Board Exam Tips

  • The free radical mechanism of halogenation of alkanes (all three steps) is a guaranteed 5-mark question.
  • Markovnikov vs anti-Markovnikov (peroxide effect) appears as a 3-mark question.
  • Electrophilic aromatic substitution mechanism (nitration or halogenation) is a 5-mark board staple.
  • NEET: Reactions of alkenes (especially addition reactions with different reagents) appear in 2–3 questions per paper.

Frequently Asked Questions

In the addition of HX (or H₂O) to an unsymmetrical alkene, the hydrogen adds to the carbon with more hydrogen atoms (more substituted carbon gets X). The major product has X on the carbon that can form the more stable carbocation.