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NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry | KalviGavani

NCERT Class 6 Maths Chapter 14 Practical Geometry exercise solutions — constructing circles line segments perpendiculars angles with compass ruler, MCQ and step-by-step answers.

Updated 16 June 202630 min read

NCERT Solutions for Class 6 Maths Chapter 14 — Practical Geometry

Key Concepts

ConceptDescription
Construction ToolsRuler (straight edge for drawing lines and measuring lengths), Compass (for drawing circles and arcs), Protractor (for measuring and drawing angles), Divider (for comparing and transferring lengths).
Constructing a Line SegmentUse a ruler to draw a line segment of given length. Mark two points at the required distance and join them. Also possible by marking a starting point, then using the ruler to mark the endpoint at the specified distance.
Constructing a Copy of a Line SegmentUse a compass to copy a line segment without measuring. Place the compass tip on one endpoint and the pencil on the other, then transfer this length to a new line.
Constructing a CircleFix the compass point at the centre, set the compass opening to the radius, and rotate the pencil end a full 360 degrees to complete the circle.
Perpendicular BisectorA line that cuts a line segment into two equal parts at 90 degrees. Constructed by drawing equal arcs from both endpoints and joining the intersection points of the arcs.
Constructing PerpendicularsA perpendicular to a line through a point on it or outside it can be constructed using a compass. From the point, draw arcs cutting the line at two places, then construct the perpendicular bisector of those two points.
Constructing Angles (60 degrees, 30 degrees, 90 degrees, 120 degrees, 150 degrees)60 degrees: Draw an arc from the vertex, then another arc of same radius from the intersection. 30 degrees: Bisect a 60-degree angle. 90 degrees: Construct perpendicular. 120 degrees: Two successive 60-degree arcs. 150 degrees: Bisect the angle between 120 and 180 degrees.
Angle BisectorA line that divides an angle into two equal parts. Constructed by drawing an arc from the vertex cutting both arms, then from each intersection drawing arcs of equal radius, and joining the vertex to the point where these arcs intersect.

Exercise 14.1 — Constructing Line Segments

Question 1

Q: Draw a line segment of length 7.3 cm using a ruler.

SolutionStep 1: Place the ruler on the paper with the zero mark at the starting point. Step 2: Mark a point at the starting position. Label it A. Step 3: Look along the ruler to the 7.3 cm mark. Step 4: Mark a point at 7.3 cm. Label it B. Step 5: Join points A and B with a straight line using the ruler.

The line segment AB = 7.3 cm.

Verification: Place the ruler along AB and check that the distance from A to B is exactly 7.3 cm.


Question 2

Q: Construct a line segment of length 5.6 cm using a ruler and compass.

SolutionStep 1: Draw a line l (a long line using a ruler). Mark a point A on it. Step 2: Open the compass so that the distance between the metal tip and the pencil tip is 5.6 cm. To do this, place the metal tip at the zero mark of the ruler and the pencil tip at the 5.6 cm mark. Step 3: Place the compass tip on point A. Step 4: Without changing the compass opening, draw an arc that cuts line l. Step 5: Mark the point where the arc cuts line l as point B.

The line segment AB = 5.6 cm.

Advantage of using a compass: The compass ensures accuracy because the length is set once and transferred without measurement error. A ruler alone may have parallax error.


Question 3

Q: Construct AB of length 7.8 cm. From this, cut off AC of length 3.4 cm. Measure BC.

SolutionStep 1: Draw a line segment AB = 7.8 cm using the compass method described above. Step 2: Now, set the compass to 3.4 cm (place metal tip at 0 and pencil tip at 3.4 cm on the ruler). Step 3: Place the compass tip on point A and draw an arc cutting AB. Step 4: The point where the arc cuts AB is point C. Step 5: Now, BC = AB - AC = 7.8 cm - 3.4 cm = 4.4 cm.

Verification: Measure BC with the ruler. It should read 4.4 cm.

AnswerBC = 4.4 cm

Question 4

Q: Given AB of length 3.9 cm, construct PQ such that PQ = AB.

SolutionThis requires copying a line segment without measuring its length directly.

Step 1: Observe the given line segment AB = 3.9 cm. Step 2: Draw a line l and mark a point P on it. Step 3: Place the compass tip on point A and the pencil tip on point B. The compass now captures the length AB. Step 4: Without changing the compass opening, place the compass tip on point P. Step 5: Draw an arc cutting line l. Mark the intersection as point Q.

Now, PQ = AB = 3.9 cm.

Key principle: A compass transfers an exact length without needing to know or read the numerical measurement.


Question 5

Q: Given two line segments AB and CD, verify that AB = CD or AB > CD or AB < CD using a compass.

SolutionWe compare the lengths without measuring them numerically.

Step 1: Place the compass tip on A and the pencil tip on B. The compass now holds the length AB. Step 2: Without changing the compass opening, place the compass tip on C. Step 3: Observe the position of the pencil tip relative to point D:

  • If the pencil tip falls exactly on D, then AB = CD.
  • If the pencil tip falls beyond D (past D on the CD side), then AB > CD.
  • If the pencil tip falls short of D, then AB < CD.
ResultThe compass comparison tells us which segment is longer without measuring either segment in centimetres.

Exercise 14.2 — Constructing a Copy of a Line Segment

Question 1

Q: Draw any line segment AB. Mark any point C on it. Construct a copy of AC using a compass.

SolutionStep 1: Draw a line segment AB of any length (say 6 cm). Step 2: Mark a point C on AB (say at 2.5 cm from A). Step 3: Draw a new line l and mark a point P on it. Step 4: Open the compass so the tip is on A and the pencil is on C. This captures length AC. Step 5: Without changing the compass, place the tip on P and draw an arc cutting line l. Step 6: Mark this intersection as Q.

PQ = AC. We have constructed a copy of AC.


Question 2

Q: Given a line segment AB, construct a line segment CD such that CD = 2 times AB.

SolutionWe need to construct a line segment that is double the length of AB.

Step 1: Draw a line l and mark a point C on it. Step 2: Place the compass tip on A and pencil on B to capture the length AB. Step 3: Without changing the compass, place the tip on C and draw an arc cutting line l. Call this point E. So CE = AB. Step 4: Now, still using the same compass opening (length AB), place the tip on E and draw another arc cutting line l. Call this point D.

Now, CD = CE + ED = AB + AB = 2AB.

Verification: Measure CD with a ruler. It should be twice the length of AB.


Question 3

Q: Given a line segment AB = 5.6 cm, construct a line segment of length 2.8 cm (half of AB).

SolutionTo get half the length, we construct the perpendicular bisector and take half the segment.

Step 1: Draw line segment AB = 5.6 cm. Step 2: Construct the perpendicular bisector of AB:

Step 3: The perpendicular bisector cuts AB at its midpoint M. Step 4: AM = MB = 5.6 / 2 = 2.8 cm. Step 5: To construct a separate copy of AM = 2.8 cm, use the compass method: place tip on A, pencil on M, then transfer this length to a new line.

  • With compass radius greater than half of AB, draw arcs from A above and below AB.
  • With the same radius, draw arcs from B above and below AB.
  • The arcs from A and B intersect at two points. Join these points.
AnswerThe constructed segment has length 2.8 cm.

Question 4

Q: Construct a line segment of length 3.4 cm and then construct a copy of it using a compass. Verify that both are equal.

SolutionStep 1: Draw a line segment AB = 3.4 cm using a ruler and compass.

Step 2: To construct a copy:

Step 3: Verify CD = AB:

  • Draw a line l, mark point A.
  • Set compass to 3.4 cm on the ruler.
  • From A, draw an arc cutting line l at B.
  • Draw another line m and mark point C.
  • Place compass tip on A and pencil on B (compass captures AB = 3.4 cm).
  • Without changing compass, place tip on C and draw an arc cutting line m at D.
  • Place compass on C and pencil on D (captures CD).
  • Without changing, place compass tip on A.
  • If the pencil tip falls exactly on B, then CD = AB.

Verification: The pencil tip falls exactly on B, confirming CD = AB = 3.4 cm.


Exercise 14.3 — Constructing Circles

Question 1

Q: Draw a circle of radius 3.2 cm.

SolutionStep 1: Open the compass so the distance between the metal tip and pencil tip is 3.2 cm. Use the ruler to set this distance accurately. Step 2: Mark a point O on the paper. This will be the centre of the circle. Step 3: Place the compass tip (metal point) firmly on point O. Step 4: Keeping the compass tip fixed on O, slowly rotate the compass 360 degrees so that the pencil tip traces a complete circle. Step 5: Ensure the compass does not slip or change its opening during the rotation.

The resulting circle has centre O and radius 3.2 cm.

Key points:

  • The centre is the fixed point where the compass tip is placed.
  • The radius is the distance from the centre to any point on the circle.
  • The diameter = 2 x radius = 2 x 3.2 = 6.4 cm.

Question 2

Q: With the same centre O, draw two circles of radii 3 cm and 5 cm.

SolutionStep 1: Mark point O as the centre. Step 2: Set the compass to 3 cm using the ruler. Place the compass tip on O and draw a circle. Label it Circle 1. Step 3: Without moving the compass tip from O, change the compass opening to 5 cm using the ruler. Step 4: With the compass tip still on O, draw a second circle. Label it Circle 2.

The two circles are concentric circles — they share the same centre O but have different radii.

Observations:

  • Circle 1 (inner): radius = 3 cm, diameter = 6 cm.
  • Circle 2 (outer): radius = 5 cm, diameter = 10 cm.
  • The region between the two circles is called a ring or annulus.

Question 3

Q: Draw a circle of radius 4 cm. Draw its diameter. Also draw a chord that is not a diameter.

SolutionStep 1: Draw a circle of radius 4 cm with centre O. Step 2: To draw a diameter:

Step 3: To draw a chord that is not a diameter:

  • Draw a line through centre O that cuts the circle at two points A and B.
  • AB is a diameter. AB = 2 x 4 = 8 cm.
  • Mark two points P and Q on the circle such that the line PQ does NOT pass through the centre O.
  • PQ is a chord but not a diameter.

Difference between diameter and chord:

  • A chord is any line segment whose both endpoints lie on the circle.
  • A diameter is a special chord that passes through the centre.
  • The diameter is the longest chord of a circle.

Question 4

Q: Draw a circle of radius 2.5 cm and mark: (a) its centre (b) a radius (c) a diameter (d) a chord that is not a diameter

SolutionStep 1: Draw a circle with centre O and radius 2.5 cm. Step 2: Mark the centre point O clearly with a dot. Step 3: Mark a point A on the circle. Join OA. OA = 2.5 cm is a radius. Step 4: Extend OA to meet the circle again at point B on the opposite side. AB = 5 cm is a diameter. Step 5: Mark two points C and D on the circle such that CD does not pass through O. CD is a chord that is not a diameter.

Summary:

ElementNameLength
OCentre—
OARadius2.5 cm
ABDiameter5.0 cm
CDChord (not diameter)Less than 5 cm

Exercise 14.4 — Constructing Perpendiculars and Perpendicular Bisectors

Question 1

Q: Draw a line segment AB of length 6.4 cm and construct its perpendicular bisector.

SolutionStep 1: Draw line segment AB = 6.4 cm. Step 2: Open the compass to a radius greater than half of AB (more than 3.2 cm). Let us take approximately 4 cm. Step 3: With A as centre, draw arcs above and below AB. Step 4: With B as centre and the same radius, draw arcs above and below AB. Step 5: The arcs from A and B intersect at two points — one above AB (say P) and one below AB (say Q). Step 6: Join P and Q with a straight line using a ruler. Step 7: Line PQ is the perpendicular bisector of AB. Step 8: PQ cuts AB at its midpoint M. AM = MB = 3.2 cm, and angle PMA = 90 degrees.

Verification:

  • Measure AM and MB. Both should be 3.2 cm (half of 6.4 cm).
  • Measure angle PMA with a protractor. It should be 90 degrees.

Question 2

Q: Draw a line l and a point P on it. Construct a perpendicular to l through P using a compass.

SolutionStep 1: Draw a line l and mark a point P on it. Step 2: With P as centre, draw an arc of any convenient radius that cuts line l at two points. Call them A and B. Step 3: With A as centre and a radius greater than AP, draw an arc above (or below) line l. Step 4: With B as centre and the same radius, draw another arc that intersects the previous arc. Call the intersection point Q. Step 5: Join P and Q with a straight line.

Line PQ is perpendicular to line l at point P.

Verification: Measure angle APQ (or BPQ) with a protractor. It should be 90 degrees.

Key insight: This method works because we are essentially constructing the perpendicular bisector of AB, where A and B are equidistant from P on line l. Since P is the midpoint of AB, the perpendicular bisector passes through P and is perpendicular to line l.


Question 3

Q: Draw a line l and a point P not on it. Construct a perpendicular from P to l using a compass.

SolutionStep 1: Draw a line l and mark a point P above (or below) it. Step 2: With P as centre, draw an arc with a radius large enough to cut line l at two points. Call them A and B. Step 3: With A as centre and a radius greater than half of AB, draw an arc below P. Step 4: With B as centre and the same radius, draw another arc that intersects the previous arc. Call the intersection point Q. Step 5: Join P and Q with a straight line. Step 6: Line PQ meets line l at point M. PQ is perpendicular to l at point M.

Verification: Measure angle PMA (or PMB). It should be 90 degrees.

Note: PQ is the shortest distance from P to line l. The foot of the perpendicular M is the closest point on l to P.


Question 4

Q: Draw a line segment AB = 5.8 cm. Construct the perpendicular bisector of AB. Verify that it bisects AB.

SolutionStep 1: Draw line segment AB = 5.8 cm. Step 2: Set the compass to a radius greater than half of AB (more than 2.9 cm), say 3.5 cm. Step 3: With A as centre, draw arcs above and below AB. Step 4: With B as centre and the same radius, draw arcs above and below AB. Step 5: The arcs intersect at two points P (above) and Q (below). Step 6: Join P and Q. Line PQ is the perpendicular bisector of AB. Step 7: PQ meets AB at point M.

Verification:

  • Measure AM: It should be 2.9 cm.
  • Measure MB: It should be 2.9 cm.
  • AM + MB = 2.9 + 2.9 = 5.8 cm = AB. (Verified)
  • Measure angle AMP with a protractor. It should be 90 degrees. (Verified)
AnswerThe perpendicular bisector PQ divides AB into two equal parts, each 2.9 cm, and is perpendicular to AB.

Question 5

Q: Draw a line l and a point P on it. Construct a perpendicular to l at P. Also construct a line parallel to l through a point Q above l.

SolutionPart A: Perpendicular through P Step 1: Draw line l and mark point P on it. Step 2: With P as centre, draw an arc cutting l at A and B. Step 3: With A and B as centres and radius greater than AP, draw arcs intersecting at R. Step 4: Join P and R. PR is perpendicular to l at P.

Part B: Parallel line through Q Step 1: Mark point Q above line l (not on l). Step 2: From Q, draw a perpendicular to line l using the method above. Let this perpendicular meet l at M. Step 3: Now, from Q, construct a perpendicular to QM (the perpendicular we just drew). Step 4: This new line through Q is perpendicular to QM and therefore parallel to l.

Principle: If two lines are both perpendicular to the same line, they are parallel to each other.


Exercise 14.5 — Constructing Angles

Question 1

Q: Construct an angle of 60 degrees using a compass.

SolutionStep 1: Draw a ray OA of any convenient length. Step 2: With O as centre, draw an arc of any radius that cuts OA at point B. Step 3: With B as centre and the same radius (OB), draw another arc that cuts the first arc at point C. Step 4: Join O to C with a straight line. Draw ray OC.

Angle AOC = 60 degrees.

Why this works: In triangle OBC, OB = OC (arcs of same radius from O) and BC = OB (arc drawn with same radius from B). So OBC is an equilateral triangle, and all angles of an equilateral triangle are 60 degrees.

Verification: Measure angle AOC with a protractor. It should be 60 degrees.


Question 2

Q: Construct an angle of 30 degrees using a compass.

SolutionWe first construct a 60-degree angle and then bisect it.

Step 1: Construct angle AOC = 60 degrees using the method from Question 1. Step 2: With B as centre and a convenient radius, draw an arc cutting OB and OC at points D and E respectively. Step 3: With D as centre and a radius greater than half of DE, draw an arc. Step 4: With E as centre and the same radius, draw another arc intersecting the previous arc at point F. Step 5: Join O to F with a ray OF.

Angle AOF = 30 degrees (half of 60 degrees).

Verification: Measure angle AOF with a protractor. It should be 30 degrees.


Question 3

Q: Construct an angle of 90 degrees using a compass.

SolutionMethod 1: Perpendicular bisector method Step 1: Draw a line segment AB of any length. Step 2: Construct the perpendicular bisector of AB using the compass method (arcs from A and B). Step 3: The perpendicular bisector makes a 90-degree angle with AB at the midpoint.

Method 2: Angle bisection method Step 1: Draw a line l and mark point O on it. Step 2: Construct angle AOC = 60 degrees at O on line l. Step 3: Construct angle COD = 60 degrees adjacent to angle AOC. Now angle AOD = 120 degrees. Step 4: Bisect angle AOD to get angle AOE = 60 degrees. Step 5: Bisect angle AOE to get angle AOF = 30 degrees.

Wait — let us use a simpler method:

Method 3: Direct construction Step 1: Draw a line l and mark point O on it. Step 2: With O as centre, draw a semicircle (arc) cutting line l at A and B (on opposite sides of O). Step 3: With A as centre and radius AO, draw an arc cutting the semicircle at C. Step 4: With B as centre and radius BO, draw an arc cutting the semicircle at D (other than A). Step 5: Join O to C. Angle AOC = 60 degrees. Step 6: The arc between C and D subtends angle COD = 60 degrees at O. Step 7: Bisect angle COD to get 30 degrees. Then angle AOB = angle AOC + angle COD = 120 degrees, and the supplementary angle is 60 degrees.

Simplest Method: Step 1: Construct angle of 60 degrees at point O on a line. Step 2: Construct another 60-degree angle adjacent to it (total = 120 degrees). Step 3: Bisect the 120-degree angle. The result is 60 degrees. Then the angle on the other side = 180 - 60 = 120. Wait, let me restate:

Correct approach: Step 1: Draw a ray OA. Step 2: Construct angle AOB = 60 degrees. Step 3: On the other side of OA, construct angle AOC = 60 degrees. Step 4: Now angle BOC = 60 + 60 = 120 degrees. Bisect angle BOC. Step 5: The bisector gives an angle of 60 degrees from OA. The remaining angle = 180 - 60 = 120. Hmm.

Best method — perpendicular: Step 1: Draw a line l and mark point O on it. Step 2: With O as centre, draw arcs cutting l at A and B on either side of O, with OA = OB. Step 3: With A as centre and radius greater than OA, draw an arc above. Step 4: With B as centre and the same radius, draw an arc intersecting the previous arc at C. Step 5: Join OC. Angle AOC = 90 degrees.

Verification: Measure angle AOC with a protractor. It should be 90 degrees.


Question 4

Q: Construct an angle of 120 degrees using a compass.

SolutionStep 1: Draw a ray OA. Step 2: With O as centre, draw an arc of any radius cutting OA at P. Step 3: With P as centre and the same radius (OP), draw an arc cutting the first arc at Q. Step 4: With Q as centre and the same radius, draw another arc cutting the first arc at R. Step 5: Join O to R with a ray OR.

Angle AOR = 120 degrees.

Why this works: Each arc of radius OP subtends 60 degrees at O. Two successive arcs give 60 + 60 = 120 degrees.

Verification: Measure angle AOR with a protractor. It should be 120 degrees.


Question 5

Q: Construct an angle of 150 degrees using a compass.

SolutionAn angle of 150 degrees can be constructed by combining known angles.

Method: We know that 150 degrees = 180 degrees - 30 degrees. So, 150 degrees = 120 degrees + 30 degrees.

Step 1: Draw a ray OA. Step 2: Construct angle AOB = 120 degrees (as described above). Step 3: Construct angle BOC = 30 degrees (by bisecting a 60-degree angle) adjacent to angle AOB, on the opposite side. Step 4: Angle AOC = 120 + 30 = 150 degrees.

Alternative Method: Step 1: Draw a line l and mark point O on it. Step 2: Construct a 60-degree angle on one side. Step 3: The supplementary angle on the other side = 180 - 60 = 120 degrees. Step 4: Bisect the 60-degree angle to get 30 degrees. Step 5: Add 120 + 30 = 150 degrees.

Verification: Measure the constructed angle with a protractor. It should be 150 degrees.


Question 6

Q: Construct an angle of 45 degrees using a compass.

SolutionWe construct 90 degrees and then bisect it.

Step 1: Draw a line l and mark point O on it. Step 2: Construct a perpendicular (90-degree angle) at O using the compass method from Exercise 14.4. Step 3: Now bisect the 90-degree angle:

Step 4: Ray OR bisects the 90-degree angle, giving angle AOR = 45 degrees.

  • With O as centre, draw an arc cutting both arms of the 90-degree angle at points P and Q.
  • With P as centre and radius greater than half PQ, draw an arc.
  • With Q as centre and the same radius, draw an arc intersecting the previous arc at R.
  • Join O to R.

Verification: Measure angle AOR with a protractor. It should be 45 degrees.


Exercise 14.6 — Angle Bisector and More Constructions

Question 1

Q: Construct angle AOB = 75 degrees using a compass and then bisect it.

SolutionConstructing 75 degrees: 75 degrees = 60 degrees + 15 degrees, or 75 degrees = 90 degrees - 15 degrees.

Step 1: Draw a ray OA. Step 2: Construct angle AOP = 60 degrees. Step 3: Construct angle POB = 90 degrees on the same side (angle AOB = 90 degrees). Step 4: Bisect angle POB (30 degrees) to get angle POQ = 15 degrees. Step 5: Angle AOQ = 60 + 15 = 75 degrees.

Bisecting 75 degrees: Step 6: With O as centre, draw an arc cutting OA and OQ at points C and D respectively. Step 7: With C as centre and radius greater than half of CD, draw an arc. Step 8: With D as centre and the same radius, draw an arc intersecting the previous arc at E. Step 9: Join O to E.

Angle AOE = 75/2 = 37.5 degrees.


Question 2

Q: Draw an angle of 140 degrees and bisect it using a compass.

SolutionDrawing 140 degrees: Step 1: Draw a ray OA. Step 2: Construct angle AOB = 120 degrees using the compass. Step 3: On the same side, construct angle BOC = 60 degrees adjacent to AOB. Now angle AOC = 180 degrees. Step 4: We need 140 degrees. Alternatively, use a protractor to mark the 140-degree point.

Since 140 degrees cannot be easily constructed with compass alone (it is not a simple combination of 60, 30, 45, 90), we may use a protractor for the initial angle.

Step 1 (using protractor): Draw a ray OA. Place the protractor at O, mark the 140-degree point, and draw ray OB. Angle AOB = 140 degrees.

Bisecting 140 degrees: Step 2: With O as centre, draw an arc cutting OA at P and OB at Q. Step 3: With P as centre and radius greater than half PQ, draw an arc. Step 4: With Q as centre and the same radius, draw an arc intersecting the previous arc at R. Step 5: Join O to R.

Angle AOR = 140/2 = 70 degrees.

Verification: Measure angle AOR with a protractor. It should be 70 degrees.


Question 3

Q: Copy an angle of 40 degrees using a compass.

SolutionGiven: An angle of 40 degrees (drawn using a protractor on the left side of the page).

Step 1: Let the given angle be POQ = 40 degrees. Step 2: Draw a ray AB on the right side of the page. Step 3: With O as centre, draw an arc cutting OP at C and OQ at D. Step 4: With A as centre and the same radius (OC), draw an arc cutting AB at E. Step 5: With E as centre and radius equal to CD (use compass to measure CD), draw an arc cutting the previous arc at F. Step 6: Join A to F with a ray AF.

Angle BAF = angle POQ = 40 degrees.

Key principle: The angle is copied by transferring the arc distance CD to the new position. This ensures the new angle subtends the same arc as the original.


Question 4

Q: Construct a rectangle of length 5 cm and breadth 3 cm using a ruler and compass.

SolutionStep 1: Draw line segment AB = 5 cm (length). Step 2: At point A, construct a perpendicular using compass (90-degree angle). Step 3: On this perpendicular, mark point D such that AD = 3 cm (breadth). Step 4: At point B, construct a perpendicular using compass (90-degree angle). Step 5: On this perpendicular, mark point C such that BC = 3 cm (breadth). Step 6: Join C and D.

ABCD is the required rectangle.

Verification:

  • AB = CD = 5 cm (opposite sides equal)
  • AD = BC = 3 cm (opposite sides equal)
  • All angles = 90 degrees
  • Diagonals AC and BD are equal

Question 5

Q: Construct a square of side 4.5 cm using a ruler and compass.

SolutionStep 1: Draw line segment AB = 4.5 cm. Step 2: At point A, construct a perpendicular (90-degree angle) using compass. Step 3: On this perpendicular, mark point D such that AD = 4.5 cm (same as side). Step 4: At point B, construct a perpendicular (90-degree angle) using compass. Step 5: On this perpendicular, mark point C such that BC = 4.5 cm. Step 6: Join C and D.

ABCD is the required square.

Verification:

  • AB = BC = CD = DA = 4.5 cm (all sides equal)
  • All angles = 90 degrees
  • Diagonals AC = BD and they bisect each other at right angles

Common Mistakes

1. Changing compass opening during construction. When copying a length or an angle, the compass opening must remain fixed. Even a slight change in the compass gap leads to incorrect constructions. Always double-check the compass setting before drawing the final arc.

2. Using the wrong radius for perpendicular bisector. When constructing the perpendicular bisector, the compass radius must be greater than half the line segment. If the radius is too small, the arcs from the two endpoints will not intersect, and the perpendicular bisector cannot be drawn.

3. Confusing the steps for constructing perpendiculars through a point on the line vs. outside the line. When the point is ON the line, we draw arcs from the point to cut the line at two places, then bisect. When the point is OUTSIDE the line, we draw arcs from the point to cut the line at two places, then bisect the segment between those two points. The initial step is similar but the reasoning differs.

4. Constructing angles with wrong arc intersections. When bisecting an angle, the two arcs drawn from the intersection points on the arms must intersect at a single point. If the compass radius is too small, the arcs will not intersect. Always use a radius greater than half the distance between the two points on the arms.

5. Forgetting to verify constructions. Always verify your construction by measuring the final result. For perpendicular bisectors, check that the two segments are equal. For angle bisections, measure the resulting angles. For copied line segments, compare lengths using a compass.

6. Drawing a 90-degree angle incorrectly. A common mistake is to try to construct 90 degrees by bisecting 180 degrees (a straight line), which does not work by simply bisecting with a protractor. The correct compass method involves constructing arcs from equidistant points on the line and joining their intersections.


Exam Checklist

  • [ ] I can identify and properly use the four basic construction tools: ruler, compass, protractor, and divider.
  • [ ] I can construct a line segment of a given length using a ruler and compass.
  • [ ] I can copy a line segment using a compass without measuring the length numerically.
  • [ ] I can construct a circle of given radius and identify its centre, radius, diameter, and chords.
  • [ ] I can construct the perpendicular bisector of a line segment and verify that it divides the segment into two equal parts at 90 degrees.
  • [ ] I can construct a perpendicular to a line through a point on the line and through a point outside the line.
  • [ ] I can construct angles of 60, 30, 90, 120, 150, and 45 degrees using a compass.
  • [ ] I can bisect a given angle using a compass and verify the result.
  • [ ] I can copy a given angle using a compass (transfer an angle to a new position without measuring it).
  • [ ] I can construct a rectangle and a square of given dimensions using a ruler and compass.

Quick Reference Table: Angle Constructions

AngleConstruction Method
60 degreesDraw arc from vertex, then another arc of same radius from intersection point
30 degreesBisect a 60-degree angle
90 degreesConstruct perpendicular at a point on a line
45 degreesBisect a 90-degree angle
120 degreesTwo successive 60-degree arcs
150 degrees120 + 30, or bisect 180 minus 60
15 degreesBisect a 30-degree angle
75 degrees60 + 15, or 90 - 15
105 degrees60 + 45, or 90 + 15
135 degrees90 + 45, or bisect (180 - 90 = 90, then 90 + 45)

Summary of Construction Steps

ConstructionKey Steps
Line segment of given lengthSet compass to length, draw arc on line
Copy of line segmentTransfer compass length to new line
Circle of given radiusFix compass at centre, set radius, rotate
Perpendicular bisectorEqual arcs from both endpoints, join intersections
Perpendicular at point on lineArc from point cuts line at two places, bisect segment
Perpendicular from point outside lineArc from point cuts line, bisect the segment
Angle of 60 degreesArc from vertex, second arc from intersection
Angle bisectorArc from vertex cuts arms, then arcs from those points
Copy an angleTransfer arc distances from original to new position

Frequently Asked Questions

A ruler (or straight edge), a compass, a protractor, and a divider are the main tools.
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