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Class 10

CBSE Class 10 Maths Chapter 14 Notes — Probability

Complete CBSE Class 10 Maths Chapter 14 notes on Probability. Covers theoretical probability, sample space, events, complementary events, and solved problems with cards, dice, and coins.

Updated 23 May 20265 min read

Introduction to Probability

Probability is a measure of the likelihood of an event occurring.

Types of Probability

TypeDescription
Experimental (Empirical)Based on actual experiments; P(E) = number of times event occurred / total trials
TheoreticalBased on equally likely outcomes; P(E) = favourable outcomes / total outcomes

Class 10 focuses on theoretical probability.


Key Definitions

Trial: A single performance of an experiment (e.g., tossing a coin once).

Sample Space (S): The set of all possible outcomes of an experiment.

  • Coin: S = {H, T}; n(S) = 2
  • Die: S = {1, 2, 3, 4, 5, 6}; n(S) = 6
  • Two coins: S = {HH, HT, TH, TT}; n(S) = 4

Event (E): A subset of the sample space.

Favourable outcomes: Outcomes that belong to the event E.


Probability Formula

$$P(E) = \frac{\text{Number of outcomes favourable to } E}{\text{Total number of equally likely outcomes}}$$

Key properties:

  • 0 ≤ P(E) ≤ 1
  • P(impossible event) = 0 (e.g., getting 7 on a die)
  • P(certain/sure event) = 1 (e.g., getting a number ≤ 6 on a die)
  • P(E) + P(not E) = 1 → P(E̅) = 1 − P(E)

Standard Experiments

Tossing a Coin

S = {H, T}; n(S) = 2

EventFavourableProbability
Getting Head{H}1/2
Getting Tail{T}1/2

Tossing Two Coins

S = {HH, HT, TH, TT}; n(S) = 4

EventFavourableP
Two heads{HH}1/4
At least one head{HH, HT, TH}3/4
No head{TT}1/4
Exactly one head{HT, TH}1/2

Rolling a Die

S = {1, 2, 3, 4, 5, 6}; n(S) = 6

EventFavourableP
Getting 4{4}1/6
Prime number{2, 3, 5}1/2
Even number{2, 4, 6}1/2
Number > 4{5, 6}1/3
Multiple of 3{3, 6}1/3

Rolling Two Dice

n(S) = 36 (6 × 6 = 36 equally likely outcomes)

EventCountP
Sum = 7{(1,6),(2,5),(3,4),(4,3),(5,2),(6,1)} = 66/36 = 1/6
Sum = 2 (doublet 1,1)11/36
Doublets{(1,1),(2,2),(3,3),(4,4),(5,5),(6,6)} = 61/6
Sum ≥ 10{(4,6),(5,5),(5,6),(6,4),(6,5),(6,6)} = 61/6

Playing Cards Problems

A standard deck has 52 cards:

SuitColourCards
Hearts ♥RedA, 2, 3, 4, 5, 6, 7, 8, 9, 10, J, Q, K
Diamonds ♦RedA, 2, 3, 4, 5, 6, 7, 8, 9, 10, J, Q, K
Spades ♠BlackA, 2, 3, 4, 5, 6, 7, 8, 9, 10, J, Q, K
Clubs ♣BlackA, 2, 3, 4, 5, 6, 7, 8, 9, 10, J, Q, K

Key counts:

  • Red cards = 26; Black cards = 26
  • Face cards (J, Q, K) = 12; Aces = 4
  • Non-face cards = 40; Number cards (2–10) = 36
  • King of hearts = 1 specific card

Sample problems:

Q. One card drawn at random from 52 cards. Find probability it is:

(a) A king: P = 4/52 = 1/13

(b) A red card: P = 26/52 = 1/2

(c) A face card: P = 12/52 = 3/13

(d) The queen of spades: P = 1/52

(e) Not an ace: P = (52−4)/52 = 48/52 = 12/13

(f) A black face card: (J, Q, K of spades and clubs) = 6; P = 6/52 = 3/26


Balls in a Bag Problems

Q. A bag contains 5 red, 4 blue, and 3 green balls. One ball drawn at random. Find:

(a) P(red) = 5/12 (b) P(not green) = (5+4)/12 = 9/12 = 3/4 (c) P(blue or green) = (4+3)/12 = 7/12


Numbers and Digits Problems

Q. A number is chosen at random from 1 to 50. Find P(multiple of 3 or 5).

Multiples of 3 up to 50: 3,6,9,...,48 → 16 numbers Multiples of 5 up to 50: 5,10,...,50 → 10 numbers Multiples of both (15): 15,30,45 → 3 numbers

By inclusion-exclusion: 16 + 10 − 3 = 23

P = 23/50


Board Exam Tips

  • 4–5 marks from this chapter — shorter than others but reliable marks
  • Cards problem appears almost every year — memorise: 52 total, 26 red, 26 black, 4 suits, 13 each, 12 face cards, 4 aces
  • Always reduce fractions to lowest terms
  • "At least one" type: use complement → P(at least one) = 1 − P(none)
  • Two dice: n(S) = 36 always; list outcomes systematically to count favourable
  • Common mistake: forgetting to include both (H,T) and (T,H) when order matters in two-coin problems

📚 RD Sharma Mathematics Class 10 — Probability Chapter

📝 Oswaal CBSE Maths Question Bank — Probability Board Questions

Frequently Asked Questions

P(E) = Number of outcomes favourable to E / Total number of equally likely outcomes. Probability always lies between 0 and 1 (inclusive). P(impossible event) = 0; P(certain event) = 1.

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