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Class 12

Tamil Nadu Class 12 Maths: Applications of Integration

Samacheer Kalvi Class 12 Maths Applications of Integration full guide - definite integral properties, area under curves and between curves, volume of revolution, with worked examples.

Updated 6 June 20262 min read

Overview

This chapter uses the definite integral to compute areas under and between curves and volumes of solids of revolution.

1. Properties of Definite Integrals

∫ₐᵇ f(x)dx = −∫ᵇₐ f(x)dx ∫ₐᵇ f(x)dx = ∫ₐᶜ f(x)dx + ∫꜀ᵇ f(x)dx ∫ₐᵇ f(x)dx = ∫ₐᵇ f(a+b−x)dx ∫₋ₐᵃ f(x)dx = 2∫₀ᵃ f(x)dx (even) ; = 0 (odd)

2. Area

Area under curve: A = ∫ₐᵇ y dx Between two curves: A = ∫ₐᵇ (y_top − y_bottom) dx

3. Volume of Revolution

About x-axis: V = π ∫ₐᵇ y² dx About y-axis: V = π ∫꜀ᵈ x² dy

Worked Examples

Example 1 — Area under a curve

Area under y = x² from x = 0 to x = 3.

A = ∫₀³ x² dx = [x³/3]₀³ = 27/3 = 9 sq.units

Example 2 — Using an even-function property

Evaluate ∫₋₂² x² dx.

x² is even → = 2∫₀² x² dx = 2[x³/3]₀² = 2(8/3) = 16/3

Example 3 — Area between curves

Area between y = x and y = x² from x = 0 to 1.

A = ∫₀¹ (x − x²) dx = [x²/2 − x³/3]₀¹ = 1/2 − 1/3 = 1/6 sq.units

Example 4 — Volume of revolution

Volume when y = x is rotated about the x-axis from 0 to 1.

V = π∫₀¹ x² dx = π[x³/3]₀¹ = π/3 cubic units

Common Mistakes

  • Ignoring the modulus for areas below the x-axis.
  • Subtracting in the wrong order (top − bottom) for area between curves.
  • Forgetting the π in the volume formula.
  • Mismatched limits when changing from dx to dy.

Exam Tips & Revision Checklist

  • Use even/odd properties to shortcut symmetric integrals.
  • Sketch the region first for area-between-curves problems.
  • Practised: area under curve, even-function property, area between curves, volume of revolution.

Frequently Asked Questions

Area = ∫ₐᵇ y dx for a curve y = f(x) between x = a and x = b (take the modulus for parts below the x-axis).

Related Notes