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The s-Block Elements — NCERT Class 11 Chemistry

Complete NCERT Solutions for CBSE Class 11 Chemistry Chapter 10 — all intext and chapter-end exercise questions on alkali metals, alkaline earth metals, diagonal relationships, compounds, and biological importance answered clearly.

Updated 11 June 202620 min read

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This page provides complete, step-by-step NCERT solutions for CBSE Class 11 Chemistry Chapter 10 — The s-Block Elements. Every intext question (grouped by page number) and every chapter-end exercise question is answered with clear explanations, chemical equations, and trend analyses. Use the section headings to jump to the question you need help with.


Key Concepts (Quick Recap)

  • Alkali Metals (Group 1): Li, Na, K, Rb, Cs, Fr. ns¹ configuration, highly reactive, low ionization enthalpy, form M⁺ ions, stored under kerosene.
  • Alkaline Earth Metals (Group 2): Be, Mg, Ca, Sr, Ba, Ra. ns² configuration, less reactive than Group 1, form M²⁺ ions, harder and denser than alkali metals.
  • Trends Down the Group: Atomic/ionic radius increases, ionization enthalpy decreases, reactivity increases, melting/boiling points decrease (alkali metals), electropositive character increases.
  • Anomalous Behaviour of Li: Small size, high polarizing power, forms covalent compounds, hardest metal in Group 1, highest IE, forms nitride (Li₃N) with N₂.
  • Anomalous Behaviour of Be: Small size, high charge/size ratio, amphoteric oxide (BeO), covalent compounds, does not form peroxide or superoxide, does not impart colour to flame.
  • Diagonal Relationships: Li–Mg (similar ionic radius, carbonates decompose on heating, form nitrides, hydroxides less soluble). Be–Al (amphoteric oxides, form covalent halides, passivate with HNO₃).
  • Important Compounds of Na: NaOH (caustic soda), Na₂CO₃ (washing soda), NaHCO₃ (baking soda), NaCl (common salt).
  • Important Compounds of Ca: CaO (quicklime), Ca(OH)₂ (slaked lime), CaCO₃ (limestone), CaSO₄·2H₂O (gypsum), CaSO₄·½H₂O (Plaster of Paris).
  • Biological Importance: Na⁺ and K⁺ (nerve impulse, fluid balance), Mg²⁺ (chlorophyll, enzymes), Ca²⁺ (bones, teeth, blood clotting, muscle contraction).
  • Cement: Mixture of limestone (CaCO₃) and clay (aluminosilicates). Composition: CaO (60–67%), SiO₂ (17–25%), Al₂O₃ (3–8%), Fe₂O₃ (0.5–6%).

Intext Questions

Page 244–245

Q1. Why are alkali metals not found in nature in the free state?
AnswerAlkali metals have only one electron in their valence shell (ns¹), which they can easily lose to attain a noble gas configuration. Their ionization enthalpies are the lowest in their respective periods, making them extremely reactive. They react vigorously with air (oxygen), water, and even nitrogen. Because of this high reactivity, they are always found in nature in the combined state (as compounds like NaCl, KCl, LiAlSi₂O₆), never in the free state.
Q2. Why does the ionization enthalpy of alkali metals decrease down the group?
AnswerDown the group from Li to Cs:
  • The atomic radius increases (additional shells are added)
  • The valence electron is farther from the nucleus
  • The shielding effect of inner electrons increases
  • The effective nuclear charge on the valence electron decreases

As a result, less energy is required to remove the outermost electron, so ionization enthalpy decreases: Li > Na > K > Rb > Cs.

Q3. Why are alkali metals soft and have low melting points?
AnswerAlkali metals have only one valence electron participating in metallic bonding. The metallic bonds are weak because:
  • Only one electron per atom contributes to the electron sea
  • Large atomic radii mean the metallic bonds are longer and weaker
  • The bond strength decreases down the group

Weak metallic bonding results in softness and low melting/boiling points. In fact, Cs and Rb are so soft they can be cut with a knife.

Q4. Why is Li the strongest reducing agent among alkali metals despite having the highest ionization enthalpy?
AnswerThe reducing power depends on the overall process: M(s) → M⁺(aq) + e⁻, which involves sublimation enthalpy, ionization enthalpy, and hydration enthalpy. Although Li has the highest ionization enthalpy, it also has the highest hydration enthalpy (due to its very small size and high charge density). The large hydration enthalpy more than compensates for the high ionization enthalpy, making the overall process most favourable for Li. Hence, Li is the strongest reducing agent in aqueous solution.
Q5. What happens when alkali metals are exposed to air?
AnswerAlkali metals react with air (oxygen and moisture) and must be stored under kerosene:
  • With oxygen: Form different oxides depending on the metal.
  • Li → Li₂O (oxide)
  • Na → Na₂O₂ (peroxide)
  • K, Rb, Cs → MO₂ (superoxide)

2M + 2H₂O → 2MOH + H₂↑

  • With moisture: React vigorously with atmospheric moisture.
  • With nitrogen (Li only): 6Li + N₂ → 2Li₃N

The reactivity increases down the group: Li < Na < K < Rb < Cs.


Page 252–254

Q6. Explain the preparation of NaOH by the Castner-Kellner process.
AnswerThe Castner-Kellner process (electrolytic process) uses a cell with:
  • Anode: Carbon
  • Cathode: Mercury (Hg)
  • Electrolyte: Brine (concentrated NaCl solution)

The process occurs in three compartments:

At the cathode (Hg): Na⁺ + e⁻ → Na (deposited on Hg as sodium amalgam, Na-Hg)

At the anode: 2Cl⁻ → Cl₂ + 2e⁻ (chlorine gas liberated)

The sodium amalgam reacts with water in a separate compartment: 2Na-Hg + 2H₂O → 2NaOH + H₂ + 2Hg

Mercury is recycled. This process gives very pure NaOH.

Q7. Write the chemical formula of: (a) Washing soda (b) Baking soda (c) Quicklime (d) Slaked lime

Answer

(a) Washing soda: Na₂CO₃·10H₂O (sodium carbonate decahydrate)

(b) Baking soda: NaHCO₃ (sodium hydrogen carbonate / sodium bicarbonate)

(c) Quicklime: CaO (calcium oxide)

(d) Slaked lime: Ca(OH)₂ (calcium hydroxide)

Q8. Why is Na₂CO₃·10H₂O called washing soda?
AnswerNa₂CO₃·10H₂O is called washing soda because: 1. It is used for washing (laundering) clothes — its alkaline nature removes grease and stains 2. It softens hard water by precipitating Ca²⁺/Mg²⁺ as carbonates: Na₂CO₃ + CaSO₄ → CaCO₃↓ + Na₂SO₄ 3. It gives a strongly alkaline solution in water (due to hydrolysis of CO₃²⁻), which helps in removing dirt and grease
Q9. How is sodium carbonate manufactured by the Solvay process?
AnswerThe Solvay process involves the following steps:

1. Ammoniation of brine: NaCl + NH₃ + H₂O → NH₄Cl + NaOH (partial)

2. Carbonation: NH₃ + H₂O + CO₂ → NH₄HCO₃ NaCl + NH₄HCO₃ → NaHCO₃↓ + NH₄Cl

3. Heating: 2NaHCO₃ → Na₂CO₃ + CO₂ + H₂O

4. Recovery of NH₃: 2NH₄Cl + Ca(OH)₂ → 2NH₃ + CaCl₂ + H₂O

Raw materials: NaCl, CaCO₃ (lime stone), NH₃. CO₂ is obtained from: CaCO₃ → CaO + CO₂.

Q10. Why cannot potassium carbonate be prepared by the Solvay process?
AnswerIn the Solvay process, NaHCO₃ precipitates out because it is less soluble in the reaction mixture. However, KHCO₃ is more soluble than NaHCO₃ and does not precipitate out under the same conditions. Since KHCO₃ remains in solution, it cannot be separated by filtration, and the process cannot continue. Hence, K₂CO₃ cannot be prepared by the Solvay process.

Page 264–265

Q11. Why are alkaline earth metals harder than alkali metals?
AnswerAlkaline earth metals are harder than alkali metals because: 1. They have two valence electrons (ns²) participating in metallic bonding, compared to one (ns¹) for alkali metals. This results in stronger metallic bonds. 2. Their atoms are smaller (higher nuclear charge pulls electrons in more), leading to closer packing. 3. The higher charge on the cation (M²⁺ vs M⁺) leads to stronger metallic bonding.
Q12. Why does the solubility of alkaline earth metal hydroxides increase down the group?
AnswerDown the group from Be to Ba:
  • The size of the M²⁺ ion increases
  • The lattice enthalpy of the hydroxide decreases (larger ion = weaker lattice)
  • The hydration enthalpy also decreases, but the decrease in lattice enthalpy is more significant
  • The net result is that the dissolution becomes more favourable

Hence, solubility increases: Be(OH)₂ < Mg(OH)₂ < Ca(OH)₂ < Sr(OH)₂ < Ba(OH)₂

Q13. Why does the solubility of alkaline earth metal carbonates and sulfates decrease down the group?
AnswerFor carbonates and sulfates:
  • Down the group, the cation size increases (Be²⁺ → Ba²⁺)
  • The lattice enthalpy decreases but the hydration enthalpy decreases more rapidly
  • Since the anion (CO₃²⁻ or SO₄²⁻) is large, the decrease in hydration enthalpy of the cation dominates
  • The overall free energy change becomes less negative

Hence, solubility decreases: BeCO₃ > MgCO₃ > CaCO₃ > SrCO₃ > BaCO₃ (same trend for sulfates).

Q14. Explain the preparation and uses of quicklime (CaO).
Answer

Preparation: CaCO₃(s) →(900–1000 °C) CaO(s) + CO₂(g) (calcination of limestone)

Uses: 1. Manufacture of cement and mortar 2. Manufacture of Ca(OH)₂ (slaked lime) 3. As a drying agent (desiccant) 4. In steel manufacture (removing impurities) 5. In the manufacture of sugar 6. As a refractory material (lined furnaces) 7. In soil treatment (reducing acidity)

Q15. What is Plaster of Paris? How is it prepared?
AnswerPlaster of Paris (CaSO₄·½H₂O) is a hemihydrate of calcium sulphate.

Preparation: CaSO₄·2H₂O (gypsum) →(120–130 °C) CaSO₄·½H₂O + 1½H₂O

When gypsum is heated carefully at 120–130 °C, it loses 1.5 molecules of water to form Plaster of Paris. If heated above 200 °C, it forms dead-burnt plaster (anhydrous CaSO₄), which does not set on mixing with water.

Uses: Surgical casts, casts for statues, decorative work, fire-proofing, dentistry.


Chapter-End Exercise

Q1. What are the common physical properties of alkali metals?
Answer1. Silvery white, soft — can be cut with a knife (softness increases down the group) 2. Low melting and boiling points — decrease down the group 3. Low density — Li, Na, K are lighter than water (K < Na < Li) 4. Low ionization enthalpy — decrease down the group 5. Highly electropositive — increase down the group 6. Good conductors of heat and electricity — due to free mobile electrons 7. Photoelectric effect — Cs and K emit electrons on exposure to light 8. Form ionic compounds — M⁺ with strong electrovalent bonding
Q2. Discuss the general trends in the properties of alkali metals.
Answer
PropertyTrend down the group (Li → Cs)
Atomic/ionic radiusIncreases
Ionization enthalpyDecreases
Electropositive characterIncreases
ReactivityIncreases
Melting/boiling pointDecreases
DensityIncreases (except K)
Hydration enthalpyDecreases
Reducing power (aqueous)Li > Na > K > Rb > Cs (overall, with Li strongest due to hydration)
Q3. Why does the reactivity of alkali metals increase down the group?
AnswerDown the group:
  • Atomic size increases
  • Ionization enthalpy decreases (valence electron is farther from nucleus, more shielded)
  • The energy required to lose the valence electron decreases
  • It becomes easier to form M⁺ ions

Hence, reactivity increases from Li to Cs: Li < Na < K < Rb < Cs.

Q4. Compare the alkali metals and alkaline earth metals with respect to: (a) Ionization enthalpy (b) Basicity of oxides (c) Solubility of hydroxides

Answer

(a) Ionization enthalpy: Group 2 metals have higher IE than Group 1 metals because of smaller size and higher nuclear charge. Both groups show decreasing IE down the group.

(b) Basicity of oxides: Group 2 oxides are less basic than Group 1 oxides. Both increase in basicity down the group. BeO is amphoteric; others are basic.

(c) Solubility of hydroxides: Group 1 hydroxides are more soluble than Group 2 hydroxides. For Group 2, solubility increases down the group: Be(OH)₂ < Mg(OH)₂ < Ca(OH)₂ < Ba(OH)₂.

Q5. What is the anomalous behaviour of lithium? Explain with examples.
AnswerLithium shows anomalous behaviour due to its:
  • Extremely small size
  • High charge/size ratio (high polarizing power)
  • High ionization enthalpy (highest in Group 1)

Examples of anomalous behaviour:

1. Harder and lighter than other alkali metals 2. Forms covalent compounds — LiCl is covalent (partially), others are ionic 3. Reacts with nitrogen — 6Li + N₂ → 2Li₃N (no other alkali metal does this at room temperature) 4. Oxide — Li forms normal oxide (Li₂O), not peroxide or superoxide 5. Less reactive with water — Li reacts steadily, others react violently 6. Carbonate decomposes on heating — Li₂CO₃ → Li₂O + CO₂ (others are stable) 7. Hydroxide decomposes on heating — 2LiOH → Li₂O + H₂O (others are stable)

Q6. Explain the diagonal relationship between Li and Mg.
AnswerLi (Group 1, Period 2) resembles Mg (Group 2, Period 3) due to similar charge/size ratios. Similarities include:

1. Both form normal oxides (Li₂O, MgO) — not peroxides or superoxides 2. Both form nitrides with N₂: 6Li + N₂ → 2Li₃N; 3Mg + N₂ → Mg₃N₂ 3. Both carbonates decompose on heating: Li₂CO₃ → Li₂O + CO₂; MgCO₃ → MgO + CO₂ 4. Both hydroxides are weak bases and decompose on heating 5. Both fluorides, phosphates, and oxalates are sparingly soluble 6. Both form organometallic compounds (Li is widely used in organolithium chemistry, similar to Grignard reagents of Mg) 7. Both have similar polarizing power due to comparable ionic radii

Q7. Explain the anomalous behaviour of beryllium.
AnswerBeryllium shows anomalous behaviour because of its:
  • Very small size
  • High charge/size ratio
  • High ionization enthalpy (highest in Group 2)

Anomalous properties:

1. Amphoteric oxide — BeO is amphoteric (reacts with both acid and base); other Group 2 oxides are basic 2. Covalent compounds — Be forms predominantly covalent compounds (BeCl₂ is covalent) 3. No peroxide or superoxide — Be does not form peroxide or superoxide 4. Does not impart colour to flame — Be has no low-energy excited states for flame test 5. Does not form hydrated salts easily — due to very high hydration energy but small size limits coordination 6. Coordination number limited to 4 — Be compounds have max coordination 4 7. Does not react with water — even at red heat

Q8. Explain the diagonal relationship between Be and Al.
AnswerBe (Group 2, Period 2) resembles Al (Group 13, Period 3):

1. Both have amphoteric oxides — BeO and Al₂O₃ dissolve in both acids and bases 2. Both form covalent halides — BeCl₂ and AlCl₃ are covalent 3. Both resist acid attack — passivated by concentrated HNO₃ 4. Both hydroxides are amphoteric — dissolve in both acid and base 5. Both carbonates are unstable — decompose on heating 6. Both form complexes — Be forms [BeF₄]²⁻; Al forms [AlF₆]³⁻

Q9. Write the electronic configuration of alkali metals and alkaline earth metals.
Answer
ElementConfigurationElementConfiguration
Li (3)[He] 2s¹Be (4)[He] 2s²
Na (11)[Ne] 3s¹Mg (12)[Ne] 3s²
K (19)[Ar] 4s¹Ca (20)[Ar] 4s²
Rb (37)[Kr] 5s¹Sr (38)[Kr] 5s²
Cs (55)[Xe] 6s¹Ba (56)[Xe] 6s²
Fr (87)[Rn] 7s¹Ra (88)[Rn] 7s²

All alkali metals: ns¹; all alkaline earth metals: ns².

Q10. Why does Be not impart colour to the flame?
AnswerThe flame test works because the valence electron is excited to a higher energy level and then returns, emitting visible light. For Be:
  • The ionization enthalpy is very high (899 kJ/mol)
  • The energy required to excite the electron is very high
  • The emitted radiation lies in the UV region, not the visible region

Hence, Be does not impart any colour to the flame.

Q11. What happens when: (a) Sodium metal is dropped on water (b) Sodium metal is heated in free supply of air (c) Sodium peroxide dissolves in water

Answer

(a) 2Na + 2H₂O → 2NaOH + H₂↑ (vigorous, exothermic; H₂ may catch fire)

(b) 2Na + O₂ → Na₂O₂ (sodium peroxide, as sodium forms peroxide, not normal oxide)

(c) Na₂O₂ + 2H₂O → 2NaOH + H₂O₂ (sodium peroxide dissolves to give NaOH and H₂O₂)

Q12. What happens when: (a) Magnesium is burnt in air (b) Calcium is burnt in air

Answer

(a) 2Mg + O₂ → 2MgO (brilliant white flame, forms magnesium oxide) 3Mg + N₂ → Mg₃N₂ (also forms some magnesium nitride)

(b) 2Ca + O₂ → 2CaO (forms calcium oxide) Ca + H₂O (moisture in air) → CaO + H₂O → Ca(OH)₂ (also reacts with moisture)

Q13. Compare the solubility of carbonates and hydroxides of Group 2 elements.
Answer

Carbonates: Solubility decreases down the group. BeCO₃ > MgCO₃ > CaCO₃ > SrCO₃ > BaCO₃

Reason: Lattice enthalpy decreases, but hydration enthalpy decreases more rapidly. The large CO₃²⁻ anion means hydration enthalpy dominates the trend.

Hydroxides: Solubility increases down the group. Be(OH)₂ < Mg(OH)₂ < Ca(OH)₂ < Sr(OH)₂ < Ba(OH)₂

Reason: Lattice enthalpy decreases more rapidly than hydration enthalpy for the smaller OH⁻ anion. The decrease in lattice enthalpy favours dissolution.

Q14. Describe the preparation and uses of: (a) Sodium hydroxide (b) Sodium carbonate (c) Quicklime

Answer

(a) Sodium hydroxide (NaOH):

2NaCl + 2H₂O → 2NaOH + H₂ + Cl₂

  • Preparation: Electrolysis of brine (Castner-Kellner / membrane cell)
  • Uses: Soap manufacture, paper industry, textile industry, petroleum refining, drain cleaner

(b) Sodium carbonate (Na₂CO₃):

  • Preparation: Solvay process (from NaCl, CaCO₃, NH₃)
  • Uses: Glass manufacture, soap/detergent, water softening, laundry

(c) Quicklime (CaO):

  • Preparation: CaCO₃ →(heat) CaO + CO₂ (calcination of limestone)
  • Uses: Cement manufacture, steel industry, soil treatment, drying agent, water treatment
Q15. What is cement? Describe its manufacture.
AnswerCement is a grey powder made by grinding clinker (obtained by heating a mixture of limestone and clay) with a small amount of gypsum.

Manufacture: 1. Mixing: Limestone (CaCO₃) and clay (aluminosilicate) are mixed in correct proportions 2. Heating: The mixture is heated in a rotary kiln at 1500–1600 °C

3. Clinker formation: 3CaO·SiO₂, 2CaO·SiO₂, 3CaO·Al₂O₃, 4CaO·Al₂O₃·Fe₂O₃ 4. Grinding: Clinker is ground with 2–3% gypsum (CaSO₄·2H₂O) to retard setting time

  • CaCO₃ → CaO + CO₂
  • CaO reacts with SiO₂, Al₂O₃, Fe₂O₃ to form clinker compounds

Composition: CaO (60–67%), SiO₂ (17–25%), Al₂O₃ (3–8%), Fe₂O₃ (0.5–6%)

Q16. Discuss the biological importance of sodium and potassium.
Answer
  • Na⁺: Major extracellular cation; maintains osmotic pressure, fluid balance, and acid-base balance; essential for nerve impulse transmission and muscle function
  • K⁺: Major intracellular cation; crucial for nerve impulse conduction, heart function, and muscle contraction; activates enzymes; regulates cell membrane potential
  • The Na⁺/K⁺ ATPase pump maintains the concentration gradient: 3 Na⁺ out and 2 K⁺ in per ATP hydrolysed
  • Daily requirement: Na ≈ 2–5 g; K ≈ 2–6 g
Q17. Discuss the biological importance of magnesium and calcium.
Answer

Magnesium (Mg²⁺):

  • Central atom in chlorophyll (essential for photosynthesis)
  • Cofactor for many enzymes (especially ATP-utilizing enzymes)
  • Required for DNA and RNA synthesis
  • Helps in neuromuscular transmission
  • Daily requirement: ~300 mg

Calcium (Ca²⁺):

  • Major component of bones and teeth (as hydroxyapatite, Ca₅(PO₄)₃OH)
  • Essential for blood clotting (factor IV)
  • Required for muscle contraction (troponin-tropomyosin system)
  • Important for nerve impulse transmission
  • Activates enzymes (lipase, amylase)
  • Regulates heart beat
  • Daily requirement: ~800–1000 mg
Q18. Why is the solution of alkali metals in liquid ammonia conducting?
AnswerWhen alkali metals dissolve in liquid ammonia, they produce a solution that conducts electricity due to two types of charged species: 1. Ammoniated electrons [e⁻(NH₃)ₓ] — electrons surrounded by ammonia molecules 2. Ammoniated metal cations [M⁺(NH₃)ₙ]

The ammoniated electrons are responsible for the characteristic deep blue colour (dilute solutions) and bronze colour (concentrated solutions). The conductivity is due to the movement of both the ammoniated cations and electrons.

Q19. Write the reactions involved in the preparation of NaCl from sea water.
AnswerNaCl is obtained from sea water by: 1. Evaporation: Sea water is evaporated in shallow pits using solar energy 2. Crystallization: As water evaporates, NaCl crystallizes out first (due to its lower solubility at high concentrations compared to other salts) 3. Purification: The crude salt is dissolved and recrystallized

NaCl obtained from sea water contains small amounts of MgCl₂, CaSO₄, and other impurities. For pure NaCl, it is dissolved in water, filtered, and recrystallized. HCl gas is passed through the saturated solution to precipitate pure NaCl (common ion effect).

Q20. Why are alkali metals kept in kerosene oil?
AnswerAlkali metals are extremely reactive with air and moisture. When exposed to air:
  • They react with oxygen to form oxides/peroxides/superoxides
  • They react with moisture to form hydroxides and release H₂ (which can ignite)
  • Na and K can catch fire spontaneously in moist air

Kerosene provides an oxygen-free and moisture-free environment, preventing these reactions. Kerosene is chosen because alkali metals do not react with it (they are denser than kerosene and sink below its surface).

Q21. What is the effect of heat on: (a) Li₂CO₃ (b) Na₂CO₃ (c) MgCO₃ (d) CaCO₃

Answer

(a) Li₂CO₃ → Li₂O + CO₂↑ (decomposes on heating — anomalous, other Group 1 carbonates are stable)

(b) Na₂CO₃ — does not decompose on heating (stable up to its melting point)

(c) MgCO₃ → MgO + CO₂↑ (decomposes on heating)

(d) CaCO₃ → CaO + CO₂↑ (decomposes on heating above 900 °C)

Note: All Group 2 carbonates decompose on heating. Group 1 carbonates are stable except Li₂CO₃.

Q22. Why is BeCl₂ soluble in organic solvents?
AnswerBeCl₂ is covalent (not ionic) due to the small size and high polarizing power of Be²⁺. The Be²⁺ ion polarizes the large Cl⁻ electron cloud, forming covalent bonds. In the solid state, BeCl₂ exists as a polymeric chain. In the vapour phase, it exists as a linear molecule (Cl–Be–Cl). Because of its covalent nature, BeCl₂ is soluble in organic solvents (like ether, benzene) and insoluble in non-polar solvents — typical of covalent compounds.

Q23. What happens when: (a) CaCO₃ is heated (b) CaO reacts with water (c) Ca(OH)₂ reacts with CO₂

Answer

(a) CaCO₃ →(heat) CaO + CO₂↑ (thermal decomposition — used in cement manufacture)

(b) CaO + H₂O → Ca(OH)₂ (slaking of lime, highly exothermic reaction)

(c) Ca(OH)₂ + CO₂ → CaCO₃↓ + H₂O (formation of insoluble calcium carbonate — this is why limewater turns milky when CO₂ is passed through it)

With excess CO₂: CaCO₃ + CO₂ + H₂O → Ca(HCO₃)₂ (soluble — milky solution clears)

Q24. Describe the importance of Ca in the human body.
AnswerCalcium is essential for: 1. Bones and teeth — 99% of body Ca is in bones as hydroxyapatite 2. Blood clotting — Ca²⁺ is Factor IV in the clotting cascade 3. Muscle contraction — Ca²⁺ triggers the sliding filament mechanism 4. Nerve impulse transmission — Ca²⁺ influx triggers neurotransmitter release 5. Enzyme activation — activates lipase, amylase, and other enzymes 6. Heart function — regulates heartbeat 7. Cell signalling — second messenger in many pathways

Deficiency causes: rickets (children), osteomalacia (adults), tetany, muscle cramps.

Q25. Compare the properties of Group 1 and Group 2 elements with respect to: (a) Electronic configuration (b) Nature of oxides (c) Flame colour

Answer

(a) Electronic configuration: Group 1 — ns¹; Group 2 — ns². Group 2 elements have one more proton and one more electron than the corresponding Group 1 element.

(b) Nature of oxides: Group 1 — all form basic oxides (Li₂O is the least basic); Group 2 — BeO is amphoteric, others form basic oxides (basicity increases down the group).

(c) Flame colour: Group 1 — Li (crimson red), Na (yellow), K (violet), Rb (red violet), Cs (blue); Group 2 — Be (no colour), Mg (no colour), Ca (brick red), Sr (crimson red), Ba (apple green).


Internal Links

  • [Chapter 10 Guide — The s-Block Elements](/school/cbse/class/11/chemistry/cbse-s-block-elements)
  • [All Class 11 Chemistry Solutions](/school/cbse/class/11/chemistry/solutions)
  • [Class 11 Chemistry Subject Guide](/school/cbse/class/11/chemistry)

Frequently Asked Questions

Alkali metals (Li, Na, K, Rb, Cs) are extremely reactive — they react vigorously with air (oxygen) and moisture. When exposed to air, they form oxides, hydroxides, and can catch fire. Kerosene provides an inert, oxygen-free, and moisture-free environment that prevents reaction. Among alkali metals, reactivity increases down the group, so heavier metals need even more careful storage.